如何在Java中按字母顺序组织对象数组
如何在Java中按字母顺序组织对象数组
提问于 2018-10-22 01:47:55
我正在尝试模拟一个唱片库。但我也可以按作者姓名的字母顺序组织图书馆的内容。如何按字母顺序组织对象数组的内容有什么帮助吗？
我已经创建了一个名为Album的类，我使用它来创建我的对象
public class Album {
private String author;
private String name;
private String year;
public Album(String a, String n, String y) { // constructor
author = a;
name = n;
year = y;
}
public String toString()
{
return author +","+ name + "," + year;
}
}类集合用于将对象存储到数组中
public class AlbumCollection {
public Album collection[]= new Album[10];
private int numAlbums = 0;
public void add (Album a){
if (numAlbums >= collection.length){
Album newcollection[]= new Album [collection.length * 2];
for (int n = 0; n < numAlbums; n ++){
newcollection[n] = collection[n];
}
newcollection = collection;
}
collection[numAlbums] = a;
numAlbums = numAlbums + 1;
}
public String toString()
{
String details = "";
for ( int p = 0; p < collection.length ; p ++)
{
details = details + collection[p] + "\n" ;
}
details += "\n";
return details;
}
}这是我用来创建相册对象的类
public class TestCollection {
public static void main(String[] args) {
AlbumCollection c = new AlbumCollection();
c.add( new Album("DaftPunk","Discovery","2001"));
c.add( new Album ("Pink Floid","The Dark Side Of The Moon","1973"));
c.add( new Album( "The Clash", "London Calling", "1979"));
System.out.print(c);
}
}回答 1
Stack Overflow用户
回答已采纳
发布于 2018-10-22 02:28:14
我不得不将compareTo方法更改为按作者排序。
public class Album {
private String author;
private String name;
private String year;
public Album(String a, String n, String y) { // constructor
author = a;
name = n;
year = y;
}
public String toString()
{
return author +","+ name + "," + year;
}
public int compareTo(Album a) {
// usually toString should not be used,
// instead one of the attributes or more in a comparator chain
return author.compareTo(a.author);
} }，我给数组的元素添加了排序方法：
public class Collection {
public Album collection[]= new Album[10];
private int numAlbums = 0;
public void Add (Album a){
if (numAlbums >= collection.length){
Album newcollection[]= new Album [collection.length * 2];
for (int n = 0; n < numAlbums; n ++){
newcollection[n] = collection[n];
}
newcollection = collection;
}
collection[numAlbums] = a;
numAlbums = numAlbums + 1;
}
public String toString()
{
String details = "";
for ( int p = 0; p < numAlbums ; p ++)
{
details = details + collection[p] + "\n" ;
}
details += "\n";
return details;
}
public void sort(){
for(int i=0;i<numAlbums;i++){
for(int j=i;j<numAlbums-1;j++){
if(collection[j].compareTo(collection[j+1])>0){
Album tmp =collection[j];
collection[j]=collection[j+1];
collection[j+1]=tmp;
}
}
}
}}
如果存储作者的数量，则不能使用数组的长度，因为将打印空值
public static void main(String[] args) {
Collection c = new Collection();
c.Add( new Album("DaftPunk","Discovery","2001"));
c.Add( new Album ("Pink Floid","The Dark Side Of The Moon","1973"));
c.Add( new Album( "The Clash", "London Calling", "1979"));
c.sort();
System.out.print(c);
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52918180
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