如何使用%、-和+作为可能的分隔符将字符列拆分为3列,并将分隔符保留在新列中?
示例数据:
data <- data.table(x=c("92.1%+100-200","90.4%-1000+200", "92.8%-200+100", "99.2%-500-200","90.1%+500-200"))
所需数据示例:
data.desired <- data.table(x1=c("92.1%", "90.4%", "92.8%","99.2%","90.1%")
, x2=c("+100","-1000","-200","-500","+500")
, x3=c("-200","+200","+100","-200","-200"))
很高兴在这个问题上得到一个好的答案和一些帮助!
发布于 2018-12-11 08:40:55
在data.table
中,等效项是tstrsplit
data[, c("x1","x2","x3") := tstrsplit(x, "(?<=.)(?=[+-])", perl=TRUE) ]
data
# x x1 x2 x3
#1: 92.1%+100-200 92.1% +100 -200
#2: 90.4%-1000+200 90.4% -1000 +200
#3: 92.8%-200+100 92.8% -200 +100
#4: 99.2%-500-200 99.2% -500 -200
#5: 90.1%+500-200 90.1% +500 -200
发布于 2018-12-11 10:23:30
下面是一个使用base R
的选项
cbind(data, read.csv(text = gsub("(?=[+-])", ",", data$x, perl = TRUE),
header = FALSE, stringsAsFactors = FALSE, col.names = c('x1', 'x2', 'x3')))
# x x1 x2 x3
#1: 92.1%+100-200 92.1% 100 -200
#2: 90.4%-1000+200 90.4% -1000 200
#3: 92.8%-200+100 92.8% -200 100
#4: 99.2%-500-200 99.2% -500 -200
#5: 90.1%+500-200 90.1% 500 -200
https://stackoverflow.com/questions/53715609
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