PHP检查字符串中是否至少包含两个特定的单词
PHP检查字符串中是否至少包含两个特定的单词
提问于 2018-12-12 07:10:46
我使用preg_match检查字符串中是否有特定的单词：
$string = 'This string contains a few words that are in an array!';
$arr = ['string', 'few', 'words'];
if(preg_match('['.implode('|', $arr).']', $string)){
//do something if there is at least one word from the array inside that string
}这很好用，但如果至少有一个单词，它将返回true，如果该字符串中至少有两个来自数组的单词，我需要它返回true。
这可以一步到位吗？如果不是，我应该从哪一条路获得结果呢？
谢谢！：d
回答 2
Stack Overflow用户
回答已采纳
发布于 2018-12-12 07:40:04
您可以使用preg_match_all来完成此操作
$string = 'This string contains a few words that are in an array!';
$arr = ['string', 'few', 'words'];
$count = preg_match_all('['.implode('|', $arr).']', $string); // Returns 3Stack Overflow用户
发布于 2018-12-12 07:53:33
如果你不关心精确匹配，那么选择的答案就可以了。如果你想精确匹配单词，那么你需要使用单词边界\b。
示例如下：
$arr = ['string', 'few', 'words'];
preg_match_all('#\b('.implode('|', $arr).')\b#', $string, $wordsFound);
$wordsFound = array_unique($wordsFound[0]);
if(count($wordsFound) >= 2){
echo "Matched";
}else{
echo "Not matched";
}
Input: $string = 'This string contains a few words that are in an array!';
Output: Matched (3 founds)
Input: $string = 'This string222 contains a few words that are in an array!';
Output: Matched (2 founds)
Input: $string = 'This string222 contains a few23 words that are in an array!';
Output: Not Matched (1 found)
Input: $string = 'This string contains a string words that are in an array!';
Output: Matched (2 founds)
Input: $string = 'This string contains a string string that are in an array!';
Output: Not Matched (1 found)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/53733739
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