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社区首页 >问答首页 >函数来排除星期六和星期日

函数来排除星期六和星期日
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Stack Overflow用户
提问于 2018-12-17 03:40:19
回答 2查看 81关注 0票数 0

我创建了一个"Daily Sales Query“,它捕获了前一个工作日输入的所有总销售额,该查询在周一至周五上午8点运行

问题是,如果今天是星期一,我如何才能捕获周五的记录。这样我就可以把周末排除在外。

因为如果是星期一,总销售额显示为0,这实际上是有意义的,因为星期天不是工作日。请协助。

请参阅我当前的代码:

SELECT 
    CONVERT(VARCHAR, DATEADD(dd, - 1, GETDATE()), 103) AS Date, 
    'Sales Orders' AS Type, 
    COUNT(o.SalesOrderID) AS Orders, 
    SUM(d.QtyOrdered) AS Chairs, 
    ISNULL(ROUND(SUM(d.ExtendedPrice), 2), 0) AS [Total Ex GST] 
FROM 
    dbo.SalesOrder o
LEFT OUTER JOIN 
    dbo.SalesOrderDetails d ON o.SalesOrderID = d.SalesOrderID 
WHERE 
    (o.EntryDate >= CONVERT(CHAR(8), DATEADD(dd, - 1, GETDATE()), 112)) 
    AND (o.EntryDate < CONVERT(CHAR(8), GETDATE(), 112)) 
    AND (o.CustomerID <> 187);
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2018-12-17 03:46:03

如果使用case语句来确定过去需要去多少天,例如

dateadd(dd, case when datepart(weekday,getdate()) = 1 then -3 else -1 end, getdate()) -- StartDate
dateadd(dd, case when datepart(weekday,getdate()) = 1 then -2 else 0 end, getdate()) -- EndDate

因此,您的代码将如下所示

SELECT 
    CONVERT(VARCHAR, dateadd(dd, case when datepart(weekday,getdate()) = 1 then -3 else -1 end, getdate()), 103) AS Date, 
    'Sales Orders' AS Type, 
    COUNT(o.SalesOrderID) AS Orders, 
    SUM(d.QtyOrdered) AS Chairs, 
    ISNULL(ROUND(SUM(d.ExtendedPrice), 2), 0) AS [Total Ex GST] 
FROM 
    dbo.SalesOrder o
LEFT OUTER JOIN 
    dbo.SalesOrderDetails d ON o.SalesOrderID = d.SalesOrderID 
WHERE 
    (o.EntryDate >= CONVERT(CHAR(8), dateadd(dd, case when datepart(weekday,getdate()) = 1 then -3 else -1 end, getdate()), 112)) 
    AND (o.EntryDate < CONVERT(CHAR(8), dateadd(dd, case when datepart(weekday,getdate()) = 1 then -2 else 0 end, getdate()), 112)) 
    AND (o.CustomerID <> 187);

PS:请确认您的服务器上的工作日1是星期一。

票数 0
EN

Stack Overflow用户

发布于 2018-12-17 07:25:08

您可以使用datediff(dd,0,getdate()) % 7 = 0来确定当前日期是否为星期一,而不考虑任何其他服务器设置(这是因为SQL server中的零日期是1900-01-01,而恰好是星期一)。

declare @start date;
declare @finish date;

set @start = dateadd(dd, case when datediff(dd,0,getdate()) % 7 = 0 then -3 else -1 end, getdate());
set @finish = dateadd(dd,1,@start);

select
    @start, datename(weekday,@start)
  , @finish, datename(weekday,@finish)
  , datename(weekday,getdate())
;

因此,在您的查询中,我将使用:

declare @start date;
declare @finish date;

set @start = dateadd(dd, case when datediff(dd,0,getdate()) % 7 = 0 then -3 else -1 end, getdate());
set @finish = dateadd(dd,1,@start);

SELECT 
    CONVERT(VARCHAR, @start, 103) AS Date, 
    'Sales Orders' AS Type, 
    COUNT(o.SalesOrderID) AS Orders, 
    SUM(d.QtyOrdered) AS Chairs, 
    ISNULL(ROUND(SUM(d.ExtendedPrice), 2), 0) AS [Total Ex GST] 
FROM 
    dbo.SalesOrder o
LEFT OUTER JOIN 
    dbo.SalesOrderDetails d ON o.SalesOrderID = d.SalesOrderID 
WHERE 
     o.EntryDate >= @start
    AND o.EntryDate < @finish
    AND o.CustomerID <> 187
;
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/53805812

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