blocks|key|2554096|text|因此，根据您的示例，您实际上是在输出2017年11月的信息，该信息从一个星期三开始。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2554097|要实现您想要的结果，您只需找出是星期几，然后在需要填充月份的情况下将额外的“空”项添加到$list数组中。|offset|length|style|CODE|2554098|要查找星期几，请使用：|2554099|...+//+Your+existing+code+under+Make+List
$year+=+date('Y',+strtotime('-1+year'));

$date+=+'01-'+.+$month+.+'-'+.+$year;
$dayofweek+=+date('w',+strtotime($date));|code-block|syntax|javascript|2554100|现在$dayofweek将包含星期的数字，其中0表示星期天，1表示星期一，依此类推。|2554101|接下来，只需将空项添加到列表数组中，以填充应该为空的天数：|2554102|if+($dayofweek+==+0)+$dayofweek+=+7;
for+(;+$dayofweek+>+1;+$dayofweek--)
++++$list[]+=+'';|2554103|请注意，在开始日期是星期天的情况下，我将其更改为7，以导致填充6个框。|2554104|最后，在输出列表项时，只需为每个填充的日期添加一个空的日期<li>：|2554105|...+//+Your+existing+code
foreach($list+as+$day){
++++if+($day+==+'')
++++++++echo+'<li>Empty+day</li>';
++++else+if($day+<+date('d')){
++++++++...+//+Your+existing+code+continues|2554106|entityMap^0|0|18|5|0|0|0|2|A|0|0|0|0|T|4|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@$D|14|E|15|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|16|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|17|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|18|8|@$D|19|E|1A|F|G]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1B|8|@]|9|@]|A|$]]|$1|S|3|T|5|L|7|1C|8|@]|9|@]|A|$M|N]]|$1|U|3|V|5|6|7|1D|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1E|8|@$D|1F|E|1G|F|G]]|9|@]|A|$]]|$1|Y|3|Z|5|L|7|1H|8|@]|9|@]|A|$M|N]]|$1|10|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]]|11|$]]

So based on your example, you are actually outputting the information for November 2017, which starts on a Wednesday.

To achieve what you are looking for, you simply need to find out what day of the week it is and then add additional 'empty' items to your <code>$list</code> array if you need to pad the month.

To find out the day of the week use:

<pre><code>... // Your existing code under Make List
$year = date('Y', strtotime('-1 year'));

$date = '01-' . $month . '-' . $year;
$dayofweek = date('w', strtotime($date));
</code></pre>

Now <code>$dayofweek</code> will contain the numeric number of the week, with 0 being Sunday, 1 being Monday, and so on.

Next, just add empty items into your list array to pad the number of days that should be empty:

<pre><code>if ($dayofweek == 0) $dayofweek = 7;
for (; $dayofweek &gt; 1; $dayofweek--)
 $list[] = '';
</code></pre>

Note that where the start day is Sunday, I change this to 7 to cause the padding of 6 boxes.

Finally, when you output your list items, just add an empty day <code>&lt;li&gt;</code> for each padded day:

<pre><code>... // Your existing code
foreach($list as $day){
 if ($day == '')
 echo '&lt;li&gt;Empty day&lt;/li&gt;';
 else if($day &lt; date('d')){
 ... // Your existing code continues
</code></pre>

blocks|key|2554127|text|对于这个示例，最简单的解决方案是根据日历周而不是天来重构代码。下面的代码应该可以帮助您做到这一点，但您需要完成代码的其余部分才能以您想要的方式显示它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2554128|$currentMonth+=+date('m');
++++$daysInMonth+=+date('t');
++++$currentDay+=+0;
++++$firstOfMonthDay+=+date('w',+strtotime('2017-01-01'));
++++nextWeek+=+true;


++++while(nextWeek){+//+displays+weekly+fields
++++++++counter+=+1;
++++++++while(counter+<=+7){+//+displays+empty+box+or+date
++++++++++++formatBox();
++++++++++++if($firstOfMonthDay+==+$counter){
++++++++++++++++//+starts+printing+date
++++++++++++++++$currentDay%2B%2B;
++++++++++++}
++++++++++++if($currentDay+>+0+&&+$currentDay+<=+$daysInMonth){
++++++++++++++++//+prints+date+while+the+month+has+valid+days
++++++++++++++++printDay();
++++++++++++}
++++++++++++$currentDay%2B%2B;
++++++++++++counter%2B%2B;
++++++++}
++++++++if($currentDay+<+$daysInMonth){
++++++++++++//+stops+printing+new+weeks+when+there+are+no+more+valid
++++++++++++//+days+in+the+month
++++++++++++nextWeek+=+false;
++++++++}
++++}|code-block|syntax|javascript|2554129|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The simplest solution for this example is to restructure your code around the calendar weeks instead of the days. The code below should help you do that, but you will need to finish the rest of the code to display it however you want.

<pre><code>$currentMonth = date('m');
 $daysInMonth = date('t');
 $currentDay = 0;
 $firstOfMonthDay = date('w', strtotime('2017-01-01'));
 nextWeek = true;


 while(nextWeek){ // displays weekly fields
 counter = 1;
 while(counter &lt;= 7){ // displays empty box or date
 formatBox();
 if($firstOfMonthDay == $counter){
 // starts printing date
 $currentDay++;
 }
 if($currentDay &gt; 0 &amp;&amp; $currentDay &lt;= $daysInMonth){
 // prints date while the month has valid days
 printDay();
 }
 $currentDay++;
 counter++;
 }
 if($currentDay &lt; $daysInMonth){
 // stops printing new weeks when there are no more valid
 // days in the month
 nextWeek = false;
 }
 }
</code></pre>

I am trying to make a calendar with HTML, CSS and PHP. And so far, it went well. But at the end, I discovered that I forgot that months not always starts on a monday.

<a href="https://i.stack.imgur.com/TxSkI.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/TxSkI.png" alt="Image"></a>

How would I do this? I am not that strong in PHP, and cant really figure out how I would do it.

This month for example (December), I would need to add 5 "hidden or disabled" days infront, to match that December 1st is a Saturday.

<pre><code>&lt;!-- Week Days --&gt;
&lt;ul class="weekdays"&gt;
 &lt;li&gt;Monday&lt;/li&gt;
 &lt;li&gt;Tuesday&lt;/li&gt;
 &lt;li&gt;Wednesday&lt;/li&gt;
 &lt;li&gt;Thursday&lt;/li&gt;
 &lt;li&gt;Friday&lt;/li&gt;
 &lt;li&gt;Saturday&lt;/li&gt;
 &lt;li&gt;Sunday&lt;/li&gt;
&lt;/ul&gt;
&lt;!-- Days --&gt;
&lt;ul class="days"&gt; 
&lt;?php

 // Make List
 $list = array();
 $month = date('m', strtotime('-1 month'));
 $year = date('Y', strtotime('-1 year'));

 for($d = 1; $d &lt;= 31; $d++){
 $time = mktime(12, 0, 0, $month, $d, $year); 

 if(date('m', $time) == $month) 
 $list[] = date('d', $time);
 }
 if(is_array($list) || is_object($list)){
 foreach($list as $day){

 if($day &lt; date('d')){
 echo '&lt;li class="passed"&gt;&lt;span&gt;' . $day . '&lt;/span&gt;&lt;/li&gt;';
 }else if($day == date('d')){
 echo '&lt;li class="current"&gt;&lt;span&gt;' . $day . '&lt;/span&gt;&lt;/li&gt;';
 }else{
 echo '&lt;li&gt;&lt;span&gt;' . $day . '&lt;/span&gt;&lt;/li&gt;';
 }
 }
 }
?&gt;
&lt;/ul&gt;
</code></pre>

Match week Names with week Days in PHP

我正在尝试用HTML，CSS和PHP制作一个日历。到目前为止，一切都很顺利。但最后，我发现我忘记了月份并不总是从星期一开始。​​我该怎么做呢？我在PHP方面不是很强，也不知道我该怎么做。以本月(12月)为例，我需要在前面添加5个“隐藏或禁用”天，以匹配12月1日是星期六。<ul cl...

问在PHP中将周名称与周天数相匹配
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在PHP中将周名称与周天数相匹配EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在PHP中将周名称与周天数相匹配
EN