blocks|key|2625721|text|您可以将变量作为值存储到双精度数组中，然后可以使用TicketType中的索引访问该值。就像这样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2625722|int+TicketType+=+0;
double+ticketsValues[]+=+[18.00,32.00,32.50];+//The+first+position+is+ChildTicket,+the+2nd+AdultTicket+and+so..
int+TicketQuantity+=+0;
double+TotalCost+=+ticketsValue[TicketType]+*+TicketQuantity;//Here+you+access+to+the+value+depending+on+the+TicketType.|code-block|syntax|javascript|2625723|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can store your variables as values into an array of doubles, then you can access to the value by using the index that is in the TicketType. Just like this:

<pre><code>int TicketType = 0;
double ticketsValues[] = [18.00,32.00,32.50]; //The first position is ChildTicket, the 2nd AdultTicket and so..
int TicketQuantity = 0;
double TotalCost = ticketsValue[TicketType] * TicketQuantity;//Here you access to the value depending on the TicketType.
</code></pre>

blocks|key|2415446|text|对它使用Enum，就像这样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2415447|public+enum+TicketType+{
ADULT(36),+CHILD(18),+SENIOR(32,50);

private+final+int+cost;
TicketType(int+cost)+{+this.cost+=+cost;+}
public+int+getValue()+{+return+cost;+}|code-block|syntax|javascript|2415448|}|2415449|public+int+getTotalPrice(TicektType+tp,+int+quantity){
return+tp.getValue()+*+quantity;|2415450|2415451|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|O|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|P|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|K|3|H|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

Use Enum for it, something like that :

<pre><code>public enum TicketType {
ADULT(36), CHILD(18), SENIOR(32,50);

private final int cost;
TicketType(int cost) { this.cost = cost; }
public int getValue() { return cost; }
</code></pre>

}

<pre><code>public int getTotalPrice(TicektType tp, int quantity){
return tp.getValue() * quantity;
</code></pre>

}

blocks|key|2415484|text|我建议使用带有构造函数的枚举，比如|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2415485|public+enum+Ticket{
++++SENIOR(7.0),+ADULT(10.0),+CHILD(3.0);

++++Ticket(double+price)+{
++++++++this.price+=+price;
++++}

++++private+final+double+price;

++++public+double+getPrice()+{
++++++++return+price;
++++}
}|code-block|syntax|javascript|2415486|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I would suggest using an enum with a constructor like 

<pre><code>public enum Ticket{
 SENIOR(7.0), ADULT(10.0), CHILD(3.0);

 Ticket(double price) {
 this.price = price;
 }

 private final double price;

 public double getPrice() {
 return price;
 }
}
</code></pre>

blocks|key|2625824|text|有不同的方法来解决这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2625825|我建议为不同类型的票据创建一个Enum。|offset|length|style|CODE|2625826|public+enum+TicketType+{
++++SENIOR(32.50D),
++++ADULT(36.00D),
++++CHILD(18.00D);

++++private+final+double+price;

++++TicketType(double+price)+{
++++++++this.price+=+price;
++++}

++++public+double+getPrice()+{
++++++++return+price;
++++}

++++public+double+getCalculatedPrice(int+ticketAmount)+{
++++++++return+price+*+ticketAmount;
++++}
}|code-block|syntax|javascript|2625827|相反，你也可以尝试这样做|2625828|int+ticketType+=+0;+//change
double[]+prices+=+{32.50D,+36.00D,+18.00D};+//Senior,+Adult,+Child
int+ticketQuantity+=+0;+//change
int+totalCost+=+prices[ticketType]+*+ticketQuantity;|2625829|此外，您还应该检查ticketType是否大于或小于prices大小，以避免出现ArrayIndexOutOfBoundsException。您还应该检查数量是否不小于零。|2625830|entityMap^0|0|F|4|0|0|0|0|9|A|Q|6|14|U|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|Y|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|11|8|@$D|12|E|13|F|G]|$D|14|E|15|F|G]|$D|16|E|17|F|G]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|T|$]]

There are different ways to solve this.

I would recommend to create an <code>Enum</code> for the different type of tickets.

<pre><code>public enum TicketType {
 SENIOR(32.50D),
 ADULT(36.00D),
 CHILD(18.00D);

 private final double price;

 TicketType(double price) {
 this.price = price;
 }

 public double getPrice() {
 return price;
 }

 public double getCalculatedPrice(int ticketAmount) {
 return price * ticketAmount;
 }
}
</code></pre>

Instead of that you can also try this way

<pre><code>int ticketType = 0; //change
double[] prices = {32.50D, 36.00D, 18.00D}; //Senior, Adult, Child
int ticketQuantity = 0; //change
int totalCost = prices[ticketType] * ticketQuantity;
</code></pre>

Some additions to that you should check if the <code>ticketType</code> isn't bigger or less than the <code>prices</code> size to avoid a <code>ArrayIndexOutOfBoundsException</code>. You also should check if the quantity isn't less than zero.

blocks|key|2415547|text|由于年龄组(老年人、成人、儿童)不应该改变，因此像其他答案建议的那样定义枚举(TicketType)是合适的。但由于价格可能会发生变化，我不会在枚举本身中硬编码它们。我建议使用地图：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2415548|Map<TicketType,+Double>+prices+=+new+EnumMap<>(TicketType.class);
prices.put(TicketType.CHILD,+ChildTicket);
prices.put(TicketType.ADULT,+AdultTicket);
prices.put(TicketType.SENIOR,+SeniorTicket);|code-block|syntax|javascript|2415549|地图可以填充从数据源读取的价格，并在每次价格变化时更新。|2415550|例如，要得到一个成年人的价格，只需打电话：|2415551|double+adultPrice+=+prices.get(TicketType.ADULT);|2415552|或者更一般的：|2415553|public+double+getPriceFor(TicketType+type)+{
++++return+prices.get(type)+;
}|2415554|来回答你问题的最后一部分。然后可以按如下方式计算总成本：|2415555|public+double+getTotalCost(int+children,+int+adults,+int+seniors)+{
++++return+getPriceFor(TicketType.CHILD)+*+children+%2B
++++++++++++getPriceFor(TicketType.ADULT)+*+adults%2B
++++++++++++getPriceFor(TicketType.SENIOR)+*+seniors;
}|2415556|entityMap^0|13|A|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|15|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|17|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|U|3|V|5|6|7|19|8|@]|D|@]|E|$]]|$1|W|3|X|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|Y|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|Z|$]]

As the age groups (senior, adult, child) shouldn't change it's appropriate to define an enum (<code>TicketType</code>) for like the other answers suggest. But since the prices may change I wouldn't hard code them in the enum iself. I suggest to use a map:

<pre><code>Map&lt;TicketType, Double&gt; prices = new EnumMap&lt;&gt;(TicketType.class);
prices.put(TicketType.CHILD, ChildTicket);
prices.put(TicketType.ADULT, AdultTicket);
prices.put(TicketType.SENIOR, SeniorTicket);
</code></pre>

The map could be filled with prices read from a datasource and updated everytime a price changes.

Getting the price for an adult for example is just calling:

<pre><code>double adultPrice = prices.get(TicketType.ADULT);
</code></pre>

or more general:

<pre><code>public double getPriceFor(TicketType type) {
 return prices.get(type) ;
}
</code></pre>

To answer the last part of your question. The total cost can be calculated then as follows:

<pre><code>public double getTotalCost(int children, int adults, int seniors) {
 return getPriceFor(TicketType.CHILD) * children +
 getPriceFor(TicketType.ADULT) * adults+
 getPriceFor(TicketType.SENIOR) * seniors;
}
</code></pre>

blocks|key|2415756|text|这就是我最终要做的。步骤1在初始化中添加了其他选项|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2415757|++++double+Option1+=+ChildTicket;
++++double+Option2+=+AdultTicket;
++++double+Option3+=+SeniorTicket;|code-block|syntax|javascript|2415758|然后-在需要信息和结果的实际代码中，创建了一系列与正确选项相关的if语句：|2415759|++++if+(TicketType+==+1)+{
+++++++++System.out.println+("Child+tickets+are+$18.00,How+many+would+you+like+to+purchase?");+
+++++++++TicketQuantity+=input.nextInt();
+++++++++TotalCost+=+Option1+*+TicketQuantity;
+++++++++System.out.println+("Total+Cost+of+tickets+=+$"+%2B+(TotalCost));
+++++++++System.out.println+("Press+1+to+confirm");
+++++++++Confirmation+=+input.nextInt();|2415760|对于初学者来说还不错|2415761|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

And here is what I ended up doing. Step 1 added additional options in the initialization

<pre><code> double Option1 = ChildTicket;
 double Option2 = AdultTicket;
 double Option3 = SeniorTicket;
</code></pre>

THEN - In the actual code where it required the information and results, created a miniseries of if statements to correlate to the correct option:

<pre><code> if (TicketType == 1) {
 System.out.println ("Child tickets are $18.00,How many would you like to purchase?"); 
 TicketQuantity =input.nextInt();
 TotalCost = Option1 * TicketQuantity;
 System.out.println ("Total Cost of tickets = $" + (TotalCost));
 System.out.println ("Press 1 to confirm");
 Confirmation = input.nextInt();
</code></pre>

Not bad for a beginner

Needing a guidance moment from the coding gods on how I could go about making my code do what I need it to.

So the situation is: 
I need to tell the program to run the calculation of the ticket price times the number of tickets purchased. Seems easy? BUT - There are three variables pre-luding to this.

See below:

<pre><code> int TicketType = 0;
 double ChildTicket = 18.00;
 double AdultTicket = 36.00;
 double SeniorTicket = 32.50;
 int TicketQuantity = 0;
 double TotalCost = ?
</code></pre>

Essentially - What i need to have happen from a Psuedocode level to make this easier:

<pre><code>Compute TotalCost = Result of ticket type (ChildTicket,AdultTicket or SeniorTicket) * TicketQuantity
</code></pre>

Any help would be amazing! :)

Java Coding - Multiple Variables to create answer variable

我需要一个来自编码之神的指导时刻，告诉我如何让我的代码做我需要它做的事情。所以情况是这样的：，，我需要告诉程序运行，计算票价乘以购买的门票数量。看起来很简单？，但是-有三个变量预示着这一点。如下所示：    int TicketType = 0;    double ChildTicket = 18.00;    do...

问Java编码-创建答案变量的多个变量
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