blocks|key|89436|text|使用DateTime类并通过diff()方法对它们进行比较。$date1->diff($date2)。输出将为您提供准确的天数结果：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|89437|$date1+=+new+DateTime('2018-01-01');
$date2+=+new+DateTime('2018-02-15');

print_r($date1->diff($date2));|code-block|syntax|javascript|89438|输出：|89439|DateInterval+Object+
(+
[y]+=>+0+
[m]+=>+1+
[d]+=>+14+
[h]+=>+0+
[i]+=>+0+
[s]+=>+0+
[f]+=>+0+
[weekday]+=>+0+
[weekday_behavior]+=>+0+
[first_last_day_of]+=>+0+
[invert]+=>+0+
[days]+=>+45+
[special_type]+=>+0+
[special_amount]+=>+0+
[have_weekday_relative]+=>+0+
[have_special_relative]+=>+0+
)|89440|entityMap^0|2|8|E|6|U|K|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|P|$]]

Use the <code>DateTime</code> class and compare them via <code>diff()</code> method. <code>$date1-&gt;diff($date2)</code>. The output will give you an accurate result of days:

<pre><code>$date1 = new DateTime('2018-01-01');
$date2 = new DateTime('2018-02-15');

print_r($date1-&gt;diff($date2));
</code></pre>

Output:

<pre><code>DateInterval Object 
( 
[y] =&gt; 0 
[m] =&gt; 1 
[d] =&gt; 14 
[h] =&gt; 0 
[i] =&gt; 0 
[s] =&gt; 0 
[f] =&gt; 0 
[weekday] =&gt; 0 
[weekday_behavior] =&gt; 0 
[first_last_day_of] =&gt; 0 
[invert] =&gt; 0 
[days] =&gt; 45 
[special_type] =&gt; 0 
[special_amount] =&gt; 0 
[have_weekday_relative] =&gt; 0 
[have_special_relative] =&gt; 0 
)
</code></pre>

blocks|key|2826307|text|你可以试试这个-|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2826308|$dateOne+=+new+DateTime("01-01-2018");
$dateTwo+=+new+DateTime("09-06-2018");

echo+$diff+=+$dateTwo->diff($dateOne)->format("%25a");|code-block|syntax|javascript|2826309|输出-+159|offset|length|style|BOLD|2826310|entityMap^0|0|0|0|3|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can try this-

<pre><code>$dateOne = new DateTime("01-01-2018");
$dateTwo = new DateTime("09-06-2018");

echo $diff = $dateTwo-&gt;diff($dateOne)-&gt;format("%a");
</code></pre>

Output- 159

blocks|key|91881|text|<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo+$diff->format("%25R%25a+days");
?>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|91882|输出:+272天。|unstyled|91883|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>&lt;?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff-&gt;format("%R%a days");
?&gt;
</code></pre>

Output : 272 days.

blocks|key|89700|text|这里我在第一个程序php+time()中得到了您的解决方案；函数是根据当前时间动态变化的，单位为毫秒(在PHP中，您可以简单地调用time+()来获取自1970年1月1日00:00:00+GMT以来经过的时间(以秒为单位))。这里您正在使用round函数来获取12+as之后的四舍五入的值。您的计算将增加超过8.5，您得到的舍入值为9|type|unstyled|depth|inlineStyleRanges|entityRanges|data|89701|在这里简要说明Getting+unix+timestamp+in+milliseconds+in+PHP5+and+Actionscript3|offset|length|89702|在程序其余部分中，您使用的是不受系统时间影响的静态时间或自定义时间|89703|++++$now+=+time();+//+or+your+date+as+well
++++$your_date+=+strtotime("2018-06-01");
++++$datediff+=+$now+-+$your_date;
++++echo+round($datediff+/+(60+*+60+*+24));|code-block|syntax|javascript|89704|在中午12点前试试上面的程序，也许你会得到答案|89705|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1063513/getting-unix-timestamp-in-milliseconds-in-php5-and-actionscript3^0|0|7|1S|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

here i got your solution in first program php time(); function is dynamically change as per current time in millisecond (In PHP you can simply call time() to get the time passed since January 1 1970 00:00:00 GMT in seconds) here you are using round function to get rounded value after 12pm it your calculation will increase more then 8.5 and you get a rounded value which is 9

here brief explanation <a href="https://stackoverflow.com/questions/1063513/getting-unix-timestamp-in-milliseconds-in-php5-and-actionscript3">Getting unix timestamp in milliseconds in PHP5 and Actionscript3</a>

in rest of program you are taking static time or custom time which are not effected by system time 

<pre><code> $now = time(); // or your date as well
 $your_date = strtotime("2018-06-01");
 $datediff = $now - $your_date;
 echo round($datediff / (60 * 60 * 24));
</code></pre>

try above program before 12pm maybe you got your answer

blocks|key|89722|text|首先编译并打印$now，几分钟后写出put；第二次编译并打印$now，你会有所不同|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|89723|entityMap^0|7|4|U|4|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

First compile and print <code>$now</code> and write down out put after some minutes 2nd time compile and print <code>$now</code> you will ge a difference

blocks|key|91942|text|您可以尝试这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|91943|++<?php
++++$start_date+=+"2020-12-24";
++++$end_date+++=+"2020-12-31";
++++$dateDiff+++=+strtotime($end_date)+-+strtotime($start_date);
++++$numOfDays++=+$dateDiff+/+86400;
++++echo+$numOfDays;
++?>|code-block|syntax|javascript|91944|输出:7|91945|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can try this:
<pre><code> &lt;?php
 $start_date = &quot;2020-12-24&quot;;
 $end_date = &quot;2020-12-31&quot;;
 $dateDiff = strtotime($end_date) - strtotime($start_date);
 $numOfDays = $dateDiff / 86400;
 echo $numOfDays;
 ?&gt;
</code></pre>
Output: 7

I want to count the total number of days between two date.

<blockquote>
 Note: I am not talking about the difference between two date
</blockquote>

I found lots of answer on google and Stack Overflow. I am sharing here

<pre><code>$now = time(); // or your date as well
$your_date = strtotime("2018-06-01");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
</code></pre>

Output is 9

<pre><code>$now = strtotime("2018-06-09");
$your_date = strtotime("2018-06-01"); 
$datediff = $now - $your_date;
echo $numberDays= round($datediff / (60 * 60 * 24));
</code></pre>

Output is 8

<pre><code>$dStart = new DateTime('2018-06-01');
$dEnd = new DateTime('2018-06-09');
$dDiff = $dStart-&gt;diff($dEnd);
echo $dDiff-&gt;days;
</code></pre>

Output is 8

<pre><code>$date1=date_create("2018-06-01");
$date2=date_create("2018-06-09");
$diff=date_diff($date1,$date2);
echo $diff-&gt;format("%a");
</code></pre>

Output is 8

<pre><code>$startTimeStamp = strtotime("2018-06-01");
$endTimeStamp = strtotime("2018-06-09");
$timeDiff = abs($endTimeStamp - $startTimeStamp);
$numberDays = $timeDiff/86400; // 86400 seconds in one day
// and you might want to convert to integer
echo $numberDays = intval($numberDays); 
</code></pre>

Output is 8

The correct answer for me is the first one 9 because it displays the total number of days from 1 to 9, not a difference.

I just want to know how to get the count because I don't want to use the time() because it's taking the current date.

For example: If I select the first date 2018-05-01 and my second date in 2018-05-31. So total days is 31, not 30.

Example: 
I am working on a project which is related to the working days and salary. So employee will select the date. for example. I am the employee and in the last month May, I select the date 2018-05-01 and 2018-05-31 so I have to display the total working days.So the according to the date I worked 31 days and using above code in the question I am getting 30 days.

Hope you understand my issue. Would you help me out in this?

How to display total number of days between two dates using php

我想计算两个日期之间的总天数。注:我不是在谈论两个日期之间的区别我在google和Stack Overflow上找到了很多答案。我在这里分享$now = time(); // or your date as well$your_date = strtotime("2018-06-01");$datediff = $no...

问如何使用php显示两个日期之间的总天数
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何使用php显示两个日期之间的总天数EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何使用php显示两个日期之间的总天数
EN