将数据从VC传递到VC段
将数据从VC传递到VC段
提问于 2014-05-21 08:50:15
我使用这段代码将一个对象传递给另一个视图控制器。
-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
if([segue.identifier isEqualToString:@"Detail"]){
UINavigationController *navController = (UINavigationController *)segue.destinationViewController;
DetailedViewController *controller = (DetailedViewController *)navController.topViewController;
controller.clipping = [pasteBoardArray objectAtIndex:_row];
}
}关于下面这一行：
DetailedViewController *controller = (DetailedViewController *)navController.topViewController;我得到了一个很长的异常
2014-05-20 18:46:39.752 SWTableViewCell[8370:60b] -[DetailedViewController topViewController]: unrecognized selector sent to instance 0x10c7169e0
2014-05-20 18:46:39.756 SWTableViewCell[8370:60b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[DetailedViewController topViewController]: unrecognized selector sent to instance 0x10c7169e0'
*** First throw call stack:
(
0 CoreFoundation 0x0000000102667495 __exceptionPreprocess + 165
1 libobjc.A.dylib 0x00000001016c699e objc_exception_throw + 43
2 CoreFoundation 0x00000001026f865d -[NSObject(NSObject) doesNotRecognizeSelector:] + 205
3 CoreFoundation 0x0000000102658d8d ___forwarding___ + 973
4 CoreFoundation 0x0000000102658938 _CF_forwarding_prep_0 + 120
5 SWTableViewCell 0x000000010000d91c -[ViewController prepareForSegue:sender:] + 204
6 UIKit 0x00000001004f4c73 -[UIStoryboardSegueTemplate _perform:] + 134
7 SWTableViewCell 0x000000010000c4be -[ViewController tableView:didSelectRowAtIndexPath:] + 350
8 SWTableViewCell 0x00000001000089ae -[SWTableViewCell selectCell] + 798
9 SWTableViewCell 0x000000010000864b -[SWTableViewCell scrollViewTapped:] + 171
10 UIKit 0x0000000100362fc2 _UIGestureRecognizerSendActions + 188
11 UIKit 0x0000000100361f28 -[UIGestureRecognizer _updateGestureWithEvent:buttonEvent:] + 357
12 UIKit 0x00000001003662d9 ___UIGestureRecognizerUpdate_block_invoke + 53
13 UIKit 0x0000000100366261 _UIGestureRecognizerRemoveObjectsFromArrayAndApplyBlocks + 257
14 UIKit 0x000000010035e337 _UIGestureRecognizerUpdate + 93
15 UIKit 0x0000000100072a15 -[UIWindow _sendGesturesForEvent:] + 928
16 UIKit 0x00000001000736d4 -[UIWindow sendEvent:] + 909
17 UIKit 0x000000010004b29a -[UIApplication sendEvent:] + 211
18 UIKit 0x0000000100038aed _UIApplicationHandleEventQueue + 9579
19 CoreFoundation 0x00000001025f6d21 __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 17
20 CoreFoundation 0x00000001025f65f2 __CFRunLoopDoSources0 + 242
21 CoreFoundation 0x000000010261246f __CFRunLoopRun + 767
22 CoreFoundation 0x0000000102611d83 CFRunLoopRunSpecific + 467
23 GraphicsServices 0x00000001025c6f04 GSEventRunModal + 161
24 UIKit 0x000000010003ae33 UIApplicationMain + 1010
25 SWTableViewCell 0x0000000100002763 main + 115
26 libdyld.dylib 0x000000010607f5fd start + 1
)
libc++abi.dylib: terminating with uncaught exception of type NSException顺便说一句，我是在一个UINavigationBarController中完成这一切的。我所需要做的就是将objectAtIndex:_row传递给DetailedViewController中的_clipping属性。
回答 2
Stack Overflow用户
发布于 2014-05-21 09:15:52
如果两个视图控制器之间没有导航控制器，请使用以下代码：
-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
if([segue.identifier isEqualToString:@"Detail"]){
DetailedViewController *controller = (DetailedViewController *)[segue destinationViewController];
controller.clipping = [pasteBoardArray objectAtIndex:_row];
/* ... */
}
}仅当两个视图控制器之间有一个导航控制器时，才使用以下代码：
-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
if([segue.identifier isEqualToString:@"Detail"]){
UINavigationController *navController = (UINavigationController *)segue.destinationViewController;
DetailedViewController *controller = (DetailedViewController *)navController.topViewController;
controller.clipping = [pasteBoardArray objectAtIndex:_row];
/* ... */
}
}Stack Overflow用户
发布于 2014-05-21 11:07:36
您发布的错误消息表明您的segue的目标视图控制器并不是您所认为的导航控制器。您应该记录目标视图控制器的类，以查看它是什么。
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原文链接：
https://stackoverflow.com/questions/23772263
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