为什么web.xml 'context-param‘不能有字符[子]？
为什么web.xml 'context-param‘不能有字符[子]？
提问于 2013-03-13 22:26:38
我只是想知道在Eclipse (juno版)的Markers视图中出现这个错误cvc-complex-type.2.3: Element 'context-param' cannot have character [children], because the type's content type is element-only.的web.xml代码发生了什么。
代码如下：
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID"
version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<display-name>Spring security web application (series)</display-name>
<!-- to specifically stop trouble with multiple apps on tomcat -->
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>customauth_root</param-value>
</context-param>
<!-- Location of the XML file that defines the root application context
applied by ContextLoaderListener. -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
WEB-INF/applicationContext.xml
WEB-INF/applicationContext-security.xml
</param-value>
</context-param>
<!-- Loads the root application context of this web app at startup. The
application context is then available via WebApplicationContextUtils.getWebApplicationContext(servletContext). -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>
org.springframework.security.web.session.HttpSessionEventPublisher</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!-- Provides core MVC application controller. See customauth-servlet.xml. -->
<servlet>
<servlet-name>customauth</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>customauth</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>customauth</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>回答 3
Stack Overflow用户
发布于 2013-04-10 21:38:09
对于初学者，您在XML节点param-value中使用了非法字符
不允许在节点中使用"/“、"<”和其他字符，因为它们会破坏XML文档的解析。
应该在XML节点内的值周围使用CDATA或PCDATA包装器。
例如：
<param-value><![CDATA[
WEB-INF/applicationContext.xml
WEB-INF/applicationContext-security.xml]]>
</param-value>这就是导致你的问题的原因。
Stack Overflow用户
发布于 2013-10-08 00:29:03
一些不可见的字符不被视为XML空白，因此显示错误。通过配置Eclipse "Text Editor“首选项来显示所有空格字符，然后红色字符将会突出显示出来。您还可以使用此工具来验证XML文件：
xmllint --noout --schema http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd XML_FILEStack Overflow用户
发布于 2016-05-24 01:02:28
您正在注释结束标记，请再次查看<filter-mapping>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern> /*</url-pattern>
</filter-mapping>`页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/15388084
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