以鼠标为增量移动玩家：pygame
以鼠标为增量移动玩家：pygame
提问于 2019-03-21 04:42:53
我使用tkinter而不是pygame，但我正在做一个pygame项目，我需要一些帮助让玩家以增量移动鼠标而不是传送到那里。我知道我可以用矢量来做，但我需要一些帮助。我目前的代码：
import pygame
import random
import sys
import time
import math
import os
WHITE = (255, 255, 255)
DARKGRAY = ( 70, 70, 70)
BLACK = ( 0, 0, 0)
RED = (255, 0, 0)
GREEN = ( 0, 255, 0)
BLUE = ( 0, 0, 255)
YELLOW = (255, 255, 0)
ORANGE = (255, 128, 0)eeeeeee
PURPLE = (255, 0, 255)
LIGHT_ORANGE = (255,165,0)
pygame.init()
screen_width = 700
screen_height = 400
screen = pygame.display.set_mode([screen_width, screen_height])
def text_objects(text, font, col):
textSurface = font.render(text, True, col)
return textSurface, textSurface.get_rect()
def center_display_subtitle(text, x, y, coll):
largeText = pygame.font.Font('freesansbold.ttf',45)
TextSurf, TextRect = text_objects(text, largeText, coll)
TextRect.center = (x, y)
screen.blit(TextSurf, TextRect)
clock = pygame.time.Clock()
done = False
while done == False:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
screen.fill(BLACK)
center_display_subtitle('Generic Game', 350, 100, RED)
mouse = pygame.mouse.get_pos()
click = pygame.mouse.get_pressed()
if 300+100 > mouse[0] > 300 and 300+50 > mouse[1] > 300:
pygame.draw.rect(screen, LIGHT_ORANGE,(300,300,100,50))
if click[0] == 1:
done = True
else:
pygame.draw.rect(screen, ORANGE,(300,300,100,50))
center_display_subtitle('Play', 350, 325, BLACK)
clock.tick(60)
pygame.display.flip()
done = False
screen.fill(BLACK)
center_display_subtitle('LOADING...', 350, 100, BLUE)
pygame.display.flip()
class Player(pygame.sprite.Sprite):
def __init__(self, color, width, height):
super().__init__()
self.image = pygame.Surface([width, height])
self.image.fill(color)
self.colour = color
self.time2 = 0
self.speed = 20
self.set_target((0, 0))
self.rect = self.image.get_rect()
self.pos = pygame.math.Vector2(0, 0)
def set_target(self, posi):
self.target = pygame.math.Vector2(posi)
def update(self):
move = self.target - self.pos
move_length = move.length()
self.rect = self.target
all_sprites_list = pygame.sprite.Group()
player = Player(RED, 32, 32)
all_sprites_list.add(player)
while done == False:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
if event.type == pygame.MOUSEBUTTONDOWN:
for ship in all_sprites_list:
ship.set_target(pygame.mouse.get_pos())
screen.fill(BLACK)
all_sprites_list.update()
all_sprites_list.draw(screen)
clock.tick(60)
pygame.display.flip()*
代码用于主菜单和小型“迷你游戏”，玩家稍后将不得不躲避敌人或其他东西。真的，这只是一个pygame测试（就像我说我使用Tkinter），我会很高兴的帮助。
回答 2
Stack Overflow用户
发布于 2019-03-21 13:02:50
Stack Overflow用户
发布于 2019-03-21 14:06:04
pygame.math.Vector2.normalize将玩家的方向向量标准化（）到目标。这意味着方向向量的长度变为1：
move = move.normalize()
将self.pos目标位置（）移动到目标方向，距离目标（move_length）和速度（self.speed）的距离最小值：
self.pos = self.pos + move * min(self.speed, move_length)
最后更新self.rect：
self.rect = self.pos
class Player(pygame.sprite.Sprite):
# [...]
def update(self):
move = self.target1 - self.pos
move_length = move.length()
if move_length > 0:
move = move.normalize()
self.pos = self.pos + move * min(self.speed, move_length)
self.rect = self.pos
注意，我建议降低速度：
self.speed = 5
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/-100006485
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