如何创建“下一步”和“上一步”按钮来导航列表？
如何创建“下一步”和“上一步”按钮来导航列表？
提问于 2019-04-12 03:38:44
我正在做这个项目，我被卡住了。我有一个表单，在表单上，我有一个下一步按钮和上一步按钮：
在我的HouseList类中，我有这段代码，我想要做的是创建一个方法来获得下一个房子，另一个方法来获得前一个房子。我已经试了很久了。
public HouseList()
{
housesList = new List<House>();
housesList.Add(new House()
{
Address = "35 Twin Oaks",
City = "Glendale",
Zip = "MDN6L3",
AskingPrice = "328,743.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739.00"
});
housesList.Add(new House()
{
Address = "35 Helen Drive",
City = "OakDale",
Zip = "G6L5M4",
AskingPrice = "455,899.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739,00"
});
housesList.Add(new House()
{
Address = "4 RiverBank Rd",
City = "Brampton",
Zip = "L9H4L2",
AskingPrice = "699,999.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739,00"
});
}
public List<string> NextHouse()
{
List<string> house = new List<string>();
foreach (House h in housesList)
{
int index = 0;
string conv = Convert.ToString(index);
if (conv == house[1])
{
conv = house[1];
}
}
return house;
}回答 2
Stack Overflow用户
回答已采纳
发布于 2019-04-12 03:51:05
您需要有一个索引来告诉您哪个索引是当前索引。最小索引的索引将被比较为0，而最大索引的索引将被比较为would List.Count-1。考虑到这一点，NextHouse和PreviousHouse应该返回House而不是List<House>。
public House NextHouse(){
if(currentIndex + 1 != houseList.Count)
currentIndex++;
return houseList[currentIndex]
}
public House PreviousHouse(){
if(currentIndex -1 >= 0)
currentIndex--;
return houseList[currentIndex];
}因此，如果你在列表中已经是最后一所房子的时候请求下一所房子，它只会返回最后一所房子。当你在列表的第一个位置时，如果你请求上一个房子，它将返回第一个房子。
为此，您必须将currentIndex初始化为类成员。
Stack Overflow用户
发布于 2019-04-12 03:50:07
这是下一项：
public List<House> housesList;
int currentIndex = 0;
public HouseList()
{
housesList = new List<House>();
housesList.Add(new House()
{
Address = "35 Twin Oaks",
City = "Glendale",
Zip = "MDN6L3",
AskingPrice = "328,743.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739.00"
});
housesList.Add(new House()
{
Address = "35 Helen Drive",
City = "OakDale",
Zip = "G6L5M4",
AskingPrice = "455,899.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739,00"
});
housesList.Add(new House()
{
Address = "4 RiverBank Rd",
City = "Brampton",
Zip = "L9H4L2",
AskingPrice = "699,999.00",
PictureFile = "",
AveragePrice = "490,747.80",
Total = "2,453,739,00"
});
}
public House NextHouse()
{
return housesList[(++currentIndex)%housesList.Count()];
}这将在到达最后一项时循环。如果你想让它停止，改变逻辑。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/55640003
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