同一按钮上的开/关事件
同一按钮上的开/关事件
提问于 2019-04-25 07:28:47
我有一个与CSS一起工作的切换按钮，但当它打开和关闭时，我需要添加一些逻辑。问题是jQuery不能读取CSS上的:after和:before，因为它们实际上不是DOM的一部分。
-切换--
<div class="onoffswitch">
<input type="checkbox" name="onoffswitch" class="onoffswitch-checkbox" id="myonoffswitch">
<label class="onoffswitch-label" for="myonoffswitch">
<span id="switch-inner" class="onoffswitch-inner"></span>
<span class="onoffswitch-switch"></span>
</label>
</div>--CSS--
.onoffswitch {
position: relative; width: 78px;
-webkit-user-select:none; -moz-user-select:none; -ms-user-select: none;
}
.onoffswitch-checkbox {
display: none;
}
.onoffswitch-label {
display: block; overflow: hidden; cursor: pointer;
border: 2px solid #C2C2C2; border-radius: 20px;
}
.onoffswitch-inner {
display: block; width: 200%; margin-left: -100%;
transition: margin 0.3s ease-in 0s;
}
.onoffswitch-inner:before, .onoffswitch-inner:after {
display: block; float: left; width: 50%; height: 28px; padding: 0; line-height: 28px;
font-size: 14px; color: white; font-family: Trebuchet, Arial, sans-serif; font-weight: bold;
box-sizing: border-box;
}
.onoffswitch-inner:before {
content: "ON";
padding-left: 10px;
background-color: #5C7FE3; color: #FFFFFF;
}
.onoffswitch-inner:after {
content: "OFF";
padding-right: 10px;
background-color: #EEEEEE; color: #999999;
text-align: right;
}
.onoffswitch-switch {
display: block; width: 18px; margin: 5px;
background: #FFFFFF;
position: absolute; top: 0; bottom: 0;
right: 46px;
border: 2px solid #C2C2C2; border-radius: 20px;
transition: all 0.3s ease-in 0s;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-inner {
margin-left: 0;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-switch {
right: 0px;
}我尝试过onClick事件，但每次我单击它(逻辑上)它都会触发代码(如果多次单击，则会触发多次)，最完美的情况是，一个事件将为真并触发代码，在第二次单击时，它将执行其他操作。
我不知道这是否会非常简单，我的大脑很疲惫，没有正确地思考，但任何帮助都会有帮助！
回答 1
Stack Overflow用户
回答已采纳
发布于 2019-04-25 07:36:16
添加click事件处理程序是正确的方法。只需查看checkbox的checked属性，即可了解按钮的状态(开/关)。
document.getElementById("myonoffswitch").addEventListener("click", function(){
// Test the state of the checkbox and act accordingly
if(this.checked){
console.log("ON");
} else {
console.log("OFF");
}
});.onoffswitch {
position: relative; width: 78px;
-webkit-user-select:none; -moz-user-select:none; -ms-user-select: none;
}
.onoffswitch-checkbox {
display: none;
}
.onoffswitch-label {
display: block; overflow: hidden; cursor: pointer;
border: 2px solid #C2C2C2; border-radius: 20px;
}
.onoffswitch-inner {
display: block; width: 200%; margin-left: -100%;
transition: margin 0.3s ease-in 0s;
}
.onoffswitch-inner:before, .onoffswitch-inner:after {
display: block; float: left; width: 50%; height: 28px; padding: 0; line-height: 28px;
font-size: 14px; color: white; font-family: Trebuchet, Arial, sans-serif; font-weight: bold;
box-sizing: border-box;
}
.onoffswitch-inner:before {
content: "ON";
padding-left: 10px;
background-color: #5C7FE3; color: #FFFFFF;
}
.onoffswitch-inner:after {
content: "OFF";
padding-right: 10px;
background-color: #EEEEEE; color: #999999;
text-align: right;
}
.onoffswitch-switch {
display: block; width: 18px; margin: 5px;
background: #FFFFFF;
position: absolute; top: 0; bottom: 0;
right: 46px;
border: 2px solid #C2C2C2; border-radius: 20px;
transition: all 0.3s ease-in 0s;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-inner {
margin-left: 0;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-switch {
right: 0px;
}<div class="onoffswitch">
<input type="checkbox" name="onoffswitch" class="onoffswitch-checkbox" id="myonoffswitch">
<label class="onoffswitch-label" for="myonoffswitch">
<span id="switch-inner" class="onoffswitch-inner"></span>
<span class="onoffswitch-switch"></span>
</label>
</div>
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原文链接：
https://stackoverflow.com/questions/55839866
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