System.out.print不显示客户数据
System.out.print不显示客户数据
提问于 2019-05-12 23:52:11
我正在编写一个客户端数据库。我想根据客户编号知道客户的姓名和家乡。当我输入2号时，我想看到爱丁堡的Arya Stark，当我输入1号时，我想看到伦敦的Jon Snow。为什么我的程序不工作？如何解决这个问题？
package app;
import java.util.Scanner;
class Person {
String name;
String homeCity;
int customerNumber;
}
public class Customers {
static Scanner input = new Scanner(System.in);
public static void main(String[] args) {
String name;
System.out.print ("Give a customer card number: ");
name = input.next();
Person person1 = new Person();
person1.name = "Jon Snow";
person1.homeCity = "London";
person1.customerNumber = 1;
Person person2 = new Person();
person2.name = "Arya Stark";
person2.homeCity = "Edinburgh";
person2.customerNumber = 2;
System.out.println();
}
}回答 1
Stack Overflow用户
回答已采纳
发布于 2019-05-13 01:11:49
这应该是可行的：
class Person {
private String name;
private String homeCity;
private int customerNumber;
public Person(String name, String homeCity, int customerNumber) {
this.name = name;
this.homeCity = homeCity;
this.customerNumber = customerNumber;
}
public boolean isMatch(int num) {
return num == customerNumber;
}
@Override
public String toString() {
return name + " from " + homeCity;
}
}import java.util.Scanner;
class Main {
private static Scanner input = new Scanner(System.in);
public static void main(String[] args) {
Person person1 = new Person("Jon Snow", "London", 1);
Person person2 = new Person("Arya Stark", "Edinburgh", 2);
while(true) {
System.out.print("Give a customer card number: ");
String num = input.next();
if (person1.isMatch(Integer.parseInt(num))) {
System.out.println(person1);
} else if (person2.isMatch(Integer.parseInt(num))) {
System.out.println(person2);
} else {
System.out.println("Not found");
}
}
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/56100941
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