我正在做的是从一个.txt
文件中加载一个URL列表,该文件正常工作:
def load_urls():
try:
input_file = open("filters\\inputLinks.txt", "r")
for each_line in input_file:
link = each_line.rstrip('\n')
identify_platform(link)
except Exception as e:
print("Loading URLs error: ", e)
def identify_platform(link):
try:
SEARCH_FOR = ["/node/", "/itemlist/"]
if any(found in link for found in SEARCH_FOR):
print(link)
except Exception as e:
print("Identifying URLs error: ", e)
if __name__ == "__main__":
load_urls()
然后,它将检查URL是否包含SEARCH_FOR
数组元素之一。如果有,我们就把它打印到屏幕上。是否还可以使用下面的命令打印出找到的哪个数组元素:
print(element_found + "|" + link)
发布于 2019-05-26 00:31:44
不使用any
操作符,只需执行列表理解即可。注意:如果两个搜索项都在目标中,这可能会给出两个结果。
matches = [(item, link) for item in SEARCH_FOR if item in link]
for match in matches:
print(match[0] + '|' + match[1])
发布于 2019-05-26 00:30:16
如果您可以将其分隔为多行,使其更具可读性:
for found in SEARCH_FOR:
if found in link:
print(found + '|' + link)
https://stackoverflow.com/questions/56306648
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