遍历表中每个单元格的内容并检索/存储其值的最佳方法是什么?使用我目前的方法,我无法在变量val
中获取表的设置值
示例表:
Set ws = ActiveSheet
ws.Name = "sheet1"
Set tbl = ws.ListObjects("tblBor")
Application.Calculation = xlCalculationManual
ws.Calculate
With tbl.Sort
.SortFields.Clear
.SortFields.Add Key:=Range("tblBor[ID]"), SortOn:=xlSortOnValues, Order:=xlAscending
.Header = xlYes
.Apply
End With
Set rng = Range(tbl)
rows = tbl.Range.rows.Count
Columns = tbl.Range.Columns.Count
For iter = 1 To rows
For col = 1 To Columns
'Iterate through each row by each column
'val = tbl.DataBodyRange(iter, col).Value
Next col
Next iter
发布于 2019-06-06 03:14:13
你有一个ListObject
,使用它的API!ListRows
和ListColumns
是对象集合,迭代它们的最快方法是by several orders of magnitude,使用For Each
循环:
Dim tblRow As ListRow
For Each tblRow In tbl.ListRows
Dim tblCol As ListColumn
For Each tblCol In tbl.ListColumns
Debug.Print "(" & tblRow.Index & "," & tblCol.Index & "): " & tblRow.Range(tblCol.Index).Value
Next
Next
如果您只想将内容收集到一个二维值的数组中,则不需要迭代任何内容-只需获取DataBodyRange
并将其视为任何其他“常规”Range
Dim contents As Variant
contents = tbl.DataBodyRange.Value
如果您稍后需要迭代2D变量数组,最快的方法(与上面的源代码相同)是For...Next
循环:
Dim currentRow As Long
For currentRow = LBound(contents, 1) To UBound(contents, 1)
Dim currentCol As Long
For currentCol = LBound(contents, 2) To UBound(contents, 2)
Debug.Print "(" & currentRow & "," & currentCol & "): " & contents(currentRow, currentCol)
Next
Next
https://stackoverflow.com/questions/56465950
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