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社区首页 >问答首页 >必须告诉用户需要多少次翻转才能将B更改为A的代码无法正常工作

必须告诉用户需要多少次翻转才能将B更改为A的代码无法正常工作
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Stack Overflow用户
提问于 2019-06-09 14:21:32
回答 1查看 100关注 0票数 0

我写了一些代码,其中我必须编写一个程序,要求用户要一排煎饼,它们可以是字母A或B,其中代码必须告诉用户需要多少次翻转才能制作所有的煎饼A,其中用户必须输入一次可以翻转多少个煎饼。如果煎饼不能翻转,并且全是字母_A_s,那么代码必须输出This couldn't be done. Would you like to try again?

代码当前输出以下内容:

Enter the row and the side of the pancakes A/B): BBBB
How many pancakes can flipped at one time? 2
It took 0 flips.
Would you like to run this program again? 

其中,它应该输出以下内容:

Enter the row and the side of the pancakes (A/B): BBBB
How many pancakes can flipped at one time? 2

而且它不应该告诉用户他们是否想再玩一次,因为煎饼还没有完全翻到A。

我的代码如下:

i = True
flips = 0

while i == True:
    pancakes = list(input('Enter the row and the side of the pancakes (A/B): '))
    flipper = int(input('How many pancakes can be flipped at one time? '))

    i = False
    if 'O' in pancakes:
        flips = flips + 1
        for x in range(flipper):
            if pancakes[x] == 'A':
                pancakes[x] = 'B'
                pancakes = (''.join(pancakes))

    if flips == 1:
        print('It took 1 flip.')
        play = input("Would you like to run this program again? ")
        if play == 'Yes' or play == 'yes' or play == 'Y' or play == 'y':
            i = True
        else:
            quit()

    if flips == 0:
        print('It took', flips, 'flip.')
        play = input("Would you like to run this program again? ")
        if play == 'Yes' or play == 'yes' or play == 'Y' or play == 'y':
            i = True
        else:
            quit()

    if flips > 1:
        print('It took', flips, 'flip.')
        play = input("Would you like to run this program again? ")
        if play == 'Yes' or play == 'yes' or play == 'Y' or play == 'y':
            i = True
        else:
            quit()

代码的一个问题是它目前不能正确地输出正确的翻转次数。

谢谢。

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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56512446

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