首页
学习
活动
专区
工具
TVP
发布
社区首页 >问答首页 >注意:未定义的变量:第16行的/Applications/XAMPP/xamppfiles/htdocs/menthor/login.php中的电子邮件

注意:未定义的变量:第16行的/Applications/XAMPP/xamppfiles/htdocs/menthor/login.php中的电子邮件
EN

Stack Overflow用户
提问于 2019-06-19 08:03:40
回答 2查看 167关注 0票数 0

当使用用户名登录应用程序时,不会使用电子邮件,因此会抛出以下错误,反之亦然“注意:未定义的索引:第16行/Applications/XAMPP/xamppfiles/htdocs/menthor/login.php中的电子邮件”

我尝试将产生错误的代码行放入条件中,但这些努力证明是徒劳的Login.php文件(与错误相关的部分)

// STEP 1. Receive data / info paassed to current file
if ((empty($_REQUEST['username']) || empty($_REQUEST['password'])) && (empty($_REQUEST['email']) || empty($_REQUEST['password']))) {
    $return['status'] = '400';
    $return['message'] = 'Missing requird information';
    echo json_encode($return);
    return;

} 


// securing received info / data from hackers or injections
$email = htmlentities($_REQUEST['email']);
$username = htmlentities($_REQUEST['username']);
$password = htmlentities($_REQUEST['password']);

// STEP 2. Establish connection with the server
require('secure/access.php');
$access = new access('localhost' , 'root', '' , 'menthor');
$access->connect();

// STEP 3. Check existence of the user. Try to fetch the user with the same email address
// STEP 3. Check availability of the login/user information
$username_aval = $access->selectUser_Username($username);
$email_aval = $access->selectUser_Email($email);

//$return = array();

// user is found
if ($username_aval) {

    // Get encrypted password and salt from the server for validation
    $encryptedPassword = $username_aval['password'];
    $salt = $username_aval['salt'];

    if ($encryptedPassword == sha1($password . $salt)) {

        $return['status'] = '200';
        $return['message'] = 'Successfully Logged In';
        $return['id'] = $username_aval['id'];
        $return['username'] = $username_aval['username'];
        $return['email'] = $username_aval['email'];
        $return['fullName'] = $username_aval['fullName'];
        $return['lastName'] = $username_aval['lastName'];
        $return['birthday'] = $username_aval['birthday'];
        $return['gender'] = $username_aval['gender'];
        $return['cover'] = $username_aval['cover'];
        $return['ava'] = $username_aval['ava'];
        $return['bio'] = $username_aval['bio'];
        $return['allow_follow'] = $username_aval['allow_follow'];

    } else {

        // In event that encrypted password and salt does not match
        $return['status'] = '201';
        $return['message'] = 'Password do not match';

    }

} else if ($email_aval) {

    // Get encrypted password and salt from the server for validation
    $encryptedPassword = $email_aval['password'];
    $salt = $email_aval['salt'];

    if ($encryptedPassword == sha1($password . $salt)) {

        $return['status'] = '200';
        $return['message'] = 'Successfully Logged In';
        $return['id'] = $email_aval['id'];
        $return['username'] = $email_aval['username'];
        $return['email'] = $email_aval['email'];
        $return['fullName'] = $email_aval['fullName'];
        $return['lastName'] = $email_aval['lastName'];
        $return['birthday'] = $email_aval['birthday'];
        $return['gender'] = $email_aval['gender'];
        $return['cover'] = $email_aval['cover'];
        $return['ava'] = $email_aval['ava'];
        $return['bio'] = $email_aval['bio'];
        $return['allow_follow'] = $email_aval['allow_follow'];

    } else {

        // In event that encrypted password and salt does not match
        $return['status'] = '202';
        $return['message'] = 'Password do not match';

    } 
}else {

        // In event that user is not found
        $return['status'] = '403';
        $return['message'] = 'User was not found';

}

// stop connection with server
$access->disconnect();

// pass info as JSON
echo json_encode($return);

Access.php文件(与错误相关的部分)将根据收到的电子邮件尝试选择数据库中的任何值

public function  selectUser_Email($email) {

    // array to store full user related information with the logic: key=>Value
    $returnArray = array();

    // SQL Language / Commande to be sent to the server
    // SELECT * FROM users WHERE email='rondell@gmail.com'
    $sql = "SELECT * FROM users WHERE email='" . $email . "'";

    // executing query via already established connection with the server
    $result = $this->conn->query($sql);

    // result isn't zero and it has least 1 row / value / result
    if ($result != null && (mysqli_num_rows($result)) >= 1) {

        // converting to JSON
        $row = $result->fetch_array(MYSQLI_ASSOC);

        // assign fetched row to ReturnArray
        if (!empty($row)) {
            $returnArray = $row;
        }
    }

    // throw back returnArray
    return $returnArray;
}

// Will try to select any value in the database based on received Email
public function  selectUser_Username($username) {

    // array to store full user related information with the logic: key=>Value
    $returnArray = array();

    // SQL Language / Commande to be sent to the server
    // SELECT * FROM users WHERE username='rondell'
    $sql = "SELECT * FROM users WHERE username='" . $username . "'";

    // executing query via already established connection with the server
    $result = $this->conn->query($sql);

    // result isn't zero and it has least 1 row / value / result
    if ($result != null && (mysqli_num_rows($result)) >= 1) {

        // converting to JSON
        $row = $result->fetch_array(MYSQLI_ASSOC);

        // assign fetched row to ReturnArray
        if (!empty($row)) {
            $returnArray = $row;
        }
    }

    // throw back returnArray
    return $returnArray;
}

通过web服务器登录时的当前结果

Notice: Undefined index: email in /Applications/XAMPP/xamppfiles/htdocs/menthor/login.php on line 16
{"status":"200","message":"Successfully Logged In","id":"44","username":"rondell","email":"rondell@gmail.com","fullName":"rondell","lastName":"","birthday":"","gender":"","cover":"","ava":"","bio":"","allow_follow":"1"}

预期结果

{"status":"200","message":"Successfully Logged In","id":"44","username":"rondell","email":"rondell@gmail.com","fullName":"rondell","lastName":"","birthday":"","gender":"","cover":"","ava":"","bio":"","allow_follow":"1"}
EN

回答 2

Stack Overflow用户

发布于 2019-06-19 10:01:12

使用电子邮件作为对象,或者您可以转储请求并查看发生了什么

票数 0
EN

Stack Overflow用户

发布于 2019-06-20 08:17:56

经过深思熟虑之后,解决方案变得相当简单……我只需要简单地创建两个login.php文件...一个专用于使用用户名和密码登录的用户,另一个专用于使用电子邮件和password...Cheers登录的用户

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56658478

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档