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社区首页 >问答首页 >如何使用map()、reduce()和filter()来简化javascript嵌套数组?

如何使用map()、reduce()和filter()来简化javascript嵌套数组?
EN

Stack Overflow用户
提问于 2019-06-26 05:24:54
回答 3查看 1.3K关注 0票数 2

首先,我是一个Javascript,ES6等的新手,我来自Java背景。我有一个复杂的javascript数组结构(示例如下),我试图将这个数组转换成一个映射(类似于Java的方法,键值对之类的东西),key是权限名称(例如,关于下面的javascript数组示例,KEY-1,KEY-2,KEY-3,KEY-4,KEY-5 )而value是实际权限的逗号分隔值。我可以通过在嵌套数组中循环b来实现,但是循环是我在这里试图避免的,并且希望使用map()/reduce()/filter()

以下是地图应如何包含数据的示例。由于KEY-2在两个数组中都存在,它们将被重写为一个(这是非常好的)

代码语言:javascript
复制
KEY-1 = ["Roles.Create","Roles.Edit"]
KEY-2 = ["API-Admin.Create","API-Admin.Edit","API-Admin.Read"]
KEY-3 = ["Roles.Create","Roles.Edit"]
KEY-4 = ["Users.Read"]      
KEY-5 = ["Roles.Create","Roles.Edit"]

Javascript数组

代码语言:javascript
复制
const teamArr = [
  {
    "name":"Team1",
    "accountId":"Billing",
    "teamId":"12345",
    "permissions": {
        "KEY-1": [
            "Roles.Create",
            "Roles.Edit"
        ],
        "KEY-2": [
            "API-Admin.Create",
            "API-Admin.Edit",
            "API-Admin.Read"
        ],
        "KEY-3": [
          "Roles.Create",
          "Roles.Edit"
        ]
     }
   },
   {
     "name":"Team2",
     "accountId":"Sales",
     "teamId":"6789",
     "permissions": {
         "KEY-4": [
             "Users.Read"
         ],
         "KEY-2": [
            "API-Admin.Create",
            "API-Admin.Edit",
            "API-Admin.Read"
        ],
         "KEY-5": [
           "Roles.Create",
           "Roles.Edit"
         ]
      }
   }
]

KEY-1、KEY-2、KEY-3、KEY-4、KEY-5等都是动态生成的,所以我不能将这些KEY名称硬编码到我的代码中(如KEY-1、KEY-2等)。

我遵循了这篇文章,下面是我尝试过的,但我想,我正在努力在一个复杂的https://www.freecodecamp.org/news/15-useful-javascript-examples-of-map-reduce-and-filter-74cbbb5e0a1f/数组上正确地使用/reduce()。我更喜欢普通的Javascript/ES6解决方案(没有JQuery请)。

代码语言:javascript
复制
const sorted = test.sort((a, b) => a.permissions - b.permissions);
// Using reduce:
dict = sorted.reduce(
    (dict, el, index) => (dict[el.permissions] = sorted.length - index, dict),
    {}
);

console.log(dict)

这里的任何帮助都将受到高度的感谢。谢谢

EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2019-06-26 08:31:56

因为您不需要担心其他键/值,所以首先需要创建一个包含所有permissions对象的数组。然后从该数组中提取属性,并使用集合保持数组的唯一性:

代码语言:javascript
复制
const teamArr = [{"name":"Team1","accountId":"Billing","teamId":"12345","permissions":{"KEY-1":["Roles.Create","Roles.Edit"],"KEY-2":["API-Admin.Create","API-Admin.Edit","API-Admin.Read"],"KEY-3":["Roles.Create","Roles.Edit"]}},{"name":"Team2","accountId":"Sales","teamId":"6789","permissions":{"KEY-4":["Users.Read"],"KEY-2":["API-Admin.Create","API-Admin.Edit","API-Admin.Read"],"KEY-5":["Roles.Create","Roles.Edit"]}}];
const res = teamArr.flatMap(({ permissions }) => Object.entries(permissions)).reduce((a, [k, v]) => ((a[k] = [...new Set(((a[k] = a[k] || []).push(...v), a[k]))], a)), {});
console.log(res);
代码语言:javascript
复制
.as-console-wrapper { max-height: 100% !important; top: auto; }

更详细的版本:

代码语言:javascript
复制
const teamArr = [{"name":"Team1","accountId":"Billing","teamId":"12345","permissions":{"KEY-1":["Roles.Create","Roles.Edit"],"KEY-2":["API-Admin.Create","API-Admin.Edit","API-Admin.Read"],"KEY-3":["Roles.Create","Roles.Edit"]}},{"name":"Team2","accountId":"Sales","teamId":"6789","permissions":{"KEY-4":["Users.Read"],"KEY-2":["API-Admin.Create","API-Admin.Edit","API-Admin.Read"],"KEY-5":["Roles.Create","Roles.Edit"]}}];
const permissions = teamArr.map(({ permissions }) => permissions);
const res = permissions.flatMap(Object.entries).reduce((a, [k, v]) => {
  a[k] = a[k] || [];
  a[k].push(...v);
  a[k] = [...new Set(a[k])];
  return a;
}, {});
console.log(res);
代码语言:javascript
复制
.as-console-wrapper { max-height: 100% !important; top: auto; }

票数 2
EN

Stack Overflow用户

发布于 2019-06-26 05:48:12

您可以使用flatMapreduce的组合来完成(尽管flatMap还不是所有浏览器都支持):

代码语言:javascript
复制
const teamArr = [{
    "name": "Team1",
    "accountId": "Billing",
    "teamId": "12345",
    "permissions": {
      "KEY-1": [
        "Roles.Create",
        "Roles.Edit"
      ],
      "KEY-2": [
        "API-Admin.Create",
        "API-Admin.Edit",
        "API-Admin.Read"
      ],
      "KEY-3": [
        "Roles.Create",
        "Roles.Edit"
      ]
    }
  },
  {
    "name": "Team2",
    "accountId": "Sales",
    "teamId": "6789",
    "permissions": {
      "KEY-4": [
        "Users.Read"
      ],
      "KEY-2": [
        "API-Admin.Create",
        "API-Admin.Edit",
        "API-Admin.Read"
      ],
      "KEY-5": [
        "Roles.Create",
        "Roles.Edit"
      ]
    }
  }
]

const result = teamArr
  .flatMap(t => Object.entries(t.permissions))
  .reduce((acc, [key, permissions]) => {
    acc[key] = acc[key] || [];
    acc[key].push(...permissions.filter(p => !acc[key].includes(p)));
    return acc;
  }, {});
  
console.log(result);

如果键的权限数组可能非常大,还可以考虑在累加器中的每个键旁边使用Set

票数 2
EN

Stack Overflow用户

发布于 2019-06-26 05:42:52

代码语言:javascript
复制
const teamArr = [
  {
    "name":"Team1",
    "accountId":"Billing",
    "teamId":"12345",
    "permissions": {
        "KEY-1": [
            "Roles.Create",
            "Roles.Edit"
        ],
        "KEY-2": [
            "API-Admin.Create",
            "API-Admin.Edit",
            "API-Admin.Read"
        ],
        "KEY-3": [
          "Roles.Create",
          "Roles.Edit"
        ]
     }
   },
   {
     "name":"Team2",
     "accountId":"Sales",
     "teamId":"6789",
     "permissions": {
         "KEY-4": [
             "Users.Read"
         ],
         "KEY-2": [
            "API-Admin.Create",
            "API-Admin.Edit",
            "API-Admin.Read"
        ],
         "KEY-5": [
           "Roles.Create",
           "Roles.Edit"
         ]
      }
   }
];



function extractPermissions(obj) {
    const perms = {};
    obj.forEach(entry => {
        if (!entry['permissions']) {
            return;
        }
        Object.keys(entry.permissions).forEach(key => {
            if (!perms[key]) {
                perms[key] = [];
            }
            entry.permissions[key].forEach(value => {
                if (!perms[key].some(val => val === value)) {
                    perms[key].push(value);
                }
            });
        });
    });
    return perms;
}
console.log(JSON.stringify(extractPermissions(teamArr), null, 2));
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56762203

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