blocks|key|1544205|text|最好的方法是使用算法remove_if和isspace：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1544206|remove_if(str.begin(),+str.end(),+isspace);|code-block|syntax|javascript|1544207|现在算法本身不能改变容器(只能修改值)，所以它实际上打乱了值，并返回一个指针，指向现在应该结束的位置。所以我们必须调用string::erase来实际修改容器的长度：|1544208|str.erase(remove_if(str.begin(),+str.end(),+isspace),+str.end());|1544209|我们还应该注意到，remove_if最多只能复制一份数据。下面是一个示例实现：|1544210|template<typename+T,+typename+P>
T+remove_if(T+beg,+T+end,+P+pred)
{
++++T+dest+=+beg;
++++for+(T+itr+=+beg;itr+!=+end;+%2B%2Bitr)
++++++++if+(!pred(*itr))
++++++++++++*(dest%2B%2B)+=+*itr;
++++return+dest;
}|1544211|entityMap|0|LINK|mutability|MUTABLE|url|http://en.cppreference.com/w/cpp/algorithm/remove^0|A|9|A|9|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|18|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|19|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

The best thing to do is to use the algorithm <a href="http://en.cppreference.com/w/cpp/algorithm/remove" rel="noreferrer"><code>remove_if</code></a> and isspace:

<pre><code>remove_if(str.begin(), str.end(), isspace);
</code></pre>

Now the algorithm itself can't change the container(only modify the values), so it actually shuffles the values around and returns a pointer to where the end now should be. So we have to call string::erase to actually modify the length of the container:

<pre><code>str.erase(remove_if(str.begin(), str.end(), isspace), str.end());
</code></pre>

We should also note that remove_if will make at most one copy of the data. Here is a sample implementation:

<pre><code>template&lt;typename T, typename P&gt;
T remove_if(T beg, T end, P pred)
{
 T dest = beg;
 for (T itr = beg;itr != end; ++itr)
 if (!pred(*itr))
 *(dest++) = *itr;
 return dest;
}
</code></pre>

blocks|key|1758976|text|std::string::iterator+end_pos+=+std::remove(str.begin(),+str.end(),+'+');
str.erase(end_pos,+str.end());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1758977|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>std::string::iterator end_pos = std::remove(str.begin(), str.end(), ' ');
str.erase(end_pos, str.end());
</code></pre>

blocks|key|1544029|text|来自gamedev|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1544030|string.erase(std::remove_if(string.begin(),+string.end(),+std::isspace),+string.end());|code-block|syntax|javascript|1544031|entityMap|0|LINK|mutability|MUTABLE|url|http://www.gamedev.net/community/forums/topic.asp?topic_id=359650^0|2|7|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

From <a href="http://www.gamedev.net/community/forums/topic.asp?topic_id=359650" rel="noreferrer">gamedev</a>

<pre><code>string.erase(std::remove_if(string.begin(), string.end(), std::isspace), string.end());
</code></pre>

blocks|key|1759157|text|你能使用Boost字符串Algo吗？http://www.boost.org/doc/libs/1_35_0/doc/html/string_algo/usage.html#id1290573|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1759158|erase_all(str,+"+");+|code-block|syntax|javascript|1759159|entityMap|0|LINK|mutability|MUTABLE|url|http://www.boost.org/doc/libs/1_35_0/doc/html/string_algo/usage.html#id1290573^0|I|26|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Can you use Boost String Algo? <a href="http://www.boost.org/doc/libs/1_35_0/doc/html/string_algo/usage.html#id1290573" rel="noreferrer">http://www.boost.org/doc/libs/1_35_0/doc/html/string_algo/usage.html#id1290573</a>

<pre><code>erase_all(str, " "); 
</code></pre>

blocks|key|1544412|text|您可以使用此解决方案删除字符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1544413|#include+<algorithm>
#include+<string>
using+namespace+std;

str.erase(remove(str.begin(),+str.end(),+char_to_remove),+str.end());|code-block|syntax|javascript|1544414|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use this solution for removing a char:

<pre><code>#include &lt;algorithm&gt;
#include &lt;string&gt;
using namespace std;

str.erase(remove(str.begin(), str.end(), char_to_remove), str.end());
</code></pre>

blocks|key|1759242|text|对于修剪，请使用boost+string+algorithms|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1759243|#include+<boost/algorithm/string.hpp>

using+namespace+std;
using+namespace+boost;

//+...

string+str1("+hello+world!+");
trim(str1);++++++//+str1+==+"hello+world!"|code-block|syntax|javascript|1759244|entityMap|0|LINK|mutability|MUTABLE|url|http://www.boost.org/doc/html/string_algo.html^0|8|N|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

For trimming, use <a href="http://www.boost.org/doc/html/string_algo.html" rel="noreferrer">boost string algorithms</a>:

<pre><code>#include &lt;boost/algorithm/string.hpp&gt;

using namespace std;
using namespace boost;

// ...

string str1(" hello world! ");
trim(str1); // str1 == "hello world!"
</code></pre>

blocks|key|1544353|text|string+replaceinString(std::string+str,+std::string+tofind,+std::string+toreplace)
{
++++++++size_t+position+=+0;
++++++++for+(+position+=+str.find(tofind);+position+!=+std::string::npos;+position+=+str.find(tofind,position)+)
++++++++{
++++++++++++++++str.replace(position+,1,+toreplace);
++++++++}
++++++++return(str);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1544354|使用它：|unstyled|1544355|string+replace+=+replaceinString(thisstring,+"+",+"%2520");
string+replace2+=+replaceinString(thisstring,+"+",+"-");
string+replace3+=+replaceinString(thisstring,+"+",+"%2B");|1544356|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>string replaceinString(std::string str, std::string tofind, std::string toreplace)
{
 size_t position = 0;
 for ( position = str.find(tofind); position != std::string::npos; position = str.find(tofind,position) )
 {
 str.replace(position ,1, toreplace);
 }
 return(str);
}
</code></pre>

use it:

<pre><code>string replace = replaceinString(thisstring, " ", "%20");
string replace2 = replaceinString(thisstring, " ", "-");
string replace3 = replaceinString(thisstring, " ", "+");
</code></pre>

blocks|key|1759395|text|如果你想用一个简单的宏来做到这一点，这里有一个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1759396|#define+REMOVE_SPACES(x)+x.erase(std::remove(x.begin(),+x.end(),+'+'),+x.end())|code-block|syntax|javascript|1759397|当然，这假设您已经完成了#include+<string>。|offset|length|style|CODE|1759398|这样叫它：|1759399|std::string+sName+=+"+Example+Name+";
REMOVE_SPACES(sName);
printf("%25s",sName.c_str());+//+requires+#include+<stdio.h>|1759400|entityMap^0|0|0|C|H|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

If you want to do this with an easy macro, here's one:
<pre><code>#define REMOVE_SPACES(x) x.erase(std::remove(x.begin(), x.end(), ' '), x.end())
</code></pre>
This assumes you have done <code>#include &lt;string&gt;</code> of course.
Call it like so:
<pre class="lang-cpp prettyprint-override"><code>std::string sName = &quot; Example Name &quot;;
REMOVE_SPACES(sName);
printf(&quot;%s&quot;,sName.c_str()); // requires #include &lt;stdio.h&gt;
</code></pre>

blocks|key|1544678|text|在C%2B%2B20中，你可以使用免费函数std::erase|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1544679|std::string+str+=+"+Hello+World++!";
std::erase(str,+'+');|code-block|syntax|javascript|1544680|完整示例：|1544681|#include<string>
#include<iostream>

int+main()+{
++++std::string+str+=+"+Hello+World++!";
++++std::erase(str,+'+');
++++std::cout+<<+"%7C"+<<+str+<<"%7C";
}|1544682|我打印%7C，这样很明显，开头的空格也被删除了。|1544683|注意:此操作仅删除空格，而不删除所有其他可能被视为空格的字符，请参见https://en.cppreference.com/w/cpp/string/byte/isspace|offset|length|1544684|entityMap|0|LINK|mutability|MUTABLE|url|https://en.cppreference.com/w/cpp/string/byte/isspace^0|0|0|0|0|0|Y|1H|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|13|8|@]|9|@$O|14|P|15|1|16]]|A|$]]|$1|Q|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

In C++20 you can use free function std::erase

<pre><code>std::string str = " Hello World !";
std::erase(str, ' ');
</code></pre>

Full example:

<pre><code>#include&lt;string&gt;
#include&lt;iostream&gt;

int main() {
 std::string str = " Hello World !";
 std::erase(str, ' ');
 std::cout &lt;&lt; "|" &lt;&lt; str &lt;&lt;"|";
}
</code></pre>

I print | so that it is obvious that space at the begining is also removed.

note: this removes only the space, not every other possible character that may be considered whitespace, see <a href="https://en.cppreference.com/w/cpp/string/byte/isspace" rel="nofollow noreferrer">https://en.cppreference.com/w/cpp/string/byte/isspace</a>

blocks|key|1759458|text|我使用下面的工作很长时间了-不确定它的复杂性。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1759459|s.erase(std::unique(s.begin(),s.end(),[](char+s,char+f){return+(f=='+'%7C%7Cs=='+');}),s.end());|offset|length|style|CODE|1759460|当您想要删除字符'+'和一些例如-时，可以使用|1759461|s.erase(std::unique(s.begin(),s.end(),[](char+s,char+f){return+((f=='+'%7C%7Cs=='+')%7C%7C(f=='-'%7C%7Cs=='-'));}),s.end());|1759462|同样，如果要删除的字符数不是1，只需增加%7C%7C|1759463|但是，正如其他人所提到的，erase+remove这个习惯用法看起来也不错。|1759464|entityMap^0|0|0|2K|0|8|3|G|1|0|0|34|0|K|2|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|V|8|@$D|W|E|X|F|G]|$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|10|8|@$D|11|E|12|F|G]]|9|@]|A|$]]|$1|L|3|M|5|6|7|13|8|@$D|14|E|15|F|G]]|9|@]|A|$]]|$1|N|3|O|5|6|7|16|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|Q|$]]

I used the below work around for long - not sure about its complexity.

<code>s.erase(std::unique(s.begin(),s.end(),[](char s,char f){return (f==' '||s==' ');}),s.end());</code>

when you wanna remove character <code>' '</code> and some for example <code>-</code> use

<code>s.erase(std::unique(s.begin(),s.end(),[](char s,char f){return ((f==' '||s==' ')||(f=='-'||s=='-'));}),s.end());</code>

likewise just increase the <code>||</code> if number of characters you wanna remove is not 1

but as mentioned by others the erase remove idiom also seems fine.

blocks|key|1759523|text|string+removeSpaces(string+word)+{
++++string+newWord;
++++for+(int+i+=+0;+i+<+word.length();+i%2B%2B)+{
++++++++if+(word[i]+!=+'+')+{
++++++++++++newWord+%2B=+word[i];
++++++++}
++++}

++++return+newWord;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1759524|这段代码基本上接受一个字符串，并遍历其中的每个字符。然后检查该字符串是否为空格，如果不是，则将该字符添加到新字符串中。|unstyled|1759525|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>string removeSpaces(string word) {
 string newWord;
 for (int i = 0; i &lt; word.length(); i++) {
 if (word[i] != ' ') {
 newWord += word[i];
 }
 }

 return newWord;
}
</code></pre>

This code basically takes a string and iterates through every character in it. It then checks whether that string is a white space, if it isn't then the character is added to a new string.

blocks|key|1759619|text|删除所有whitespace+characters，例如制表符和换行符(C%2B%2B11)：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1759620|string+str+=+"+\n+AB+cd+\t+efg\v\n";
str+=+regex_replace(str,regex("\\s"),"");|code-block|syntax|javascript|1759621|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikipedia.org/wiki/Category:Whitespace^0|4|L|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Removes all <a href="https://en.wikipedia.org/wiki/Category:Whitespace" rel="nofollow noreferrer">whitespace characters</a> such as tabs and line breaks (C++11):

<pre><code>string str = " \n AB cd \t efg\v\n";
str = regex_replace(str,regex("\\s"),"");
</code></pre>

blocks|key|1544735|text|++string+str+=+"2C+F4+32+3C+B9+DE";
++str.erase(remove(str.begin(),str.end(),'+'),str.end());
++cout+<<+str+<<+endl;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1544736|输出:+2CF4323CB9DE|unstyled|1544737|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code> string str = "2C F4 32 3C B9 DE";
 str.erase(remove(str.begin(),str.end(),' '),str.end());
 cout &lt;&lt; str &lt;&lt; endl;
</code></pre>

output: 2CF4323CB9DE

blocks|key|1544776|text|只是为了好玩，因为其他答案比这个要好得多。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1544777|#include+<boost/hana/functional/partial.hpp>
#include+<iostream>
#include+<range/v3/range/conversion.hpp>
#include+<range/v3/view/filter.hpp>
int+main()+{
++++using+ranges::to;
++++using+ranges::views::filter;
++++using+boost::hana::partial;
++++auto+const&+not_space+=+partial(std::not_equal_to<>{},+'+');
++++auto+const&+to_string+=+to<std::string>;

++++std::string+input+=+"2C+F4+32+3C+B9+DE";
++++std::string+output+=+input+%7C+filter(not_space)+%7C+to_string;
++++assert(output+==+"2CF4323CB9DE");
}|code-block|syntax|javascript|1544778|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just for fun, as other answers are much better than this.
<pre class="lang-cpp prettyprint-override"><code>#include &lt;boost/hana/functional/partial.hpp&gt;
#include &lt;iostream&gt;
#include &lt;range/v3/range/conversion.hpp&gt;
#include &lt;range/v3/view/filter.hpp&gt;
int main() {
 using ranges::to;
 using ranges::views::filter;
 using boost::hana::partial;
 auto const&amp; not_space = partial(std::not_equal_to&lt;&gt;{}, ' ');
 auto const&amp; to_string = to&lt;std::string&gt;;

 std::string input = &quot;2C F4 32 3C B9 DE&quot;;
 std::string output = input | filter(not_space) | to_string;
 assert(output == &quot;2CF4323CB9DE&quot;);
}
</code></pre>

blocks|key|1759743|text|我创建了一个函数，用于删除字符串两端的空格。例如"++Hello+World+++"，将被转换为"Hello+world"。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1759744|这类似于python中经常使用的strip、lstrip和rstrip函数。|1759745|string+strip(string+str)+{
++++while+(str[str.length()+-+1]+==+'+')+{
++++++++str+=+str.substr(0,+str.length()+-+1);
++++}
++++while+(str[0]+==+'+')+{
++++++++str+=+str.substr(1,+str.length()+-+1);
++++}
++++return+str;
}

string+lstrip(string+str)+{
++++while+(str[0]+==+'+')+{
++++++++str+=+str.substr(1,+str.length()+-+1);
++++}
++++return+str;
}

string+rstrip(string+str)+{
++++while+(str[str.length()+-+1]+==+'+')+{
++++++++str+=+str.substr(0,+str.length()+-+1);
++++}
++++return+str;
}|code-block|syntax|javascript|1759746|entityMap^0|O|I|1C|D|0|G|5|M|6|T|6|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|N|$]]

I created a function, that removes the white spaces from the either ends of string. Such as
<code>&quot; Hello World &quot;</code>, will be converted into <code>&quot;Hello world&quot;</code>.
This works similar to <code>strip</code>, <code>lstrip</code> and <code>rstrip</code> functions, which are frequently used in python.
<pre><code>string strip(string str) {
 while (str[str.length() - 1] == ' ') {
 str = str.substr(0, str.length() - 1);
 }
 while (str[0] == ' ') {
 str = str.substr(1, str.length() - 1);
 }
 return str;
}

string lstrip(string str) {
 while (str[0] == ' ') {
 str = str.substr(1, str.length() - 1);
 }
 return str;
}

string rstrip(string str) {
 while (str[str.length() - 1] == ' ') {
 str = str.substr(0, str.length() - 1);
 }
 return str;
}
</code></pre>

blocks|key|1759317|text|string+removespace(string+str)
{++++
++++int+m+=+str.length();
++++int+i=0;
++++while(i<m)
++++{
++++++++while(str[i]+==+32)
++++++++str.erase(i,1);
++++++++i%2B%2B;
++++}++++
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1759318|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>string removespace(string str)
{ 
 int m = str.length();
 int i=0;
 while(i&lt;m)
 {
 while(str[i] == 32)
 str.erase(i,1);
 i++;
 } 
}
</code></pre>

blocks|key|1544115|text|恐怕这是我能想到的最好的解决方案了。但是，您可以使用reserve()预先分配所需的最小内存，以提高速度。您将得到一个可能更短但占用相同内存量的新字符串，但您将避免重新分配。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1544116|编辑:根据你的情况，这可能会比乱七八糟的字符产生更少的开销。|1544117|您应该尝试不同的方法，看看哪种方法最适合您:您可能根本没有任何性能问题。|1544118|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

I'm afraid it's the best solution that I can think of. But you can use reserve() to pre-allocate the minimum required memory in advance to speed up things a bit. You'll end up with a new string that will probably be shorter but that takes up the same amount of memory, but you'll avoid reallocations.

EDIT: Depending on your situation, this may incur less overhead than jumbling characters around.

You should try different approaches and see what is best for you: you might not have any performance issues at all.

What is the preferred way to remove spaces from a string in C++? I could loop through all the characters and build a new string, but is there a better way?

Remove spaces from std::string in C++

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在C++中，从字符串中删除空格的首选方法是什么？我可以遍历所有的字符并构建一个新的字符串，但是有更好的方法吗？

问删除C++中std::string中的空格
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