blocks|key|1798948|text|试着使用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1798949|$arrayDateAndMachine+=+array(+++array("1999","3.0"),+
++++++++++++++++++++++++++++++++array("2000","3.9")
++++++++++++++++++++++++++++++++);|code-block|syntax|javascript|1798950|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try using this

<pre><code>$arrayDateAndMachine = array( array("1999","3.0"), 
 array("2000","3.9")
 );
</code></pre>

blocks|key|1584024|text|$obj+=+new+stdClass();
$obj->label="Devices+per+year";
$obj->data+=+array(
++++array('1999','3.0'),
++++array('2000','3.9'),
++++//and+so+on...
);

echo+json_encode($obj);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1584025|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$obj = new stdClass();
$obj-&gt;label="Devices per year";
$obj-&gt;data = array(
 array('1999','3.0'),
 array('2000','3.9'),
 //and so on...
);

echo json_encode($obj);
</code></pre>

blocks|key|1799065|text|json中的方括号[]是数组，所以你必须这样做|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1799066|<?php

$arrayDateAndMachine+=+array(+
++++array(1999,+3.0),+
++++array(2000,+3.9),
);

$arr+=+array("label"+=>+"Devices+per+year",+
+++++++++++++"data"+=>+$arrayDateAndMachine);

var_dump(json_encode($arr));|code-block|syntax|javascript|1799067|entityMap^0|0|4|9|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

square brackets <code>[]</code> in <code>json</code> is array so you have to do it like this

<pre><code>&lt;?php

$arrayDateAndMachine = array( 
 array(1999, 3.0), 
 array(2000, 3.9),
);

$arr = array("label" =&gt; "Devices per year", 
 "data" =&gt; $arrayDateAndMachine);

var_dump(json_encode($arr));
</code></pre>

blocks|key|1584459|text|我更喜欢下面的语法，它可以得到想要的结果，并且易于阅读：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1584460|$ar+=+array(
++++++++++++"label"+=>+"Devices+per+years",
++++++++++++"data"+=>+array(array(1999,+3.0),+array(2000,+3.9)+)
++++++++);

var_dump(json_encode($ar));|code-block|syntax|javascript|1584461|唯一的区别是在输出"3.0“中呈现为"3”。如果您需要尾随的".0“，您可以用引号将这些值括起来。|1584462|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I prefer the following syntax which gets the desired result and is clear to read:

<pre><code>$ar = array(
 "label" =&gt; "Devices per years",
 "data" =&gt; array(array(1999, 3.0), array(2000, 3.9) )
 );

var_dump(json_encode($ar));
</code></pre>

The only difference being that in the output "3.0" is rendered as "3". If you need the trailing ".0" you could surround those values with quotes.

blocks|key|1799710|text|如果您只想将其声明为JSON，而不是使用json_encode，那么这样做应该是可行的。这也消除了为其中的每个数组声明多个变量的需要。但只有在数据数组的内容是有限的情况下，这才是一个可行的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1799711|$json_string+=+'{+
"label":+"Devices+per+year",
"data":+[
++++[1999,+3.0],+[2000,+3.9],+[2001,+2.0],+[2002,+1.2],+[2003,+1.3],+[2004,+2.5],+[2005,+2.0],+[2006,+3.1],+[2007,+2.9],+[2008,+0.9]
]}';|code-block|syntax|javascript|1799712|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Doing something like this should work if you would like to declare it as JSON only and not by using json_encode. This also eliminates the need to declare multiple variables for each of the arrays inside. But this would be a viable solution only if the contents of the array for data is finite.

<pre><code>$json_string = '{ 
"label": "Devices per year",
"data": [
 [1999, 3.0], [2000, 3.9], [2001, 2.0], [2002, 1.2], [2003, 1.3], [2004, 2.5], [2005, 2.0], [2006, 3.1], [2007, 2.9], [2008, 0.9]
]}';
</code></pre>

<h2>How can I achieve or create this type JSON object using PHP?</h2>

<pre><code>{ 
 "label": "Devices per year",
 "data": [
 [1999, 3.0], [2000, 3.9], [2001, 2.0], [2002, 1.2], [2003, 1.3], [2004, 2.5], [2005, 2.0], [2006, 3.1], [2007, 2.9], [2008, 0.9]
 ]
}
</code></pre>

<hr>

After several attempt I didn't find the solution.
For example I tried this:

<pre><code>$arrayDateAndMachine = array(
 "1999"=&gt;3.0, 
 "2000"=&gt;3.9
); 

$arr = array(
 "label" =&gt; "Devices per year", 
 "data" =&gt; $arrayDateAndMachine
);

var_dump(json_encode($arr));
</code></pre>

Create JSON object using PHP

JSON

如何使用PHP实现或创建此类型的JSON对象？{     "label": "Devices per year",    "data": [        [1999, 3.0], [2000, 3.9], [2001, 2.0], [2002, 1.2], [2003, 1.3], [2004, 2.5], [200...

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