blocks|key|1157354|text|调用str(...)是一种将事物转换为字符串的Pythonic方式。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1157355|您可能需要考虑为什么需要一个字符串列表。相反，您可以将其保留为整数列表，并仅在需要显示整数时才将其转换为字符串。例如，如果您有一个整数列表，那么您可以在For循环中逐个转换它们，并使用,连接它们|1157356|print(','.join(str(x)+for+x+in+list_of_ints))|code-block|syntax|javascript|1157357|entityMap^0|2|8|0|2K|1|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|U|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

Calling <code>str(...)</code> is the Pythonic way to convert something to a string.

You might want to consider why you want a list of strings. You could instead keep it as a list of integers and only convert the integers to strings when you need to display them. For example, if you have a list of integers then you can convert them one by one in a for-loop and join them with <code>,</code>:

<pre><code>print(','.join(str(x) for x in list_of_ints))
</code></pre>

blocks|key|943297|text|将整数传递给str没有任何错误。你可能不这样做的一个原因是，myList实际上被认为是一个整数列表，例如，对列表中的值求和是合理的。在这种情况下，在将整型值附加到myList之前，不要将它们传递给字符串。如果在追加之前没有转换为字符串，则可以通过执行以下操作来构造一个大字符串|type|unstyled|depth|inlineStyleRanges|entityRanges|data|943298|',+'.join(map(str,+myList))|code-block|syntax|javascript|943299|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

There's nothing wrong with passing integers to str. One reason you might not do this is that myList is really supposed to be a list of integers e.g. it would be reasonable to sum the values in the list. In that case, do not pass your ints to str before appending them to myList. If you end up not converting to strings before appending, you can construct one big string by doing something like

<pre><code>', '.join(map(str, myList))
</code></pre>

blocks|key|1157462|text|你的问题很明显。也许您正在寻找extend，将另一个列表的所有元素添加到现有列表中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1157463|>>>+x+=+[1,2]
>>>+x.extend([3,4,5])
>>>+x
[1,+2,+3,+4,+5]|code-block|syntax|javascript|1157464|如果您想将整数转换为字符串，请使用str()或字符串插值，可能与列表理解相结合，例如|1157465|>>>+x+=+['1',+'2']
>>>+x.extend([str(i)+for+i+in+range(3,+6)])
>>>+x
['1',+'2',+'3',+'4',+'5']|1157466|所有这些都被认为是pythonic式的(好吧，生成器表达式甚至更pythonic式，但让我们保持简单并继续讨论主题)|1157467|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Your problem is rather clear. Perhaps you're looking for extend, to add all elements of another list to an existing list:

<pre><code>&gt;&gt;&gt; x = [1,2]
&gt;&gt;&gt; x.extend([3,4,5])
&gt;&gt;&gt; x
[1, 2, 3, 4, 5]
</code></pre>

If you want to convert integers to strings, use str() or string interpolation, possibly combined with a list comprehension, i.e.

<pre><code>&gt;&gt;&gt; x = ['1', '2']
&gt;&gt;&gt; x.extend([str(i) for i in range(3, 6)])
&gt;&gt;&gt; x
['1', '2', '3', '4', '5']
</code></pre>

All of this is considered pythonic (ok, a generator expression is even more pythonic but let's stay simple and on topic)

blocks|key|943383|text|也许你不需要数字作为字符串，只需要这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|943384|functaulu+=+[munfunc(arg)+for+arg+in+range(loppu)]|code-block|syntax|javascript|943385|以后，如果你需要字符串，你可以使用字符串或格式字符串：|943386|print+"Vastaus5+=+%25s"+%25+functaulu[5]|offset|length|style|CODE|943387|entityMap^0|0|0|0|0|10|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@$K|U|L|V|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Maybe you do not need numbers as strings, just do:

<pre><code>functaulu = [munfunc(arg) for arg in range(loppu)]
</code></pre>

Later if you need it as string you can do it with string or with format string:

<code>print "Vastaus5 = %s" % functaulu[5]</code>

blocks|key|943406|text|a=[1,2,3]
b=[str(x)+for+x+in+a]
print+b|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|943407|上面的方法是将列表转换为字符串的最简单和最通用的方法。另一种简单的方法是-|unstyled|943408|a=[1,2,3]
b=map(str,a)
print+b|943409|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>a=[1,2,3]
b=[str(x) for x in a]
print b
</code></pre>

above method is the easiest and most general way to convert list into string. another short method is-

<pre><code>a=[1,2,3]
b=map(str,a)
print b
</code></pre>

blocks|key|1157537|text|例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1157538|lst_points+=+[[313,+262,+470,+482],+[551,+254,+697,+449]]

lst_s_points+=+["+".join(map(str,+lst))+for+lst+in+lst_points]
print+lst_s_points
#+['313+262+470+482',+'551+254+697+449']|code-block|syntax|javascript|1157539|对我来说，我想在每个字符串列表之前添加一个str：|offset|length|style|CODE|1157540|#+here+o+means+class,+other+four+points+means+coordinate
print+['0+'+%2B+"+".join(map(str,+lst))+for+lst+in+lst_points]
#+['0+313+262+470+482',+'0+551+254+697+449']|1157541|或单个列表：|1157542|lst+=+[313,+262,+470,+482]
lst_str+=+[str(i)+for+i+in+lst]
print+lst_str,+",+".join(lst_str)
#+['313',+'262',+'470',+'482'],+313,+262,+470,+482

lst_str+=+map(str,+lst)
print+lst_str,+",+".join(lst_str)
#+['313',+'262',+'470',+'482'],+313,+262,+470,+482|1157543|entityMap^0|0|0|L|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

For example:

<pre><code>lst_points = [[313, 262, 470, 482], [551, 254, 697, 449]]

lst_s_points = [" ".join(map(str, lst)) for lst in lst_points]
print lst_s_points
# ['313 262 470 482', '551 254 697 449']
</code></pre>

As to me, I want to add a <code>str</code> before each str list:

<pre><code># here o means class, other four points means coordinate
print ['0 ' + " ".join(map(str, lst)) for lst in lst_points]
# ['0 313 262 470 482', '0 551 254 697 449']
</code></pre>

Or single list:

<pre><code>lst = [313, 262, 470, 482]
lst_str = [str(i) for i in lst]
print lst_str, ", ".join(lst_str)
# ['313', '262', '470', '482'], 313, 262, 470, 482

lst_str = map(str, lst)
print lst_str, ", ".join(lst_str)
# ['313', '262', '470', '482'], 313, 262, 470, 482
</code></pre>

blocks|key|943448|text|为什么似乎没有人喜欢repr？|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|943449|+python+3.7.2:|code-block|syntax|javascript|943450|>>>+int_list+=+[1,+2,+3,+4,+5]
>>>+print(repr(int_list))
[1,+2,+3,+4,+5]
>>>+|943451|不过要小心，这是一个明确的表示。示例如下所示：|943452|#Print+repr(object)+backwards
>>>+print(repr(int_list)[::-1])
]5+,4+,3+,2+,1[
>>>+|943453|欲了解更多信息，请访问pydocs-repr|943454|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3.7/library/functions.html#repr^0|A|4|0|0|0|0|0|B|B|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|M|3|N|5|6|7|15|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|S|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

How come no-one seems to like <code>repr</code>? 
 python 3.7.2:

<pre><code>&gt;&gt;&gt; int_list = [1, 2, 3, 4, 5]
&gt;&gt;&gt; print(repr(int_list))
[1, 2, 3, 4, 5]
&gt;&gt;&gt; 
</code></pre>

Take care though, it's an explicit representation. An example shows:

<pre><code>#Print repr(object) backwards
&gt;&gt;&gt; print(repr(int_list)[::-1])
]5 ,4 ,3 ,2 ,1[
&gt;&gt;&gt; 
</code></pre>

more info at <a href="https://docs.python.org/3.7/library/functions.html#repr" rel="nofollow noreferrer">pydocs-repr</a>

I need to join a list of items. Many of the items in the list are integer values returned from a function; i.e.,

<pre><code>myList.append(munfunc()) 
</code></pre>

How should I convert the returned result to a string in order to join it with the list?

Do I need to do the following for every integer value:

<pre><code>myList.append(str(myfunc()))
</code></pre>

Is there a more Pythonic way to solve casting problems?

Join a list of items with different types as string in Python

我需要加入一个项目列表。列表中的许多项是从函数返回的整数值；即，myList.append(munfunc()) 我应该如何将返回的结果转换为字符串，以便将其与列表连接？是否需要对每个整数值执行以下操作：myList.append(str(myfunc()))有没有更具Pythonic风格的方法来解决造型问题？

问在Python中将具有不同类型的项目列表连接为字符串
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