blocks|key|1137285|text|这可以很好地工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137286|<?php
++//date+in+mm/dd/yyyy+format;+or+it+can+be+in+other+formats+as+well
++$birthDate+=+"12/17/1983";
++//explode+the+date+to+get+month,+day+and+year
++$birthDate+=+explode("/",+$birthDate);
++//get+age+from+date+or+birthdate
++$age+=+(date("md",+date("U",+mktime(0,+0,+0,+$birthDate[0],+$birthDate[1],+$birthDate[2])))+>+date("md")
++++?+((date("Y")+-+$birthDate[2])+-+1)
++++:+(date("Y")+-+$birthDate[2]));
++echo+"Age+is:"+.+$age;
?>|code-block|syntax|javascript|1137287|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works fine. 

<pre><code>&lt;?php
 //date in mm/dd/yyyy format; or it can be in other formats as well
 $birthDate = "12/17/1983";
 //explode the date to get month, day and year
 $birthDate = explode("/", $birthDate);
 //get age from date or birthdate
 $age = (date("md", date("U", mktime(0, 0, 0, $birthDate[0], $birthDate[1], $birthDate[2]))) &gt; date("md")
 ? ((date("Y") - $birthDate[2]) - 1)
 : (date("Y") - $birthDate[2]));
 echo "Age is:" . $age;
?&gt;
</code></pre>

blocks|key|1137263|text|$tz++=+new+DateTimeZone('Europe/Brussels');
$age+=+DateTime::createFromFormat('d/m/Y',+'12/02/1973',+$tz)
+++++->diff(new+DateTime('now',+$tz))
+++++->y;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1137264|从PHP5.3.0开始，您可以使用方便的DateTime::createFromFormat来确保日期不会被误认为m/d/Y格式，并使用DateInterval类(通过DateTime::diff)来获取从现在到目标日期之间的年数。|unstyled|offset|length|style|CODE|1137265|entityMap^0|0|K|Q|1L|5|1W|C|2C|E|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]|$G|S|H|T|I|J]|$G|U|H|V|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|W|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>$tz = new DateTimeZone('Europe/Brussels');
$age = DateTime::createFromFormat('d/m/Y', '12/02/1973', $tz)
 -&gt;diff(new DateTime('now', $tz))
 -&gt;y;
</code></pre>

As of PHP 5.3.0 you can use the handy <code>DateTime::createFromFormat</code> to ensure that your date does not get mistaken for <code>m/d/Y</code> format and the <code>DateInterval</code> class (via <code>DateTime::diff</code>) to get the number of years between now and the target date.

blocks|key|922640|text|+$date+=+new+DateTime($bithdayDate);
+$now+=+new+DateTime();
+$interval+=+$now->diff($date);
+return+$interval->y;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|922641|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> $date = new DateTime($bithdayDate);
 $now = new DateTime();
 $interval = $now-&gt;diff($date);
 return $interval-&gt;y;
</code></pre>

blocks|key|1137726|text|我使用日期/时间来执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137727|$age+=+date_diff(date_create($bdate),+date_create('now'))->y;|code-block|syntax|javascript|1137728|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I use Date/Time for this:
<pre><code>$age = date_diff(date_create($bdate), date_create('now'))-&gt;y;
</code></pre>

blocks|key|1137550|text|从道布推算年龄的简单方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137551|$_age+=+floor((time()+-+strtotime('1986-09-16'))+/+31556926);|code-block|syntax|javascript|1137552|31556926是一年中的秒数。|offset|length|style|CODE|1137553|entityMap^0|0|0|0|8|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Simple method for calculating Age from dob:

<pre><code>$_age = floor((time() - strtotime('1986-09-16')) / 31556926);
</code></pre>

<code>31556926</code> is the number of seconds in a year.

blocks|key|923449|text|我发现这很有效，而且很简单。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923450|从1970减去，因为strtotime从1970-01-01计算时间(http://php.net/manual/en/function.strtotime.php)|offset|length|923451|function+getAge($date)+{
++++return+intval(date('Y',+time()+-+strtotime($date)))+-+1970;
}|code-block|syntax|javascript|923452|结果：|923453|Current+Time:+2015-10-22+10:04:23

getAge('2005-10-22')+//+=>+10
getAge('1997-10-22+10:06:52')+//+one+1s+before++=>+17
getAge('1997-10-22+10:06:50')+//+one+1s+after+=>+18
getAge('1985-02-04')+//+=>+30
getAge('1920-02-29')+//+=>+95|923454|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.strtotime.php^0|0|Z|1B|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|A|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

I find this works and is simple. 

Subtract from 1970 because strtotime calculates time from 1970-01-01 (<a href="http://php.net/manual/en/function.strtotime.php" rel="noreferrer">http://php.net/manual/en/function.strtotime.php</a>)

<pre><code>function getAge($date) {
 return intval(date('Y', time() - strtotime($date))) - 1970;
}
</code></pre>

Results:

<pre><code>Current Time: 2015-10-22 10:04:23

getAge('2005-10-22') // =&gt; 10
getAge('1997-10-22 10:06:52') // one 1s before =&gt; 17
getAge('1997-10-22 10:06:50') // one 1s after =&gt; 18
getAge('1985-02-04') // =&gt; 30
getAge('1920-02-29') // =&gt; 95
</code></pre>

blocks|key|922888|text|如果你想计算使用道布的年龄，你也可以使用这个函数。它使用DateTime对象。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|922889|function+calcutateAge($dob){

++++++++$dob+=+date("Y-m-d",strtotime($dob));

++++++++$dobObject+=+new+DateTime($dob);
++++++++$nowObject+=+new+DateTime();

++++++++$diff+=+$dobObject->diff($nowObject);

++++++++return+$diff->y;

}|code-block|syntax|javascript|922890|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you want to caculate the Age of using the dob, you can also use this function. 
It uses the DateTime object.

<pre><code>function calcutateAge($dob){

 $dob = date("Y-m-d",strtotime($dob));

 $dobObject = new DateTime($dob);
 $nowObject = new DateTime();

 $diff = $dobObject-&gt;diff($nowObject);

 return $diff-&gt;y;

}
</code></pre>

blocks|key|1138179|text|您可以使用API，它是DateTime的一个Carbon+library扩展。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1138180|您可以：|1138181|function+calculate_age($date)+{
++++$date+=+new+\Carbon\Carbon($date);
++++return+(int)+$date->diffInYears();
}|code-block|syntax|javascript|1138182|或者：|1138183|$age+=+(new+\Carbon\Carbon($date))->age;|1138184|entityMap|0|LINK|mutability|MUTABLE|url|http://carbon.nesbot.com/docs/#api-difference^0|M|6|M|E|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|F|3|G|5|6|7|14|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|15|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|16|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|17|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

You can use the <a href="http://carbon.nesbot.com/docs/#api-difference" rel="noreferrer"><code>Carbon</code> library</a>, which is an API extension for DateTime.

You can:

<pre><code>function calculate_age($date) {
 $date = new \Carbon\Carbon($date);
 return (int) $date-&gt;diffInYears();
}
</code></pre>

or:

<pre><code>$age = (new \Carbon\Carbon($date))-&gt;age;
</code></pre>

blocks|key|1138370|text|编写一个PHP脚本来计算一个人的当前年龄。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1138371|样本出生日期:1987年4月11日|1138372|示例解决方案：|1138373|PHP代码：|1138374|<?php
$bday+=+new+DateTime('11.4.1987');+//+Your+date+of+birth
$today+=+new+Datetime(date('m.d.y'));
$diff+=+$today->diff($bday);
printf('+Your+age+:+%25d+years,+%25d+month,+%25d+days',+$diff->y,+$diff->m,+$diff->d);
printf("\n");
?>|code-block|syntax|javascript|1138375|示例输出：|1138376|您的年龄:+30岁3个月零天|1138377|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|U|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|V|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|W|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Write a PHP script to calculate the current age of a person.

Sample date of birth : 11.4.1987

Sample Solution:

PHP Code:

<pre><code>&lt;?php
$bday = new DateTime('11.4.1987'); // Your date of birth
$today = new Datetime(date('m.d.y'));
$diff = $today-&gt;diff($bday);
printf(' Your age : %d years, %d month, %d days', $diff-&gt;y, $diff-&gt;m, $diff-&gt;d);
printf("\n");
?&gt;
</code></pre>

Sample Output:

Your age : 30 years, 3 month, 0 days

blocks|key|1137304|text|$birthday_timestamp+=+strtotime('1988-12-10');++

//+Calculates+age+correctly
//+Just+need+birthday+in+timestamp
$age+=+date('md',+$birthday_timestamp)+>+date('md')+?+date('Y')+-+date('Y',+$birthday_timestamp)+-+1+:+date('Y')+-+date('Y',+$birthday_timestamp);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1137305|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$birthday_timestamp = strtotime('1988-12-10'); 

// Calculates age correctly
// Just need birthday in timestamp
$age = date('md', $birthday_timestamp) &gt; date('md') ? date('Y') - date('Y', $birthday_timestamp) - 1 : date('Y') - date('Y', $birthday_timestamp);
</code></pre>

blocks|key|922619|text|//replace+/+with+-+so+strtotime+works
$dob+=+strtotime(str_replace("/","-",$birthdayDate));+++++++
$tdate+=+time();
return+date('Y',+$tdate)+-+date('Y',+$dob);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|922620|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>//replace / with - so strtotime works
$dob = strtotime(str_replace("/","-",$birthdayDate)); 
$tdate = time();
return date('Y', $tdate) - date('Y', $dob);
</code></pre>

blocks|key|1137202|text|++function+dob+($birthday){
++++list($day,$month,$year)+=+explode("/",$birthday);
++++$year_diff++=+date("Y")+-+$year;
++++$month_diff+=+date("m")+-+$month;
++++$day_diff+++=+date("d")+-+$day;
++++if+($day_diff+<+0+%7C%7C+$month_diff+<+0)
++++++$year_diff--;
++++return+$year_diff;
++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1137203|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> function dob ($birthday){
 list($day,$month,$year) = explode("/",$birthday);
 $year_diff = date("Y") - $year;
 $month_diff = date("m") - $month;
 $day_diff = date("d") - $day;
 if ($day_diff &lt; 0 || $month_diff &lt; 0)
 $year_diff--;
 return $year_diff;
 }
</code></pre>

blocks|key|922838|text|我发现这个脚本是可靠的。它采用YYYY-mm-dd的日期格式，但是可以很容易地修改为其他格式。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|922839|/*
*+Get+age+from+dob
*+@param++++++++dob++++++string+++++++The+dob+to+validate+in+mysql+format+(yyyy-mm-dd)
*+@return++++++++++++integer++++++The+age+in+years+as+of+the+current+date
*/
function+getAge($dob)+{
++++//calculate+years+of+age+(input+string:+YYYY-MM-DD)
++++list($year,+$month,+$day)+=+explode("-",+$dob);

++++$year_diff++=+date("Y")+-+$year;
++++$month_diff+=+date("m")+-+$month;
++++$day_diff+++=+date("d")+-+$day;

++++if+($day_diff+<+0+%7C%7C+$month_diff+<+0)
++++++++$year_diff--;

++++return+$year_diff;
}|code-block|syntax|javascript|922840|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I have found this script reliable. It takes the date format as YYYY-mm-dd, but it could be modified for other formats pretty easily. 

<pre><code>/*
* Get age from dob
* @param dob string The dob to validate in mysql format (yyyy-mm-dd)
* @return integer The age in years as of the current date
*/
function getAge($dob) {
 //calculate years of age (input string: YYYY-MM-DD)
 list($year, $month, $day) = explode("-", $dob);

 $year_diff = date("Y") - $year;
 $month_diff = date("m") - $month;
 $day_diff = date("d") - $day;

 if ($day_diff &lt; 0 || $month_diff &lt; 0)
 $year_diff--;

 return $year_diff;
}
</code></pre>

blocks|key|923091|text|i18n：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923092|function+getAge($birthdate,+$pattern+=+'eu')
{
++++$patterns+=+array(
++++++++'eu'++++=>+'d/m/Y',
++++++++'mysql'+=>+'Y-m-d',
++++++++'us'++++=>+'m/d/Y',
++++);

++++$now++++++=+new+DateTime();
++++$in+++++++=+DateTime::createFromFormat($patterns[$pattern],+$birthdate);
++++$interval+=+$now->diff($in);
++++return+$interval->y;
}

//+Usage
echo+getAge('05/29/1984',+'us');
//+return+28|code-block|syntax|javascript|923093|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

i18n :

<pre><code>function getAge($birthdate, $pattern = 'eu')
{
 $patterns = array(
 'eu' =&gt; 'd/m/Y',
 'mysql' =&gt; 'Y-m-d',
 'us' =&gt; 'm/d/Y',
 );

 $now = new DateTime();
 $in = DateTime::createFromFormat($patterns[$pattern], $birthdate);
 $interval = $now-&gt;diff($in);
 return $interval-&gt;y;
}

// Usage
echo getAge('05/29/1984', 'us');
// return 28
</code></pre>

blocks|key|1138138|text|使用DateTime对象尝试其中任何一个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1138139|$hours_in_day+++=+24;
$minutes_in_hour=+60;
$seconds_in_mins=+60;

$birth_date+++++=+new+DateTime("1988-07-31T00:00:00");
$current_date+++=+new+DateTime();

$diff+++++++++++=+$birth_date->diff($current_date);

echo+$years+++++=+$diff->y+.+"+years+"+.+$diff->m+.+"+months+"+.+$diff->d+.+"+day(s)";+echo+" ";
echo+$months++++=+($diff->y+*+12)+%2B+$diff->m+.+"+months+"+.+$diff->d+.+"+day(s)";+echo+" ";
echo+$weeks+++++=+floor($diff->days/7)+.+"+weeks+"+.+$diff->d%257+.+"+day(s)";+echo+" ";
echo+$days++++++=+$diff->days+.+"+days";+echo+" ";
echo+$hours+++++=+$diff->h+%2B+($diff->days+*+$hours_in_day)+.+"+hours";+echo+" ";
echo+$mins++++++=+$diff->h+%2B+($diff->days+*+$hours_in_day+*+$minutes_in_hour)+.+"+minutest";+echo+" ";
echo+$seconds+++=+$diff->h+%2B+($diff->days+*+$hours_in_day+*+$minutes_in_hour+*+$seconds_in_mins)+.+"+seconds";+echo+" ";|code-block|syntax|javascript|1138140|参考http://www.calculator.net/age-calculator.html|offset|length|1138141|entityMap|0|LINK|mutability|MUTABLE|url|http://www.calculator.net/age-calculator.html^0|0|0|2|19|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Try any of these using DateTime object

<pre><code>$hours_in_day = 24;
$minutes_in_hour= 60;
$seconds_in_mins= 60;

$birth_date = new DateTime("1988-07-31T00:00:00");
$current_date = new DateTime();

$diff = $birth_date-&gt;diff($current_date);

echo $years = $diff-&gt;y . " years " . $diff-&gt;m . " months " . $diff-&gt;d . " day(s)"; echo "&lt;br/&gt;";
echo $months = ($diff-&gt;y * 12) + $diff-&gt;m . " months " . $diff-&gt;d . " day(s)"; echo "&lt;br/&gt;";
echo $weeks = floor($diff-&gt;days/7) . " weeks " . $diff-&gt;d%7 . " day(s)"; echo "&lt;br/&gt;";
echo $days = $diff-&gt;days . " days"; echo "&lt;br/&gt;";
echo $hours = $diff-&gt;h + ($diff-&gt;days * $hours_in_day) . " hours"; echo "&lt;br/&gt;";
echo $mins = $diff-&gt;h + ($diff-&gt;days * $hours_in_day * $minutes_in_hour) . " minutest"; echo "&lt;br/&gt;";
echo $seconds = $diff-&gt;h + ($diff-&gt;days * $hours_in_day * $minutes_in_hour * $seconds_in_mins) . " seconds"; echo "&lt;br/&gt;";
</code></pre>

Reference <a href="http://www.calculator.net/age-calculator.html" rel="nofollow">http://www.calculator.net/age-calculator.html</a>

blocks|key|1138018|text|如果你只想随着年龄的增长获得完整的年龄，那么有一个非常简单的方法可以做到。将格式为'YYYYMMDD‘的日期视为数字并减去它们。在那之后，通过将结果除以10000来抵消MMDD部分，并将其向下。简单且永不失败，甚至考虑到leapyears和您当前的服务器时间;)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1138019|因为生日或主要由出生地点的完整日期提供，并且它们与当前当地时间(实际进行年龄检查的地方)相关。|1138020|$now+=+date['Ymd'];
$birthday+=+'19780917';+#september+17th,+1978
$age+=+floor(($now-$birthday)/10000);|code-block|syntax|javascript|1138021|因此，如果你想在生日前检查某人是否在你所在时区的18岁、21岁或100岁以下(不用管原始时区)，这是我的方法|1138022|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you want to only get fullyears as age, there is a supersimple way on doing that. treat dates formatted as 'YYYYMMDD' as numbers and substract them. After that cancel out the MMDD part by dividing the result with 10000 and floor it down. Simple and never fails, even takes to account leapyears and your current server time ;)
Since birthdays or mostly provided by full dates on birth location and they are relevant to CURRENT LOCAL TIME (where the age check is actually done).
<pre><code>$now = date['Ymd'];
$birthday = '19780917'; #september 17th, 1978
$age = floor(($now-$birthday)/10000);
</code></pre>
so if you want to check if someone is 18 or 21 or below 100 on your timezone (nevermind the origin timezone) by birthday, this is my way to do this

blocks|key|923578|text|此函数将返回以年为单位的年龄。输入值为日期格式(YYYY-MM-DD)出生日期字符串，例如:+2000-01-01|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923579|它以天为单位工作|923580|function+getAge($dob)+{
++++//calculate+years+of+age+(input+string:+YYYY-MM-DD)
++++list($year,+$month,+$day)+=+explode("-",+$dob);

++++$year_diff++=+date("Y")+-+$year;
++++$month_diff+=+date("m")+-+$month;
++++$day_diff+++=+date("d")+-+$day;

++++//+if+we+are+any+month+before+the+birthdate:+year+-+1+
++++//+OR+if+we+are+in+the+month+of+birth+but+on+a+day+
++++//+before+the+actual+birth+day:+year+-+1
++++if+(+($month_diff+<+0+)+%7C%7C+($month_diff+===+0+&&+$day_diff+<+0))
++++++++$year_diff--;+++

++++return+$year_diff;
}|code-block|syntax|javascript|923581|干杯，妮拉|923582|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This function will return the age in years. Input value is a date formated (YYYY-MM-DD) day of birth string eg: 2000-01-01 

It works with day - precision

<pre><code>function getAge($dob) {
 //calculate years of age (input string: YYYY-MM-DD)
 list($year, $month, $day) = explode("-", $dob);

 $year_diff = date("Y") - $year;
 $month_diff = date("m") - $month;
 $day_diff = date("d") - $day;

 // if we are any month before the birthdate: year - 1 
 // OR if we are in the month of birth but on a day 
 // before the actual birth day: year - 1
 if ( ($month_diff &lt; 0 ) || ($month_diff === 0 &amp;&amp; $day_diff &lt; 0))
 $year_diff--; 

 return $year_diff;
}
</code></pre>

Cheers, nira

blocks|key|1137446|text|如果你看起来不能使用一些新的函数，这里有一些我做的。可能比你需要的更多，我相信有更好的方法，但它很容易阅读，所以它应该能做好工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137447|function+get_age($date,+$units='years')
{
++++$modifier+=+date('n')+-+date('n',+strtotime($date))+?+1+:+(date('j')+-+date('j',+strtotime($date))+?+1+:+0);
++++$seconds+=+(time()-strtotime($date));
++++$years+=+(date('Y')-date('Y',+strtotime($date))-$modifier);
++++switch($units)
++++{
++++++++case+'seconds':
++++++++++++return+$seconds;
++++++++case+'minutes':
++++++++++++return+round($seconds/60);
++++++++case+'hours':
++++++++++++return+round($seconds/60/60);
++++++++case+'days':
++++++++++++return+round($seconds/60/60/24);
++++++++case+'months':
++++++++++++return+($years*12%2Bdate('n'));
++++++++case+'decades':
++++++++++++return+($years/10);
++++++++case+'centuries':
++++++++++++return+($years/100);
++++++++case+'years':
++++++++default:
++++++++++++return+$years;
++++}
}|code-block|syntax|javascript|1137448|示例用法：|1137449|echo+'I+am+'.get_age('September+19th,+1984',+'days').'+days+old';|1137450|希望这能有所帮助。|1137451|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If you can't seem to use some of the newer functions, here's something I whipped up. Probably more than you need, and I'm sure there are better ways, but it's easy to read, so it should do the job:

<pre><code>function get_age($date, $units='years')
{
 $modifier = date('n') - date('n', strtotime($date)) ? 1 : (date('j') - date('j', strtotime($date)) ? 1 : 0);
 $seconds = (time()-strtotime($date));
 $years = (date('Y')-date('Y', strtotime($date))-$modifier);
 switch($units)
 {
 case 'seconds':
 return $seconds;
 case 'minutes':
 return round($seconds/60);
 case 'hours':
 return round($seconds/60/60);
 case 'days':
 return round($seconds/60/60/24);
 case 'months':
 return ($years*12+date('n'));
 case 'decades':
 return ($years/10);
 case 'centuries':
 return ($years/100);
 case 'years':
 default:
 return $years;
 }
}
</code></pre>

Example Use:

<pre><code>echo 'I am '.get_age('September 19th, 1984', 'days').' days old';
</code></pre>

Hope this helps.

blocks|key|1137518|text|由于是闰年，仅仅从一个日期减去另一个日期并将其计算为年数是不明智的。为了像人类一样计算年龄，你需要这样的东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137519|$birthday_date+=+'1977-04-01';
$age+=+date('Y')+-+substr($birthday_date,+0,+4);
if+(strtotime(date('Y-m-d'))+-+strtotime(date('Y')+.+substr($birthday_date,+4,+6))+<+0)
{
++++$age--;
}|code-block|syntax|javascript|1137520|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Due to leap year, it is not wise just to subtract one date from another and floor it to number of years. To calculate the age like the humans, you will need something like this:

<pre><code>$birthday_date = '1977-04-01';
$age = date('Y') - substr($birthday_date, 0, 4);
if (strtotime(date('Y-m-d')) - strtotime(date('Y') . substr($birthday_date, 4, 6)) &lt; 0)
{
 $age--;
}
</code></pre>

blocks|key|1137583|text|下面的例子对我来说很有效，而且看起来比已经给出的例子简单得多。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137584|$dob_date+=+"01";
$dob_month+=+"01";
$dob_year+=+"1970";
$year+=+gmdate("Y");
$month+=+gmdate("m");
$day+=+gmdate("d");
$age+=+$year-$dob_year;+//+$age+calculates+the+user's+age+determined+by+only+the+year
if($month+<+$dob_month)+{+//+this+checks+if+the+current+month+is+before+the+user's+month+of+birth
++$age+=+$age-1;
}+else+if($month+==+$dob_month+&&+$day+>=+$dob_date)+{+//+this+checks+if+the+current+month+is+the+same+as+the+user's+month+of+birth+and+then+checks+if+it+is+the+user's+birthday+or+if+it+is+after+it
++$age+=+$age;
}+else+if($month+==+$dob_month+&&+$day+<+$dob_date)+{+//this+checks+if+the+current+month+is+the+user's+month+of+birth+and+checks+if+it+before+the+user's+birthday
++$age+=+$age-1;
}+else+{
++$age+=+$age;
}|code-block|syntax|javascript|1137585|我已经测试并积极使用了这段代码，它看起来可能有点麻烦，但它的使用和编辑非常简单，而且非常准确。|1137586|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The following works great for me and seems to be a lot simpler than the examples that have already been given.

<pre><code>$dob_date = "01";
$dob_month = "01";
$dob_year = "1970";
$year = gmdate("Y");
$month = gmdate("m");
$day = gmdate("d");
$age = $year-$dob_year; // $age calculates the user's age determined by only the year
if($month &lt; $dob_month) { // this checks if the current month is before the user's month of birth
 $age = $age-1;
} else if($month == $dob_month &amp;&amp; $day &gt;= $dob_date) { // this checks if the current month is the same as the user's month of birth and then checks if it is the user's birthday or if it is after it
 $age = $age;
} else if($month == $dob_month &amp;&amp; $day &lt; $dob_date) { //this checks if the current month is the user's month of birth and checks if it before the user's birthday
 $age = $age-1;
} else {
 $age = $age;
}
</code></pre>

I've tested and actively use this code, it might seem a little cumbersome but it is very simple to use and edit and is quite accurate.

blocks|key|1137636|text|遵循第一个逻辑，您必须在比较中使用=。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137637|<?php+
++++function+age($birthdate)+{
++++++++$birthdate+=+strtotime($birthdate);
++++++++$now+=+time();
++++++++$age+=+0;
++++++++while+($now+>=+($birthdate+=+strtotime("%2B1+YEAR",+$birthdate)))+{
++++++++++++$age%2B%2B;
++++++++}
++++++++return+$age;
++++}

++++//+Usage:

++++echo+age(implode("-",array_reverse(explode("/",'14/09/1986'))));+//+format+yyyy-mm-dd+is+safe!
++++echo+age("-10+YEARS")+//+without+=+in+the+comparison,+will+returns+9.

?>|code-block|syntax|javascript|1137638|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Following the first logic, you have to use = in the comparison. 

<pre><code>&lt;?php 
 function age($birthdate) {
 $birthdate = strtotime($birthdate);
 $now = time();
 $age = 0;
 while ($now &gt;= ($birthdate = strtotime("+1 YEAR", $birthdate))) {
 $age++;
 }
 return $age;
 }

 // Usage:

 echo age(implode("-",array_reverse(explode("/",'14/09/1986')))); // format yyyy-mm-dd is safe!
 echo age("-10 YEARS") // without = in the comparison, will returns 9.

?&gt;
</code></pre>

blocks|key|1137692|text|当您将strtotime与DD/MM/YYYY一起使用时，这是一个问题。你不能使用这种格式。您可以使用MM/DD/YYYY+(或许多其他如YYYYMMDD或YYYY-MM-DD)来代替它，并且它应该可以正常工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137693|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

It is a problem when you use strtotime with DD/MM/YYYY. You cant use that format. Instead of it you can use MM/DD/YYYY (or many others like YYYYMMDD or YYYY-MM-DD) and it should work properly.

blocks|key|1137772|text|启动此查询并让MySQL为您计算它如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137773|SELECT+
username
,date_of_birth
,(PERIOD_DIFF(+DATE_FORMAT(CURDATE(),+'%25Y%25m')+,+DATE_FORMAT(date_of_birth,+'%25Y%25m')+))+DIV+12+AS+years
,(PERIOD_DIFF(+DATE_FORMAT(CURDATE(),+'%25Y%25m')+,+DATE_FORMAT(date_of_birth,+'%25Y%25m')+))+MOD+12+AS+months
FROM+users|code-block|syntax|javascript|1137774|结果：|1137775|r2d2,+1986-12-23+00:00:00,+27+,+6+|1137776|用户有27年零6个月(按整月计算)|1137777|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

How about launching this query and having MySQL calculating it for you:

<pre><code>SELECT 
username
,date_of_birth
,(PERIOD_DIFF( DATE_FORMAT(CURDATE(), '%Y%m') , DATE_FORMAT(date_of_birth, '%Y%m') )) DIV 12 AS years
,(PERIOD_DIFF( DATE_FORMAT(CURDATE(), '%Y%m') , DATE_FORMAT(date_of_birth, '%Y%m') )) MOD 12 AS months
FROM users
</code></pre>

Result:

<pre><code>r2d2, 1986-12-23 00:00:00, 27 , 6 
</code></pre>

The user has 27 years and 6 months (it counts an entire month)

blocks|key|923288|text|我是这样做的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923289|$geboortedatum+=+1980-01-30+00:00:00;
echo+leeftijd($geboortedatum)+

function+leeftijd($geboortedatum)+{
++++$leeftijd+=+date('Y')-date('Y',+strtotime($geboortedatum));
++++if+(date('m')<date('m',+strtotime($geboortedatum)))
++++++++$leeftijd+=+$leeftijd-1;
++++elseif+(date('m')==date('m',+strtotime($geboortedatum)))
+++++++if+(date('d')<date('d',+strtotime($geboortedatum)))
+++++++++++$leeftijd+=+$leeftijd-1;
++++return+$leeftijd;
}|code-block|syntax|javascript|923290|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I did it like this.

<pre><code>$geboortedatum = 1980-01-30 00:00:00;
echo leeftijd($geboortedatum) 

function leeftijd($geboortedatum) {
 $leeftijd = date('Y')-date('Y', strtotime($geboortedatum));
 if (date('m')&lt;date('m', strtotime($geboortedatum)))
 $leeftijd = $leeftijd-1;
 elseif (date('m')==date('m', strtotime($geboortedatum)))
 if (date('d')&lt;date('d', strtotime($geboortedatum)))
 $leeftijd = $leeftijd-1;
 return $leeftijd;
}
</code></pre>

blocks|key|923405|text|这个问题的最高答案是OK，但只计算了一个人出生的年份，我为了自己的目的调整了它，以计算出日期和月份。但觉得值得分享。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923406|这是由用户的时间戳的作品，但请随意更改|923407|$birthDate+=+date('d-m-Y',$usersDOBtimestamp);
$currentDate+=+date('d-m-Y',+time());
//explode+the+date+to+get+month,+day+and+year
$birthDate+=+explode("-",+$birthDate);
$currentDate+=+explode("-",+$currentDate);
$birthDate[0]+=+ltrim($birthDate[0],'0');
$currentDate[0]+=+ltrim($currentDate[0],'0');
//that+gets+a+rough+age
$age+=+$currentDate[2]+-+$birthDate[2];
//check+if+month+has+passed
if($birthDate[1]+>+$currentDate[1]){
++++++//user+birthday+has+not+passed
++++++$age+=+$age+-+1;
}+else+if($birthDate[1]+==+$currentDate[1]){+
++++++//check+if+birthday+is+in+current+month
++++++if($birthDate[0]+>+$currentDate[0]){
++++++++++++$age+-+1;
++++++}


}
+++echo+$age;|code-block|syntax|javascript|923408|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The top answer for this is OK but only calualtes the year a person was born, I tweaked it for my own purposes to work out the day and month. But thought it was worth sharing.

This works by taken a timestamp of the the users DOB, but feel free to change that

<pre><code>$birthDate = date('d-m-Y',$usersDOBtimestamp);
$currentDate = date('d-m-Y', time());
//explode the date to get month, day and year
$birthDate = explode("-", $birthDate);
$currentDate = explode("-", $currentDate);
$birthDate[0] = ltrim($birthDate[0],'0');
$currentDate[0] = ltrim($currentDate[0],'0');
//that gets a rough age
$age = $currentDate[2] - $birthDate[2];
//check if month has passed
if($birthDate[1] &gt; $currentDate[1]){
 //user birthday has not passed
 $age = $age - 1;
} else if($birthDate[1] == $currentDate[1]){ 
 //check if birthday is in current month
 if($birthDate[0] &gt; $currentDate[0]){
 $age - 1;
 }


}
 echo $age;
</code></pre>

blocks|key|923298|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923299|<?php
++$birth_date+=+strtotime("1988-03-22");
++$now+=+time();
++$age+=+$now-$birth_date;
++$a+=+$age/60/60/24/365.25;
++echo+floor($a);
?>|code-block|syntax|javascript|923300|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this :

<pre><code>&lt;?php
 $birth_date = strtotime("1988-03-22");
 $now = time();
 $age = $now-$birth_date;
 $a = $age/60/60/24/365.25;
 echo floor($a);
?&gt;
</code></pre>

blocks|key|1137819|text|我使用以下方法来计算年龄：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1137820|$oDateNow+=+new+DateTime();
$oDateBirth+=+new+DateTime($sDateBirth);

//+New+interval
$oDateIntervall+=+$oDateNow->diff($oDateBirth);

//+Output
echo+$oDateIntervall->y;|code-block|syntax|javascript|1137821|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I use the following method to calculate age:

<pre><code>$oDateNow = new DateTime();
$oDateBirth = new DateTime($sDateBirth);

// New interval
$oDateIntervall = $oDateNow-&gt;diff($oDateBirth);

// Output
echo $oDateIntervall-&gt;y;
</code></pre>

blocks|key|923624|text|下面是计算年龄的简单函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923625|<?php
++++function+age($birthDate){
++++++//date+in+mm/dd/yyyy+format;+or+it+can+be+in+other+formats+as+well
++++++//explode+the+date+to+get+month,+day+and+year
++++++$birthDate+=+explode("/",+$birthDate);
++++++//get+age+from+date+or+birthdate
++++++$age+=+(date("md",+date("U",+mktime(0,+0,+0,+$birthDate[0],+$birthDate[1],+$birthDate[2])))+>+date("md")
++++++++?+((date("Y")+-+$birthDate[2])+-+1)
++++++++:+(date("Y")+-+$birthDate[2]));
+++++return+$age;
++++}

++++?>

++++<?php
++++echo+age('11/05/1991');
++++?>|code-block|syntax|javascript|923626|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

here's the simple function to calculate age:

<pre><code>&lt;?php
 function age($birthDate){
 //date in mm/dd/yyyy format; or it can be in other formats as well
 //explode the date to get month, day and year
 $birthDate = explode("/", $birthDate);
 //get age from date or birthdate
 $age = (date("md", date("U", mktime(0, 0, 0, $birthDate[0], $birthDate[1], $birthDate[2]))) &gt; date("md")
 ? ((date("Y") - $birthDate[2]) - 1)
 : (date("Y") - $birthDate[2]));
 return $age;
 }

 ?&gt;

 &lt;?php
 echo age('11/05/1991');
 ?&gt;
</code></pre>

blocks|key|923992|text|下面的过程更简单，适用于dd/mm/yyyy和dd-mm-yyyy格式。这对我来说非常有效：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|923993|++++<?php

+++++++$birthday+=+'26/04/1994';

+++++++$dob+=+strtotime(str_replace("/",+"-",+$birthday));
+++++++$tdate+=+time();
+++++++echo+date('Y',+$tdate)+-+date('Y',+$dob);

+++?>|code-block|syntax|javascript|923994|如果你关心你的时区，只需添加上面的date_default_timezone_set("Asia/Dhaka");，用你的时区改变时区。|offset|length|style|CODE|923995|entityMap^0|0|0|H|14|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Here is the process that is more simple and works both for the formats dd/mm/yyyy and dd-mm-yyyy. This is working great for me:

<pre><code> &lt;?php

 $birthday = '26/04/1994';

 $dob = strtotime(str_replace("/", "-", $birthday));
 $tdate = time();
 echo date('Y', $tdate) - date('Y', $dob);

 ?&gt;
</code></pre>

And if you care about your time zone just add above <code>date_default_timezone_set("Asia/Dhaka");</code> change the zone with yours.

blocks|key|923148|text|此函数运行良好。这是对Parkyprg代码的一个细微改进|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|923149|function+age($birthday){
+list($day,$month,$year)+=+explode("/",$birthday);
+$year_diff++=+date("Y")+-+$year;
+$month_diff+=+date("m")+-+$month;
+$day_diff+++=+date("d")+-+$day;
+if+($day_diff+<+0+&&+$month_diff==0){$year_diff--;}
+if+($day_diff+<+0+&&+$month_diff+<+0){$year_diff--;}
+return+$year_diff;
}|code-block|syntax|javascript|923150|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/users/347807/parkyprg^0|B|8|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

This function works fine. It's a slight imporvement of the code of <a href="https://stackoverflow.com/users/347807/parkyprg">Parkyprg</a>

<pre><code>function age($birthday){
 list($day,$month,$year) = explode("/",$birthday);
 $year_diff = date("Y") - $year;
 $month_diff = date("m") - $month;
 $day_diff = date("d") - $day;
 if ($day_diff &lt; 0 &amp;&amp; $month_diff==0){$year_diff--;}
 if ($day_diff &lt; 0 &amp;&amp; $month_diff &lt; 0){$year_diff--;}
 return $year_diff;
}
</code></pre>

I'm looking for a way to calculate the age of a person, given their DOB in the format dd/mm/yyyy.

I was using the following function which worked fine for several months until some kind of glitch caused the while loop to never end and grind the entire site to a halt. Since there are almost 100,000 DOBs going through this function several times a day, it's hard to pin down what was causing this.

Does anyone have a more reliable way of calculating the age?

<pre><code>//replace / with - so strtotime works
$dob = strtotime(str_replace("/","-",$birthdayDate)); 
$tdate = time();

$age = 0;
while( $tdate &gt; $dob = strtotime('+1 year', $dob))
{
 ++$age;
}
return $age;
</code></pre>

EDIT: this function seems to work OK some of the time, but returns "40" for a DOB of 14/09/1986

<pre><code>return floor((time() - strtotime($birthdayDate))/31556926);
</code></pre>

PHP calculate age

服务器

MySQL

我正在寻找一种计算一个人的年龄的方法，给定一个人的道布的格式为dd/mm/yyyy。我正在使用下面的函数，它在几个月内一直工作得很好，直到某种故障导致while循环永远不会结束，并使整个网站陷入停顿。由于每天有近100,000个DOB使用此功能数次，因此很难确定是什么原因造成了这种情况。有没有人有更可靠的计算年龄的方法？//replace / with - so strtotime works$d

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