blocks|key|1439667|text|PHP是一种解释型语言。用于解释PHP的二进制文件是编译的，但您编写的代码是解释的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1439668|您可以看到更多on+the+Wikipedia+page+for+Interpreted+languages|offset|length|1439669|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Interpreted_language^0|0|7|1B|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@$D|P|E|Q|1|R]]|A|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|M]]]]

PHP is an interpreted language. The binary that lets you interpret PHP is compiled, but what you write is interpreted.

You can see more <a href="http://en.wikipedia.org/wiki/Interpreted_language" rel="noreferrer">on the Wikipedia page for Interpreted languages</a>

blocks|key|1224974|text|PHP是一种解释型语言。不过，它可以被第三方工具编译成字节码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1224975|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

PHP is an interpreted language. It can be compiled to bytecode by third party-tools, though.

blocks|key|1439764|text|这是一个没有意义的问题。PHP使用yacc+(野牛)，就像GCC一样。yacc是一个“编译器编译器”。yacc的输出是一个编译器。编译器的输出是“编译”的。PHP由yacc的输出解析。因此，根据定义，它是编译的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1439765|如果这还不能令人满意，请考虑以下几点。php+(二进制)和gcc都会读取你的源代码并生成一个抽象的语法树。在版本4和版本5中，php然后遍历树以将程序转换为字节码(编译步骤)。您可以看到使用Vulcan+Logic+Dumper将字节码转换为操作码(类似于汇编)。最后，php+(特别是Zend引擎)解释字节码。相比之下，gcc遍历树并输出程序集；它还可以运行汇编器和链接器来完成该过程。将一个程序称为“解释”程序，而将另一个程序称为“编译程序”是没有意义的。毕竟，程序都是通过两者的“编译器”来运行的。|offset|length|1439766|实际上，你应该问你想问的问题。(“当PHP为每个请求重新编译我的源代码时，我是否要付出性能损失？”等等。)|1439767|entityMap|0|LINK|mutability|MUTABLE|url|http://derickrethans.nl/projects.html#vld^0|0|2N|J|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@$D|R|E|S|1|T]]|A|$]]|$1|F|3|G|5|6|7|U|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]]]

This is a meaningless question. PHP uses yacc (bison), just like GCC. yacc is a "compiler compiler". The output of yacc is a compiler. The output of a compiler is "compiled". PHP is parsed by the output of yacc. So it is, by definition, compiled.

If that doesn't satisfy, consider the following. Both php (the binary) and gcc read your source code and produce an abstract syntax tree. Under versions 4 and 5, php then walks the tree to translate the program to bytecode (the compilation step). You can see the bytecode translated to opcodes (which are analogous to assembly) using the <a href="http://derickrethans.nl/projects.html#vld" rel="noreferrer">Vulcan Logic Dumper</a>. Finally, php (in particular, the Zend engine) interprets the bytecode. gcc, in comparison, walks the tree and outputs assembly; it can also run assemblers and linkers to finish the process. Calling a program handled by one "interpreted" and another program handled by the other "compiled" is meaningless. After all, programs are both run through a "compiler" with both.

You should actually ask the question you want to ask instead. ("Do I pay a performance penalty as PHP recompiles my source code for every request?", etc.)

blocks|key|1225062|text|在一般情况下，它是解释的，但有时可以将其作为编译使用，并且它确实提高了性能。执行此操作的开源工具:+hhvm.com|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1225063|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

In generally it is interpreted, but some time can use it as compiled and it is really increases performance.
Open source tool to perform this operation:
hhvm.com

blocks|key|1439859|text|至少它不会像人们想要的那样编译(或者我应该说优化)代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1439860|这个代码..。|1439861|for($i=0;$i<100000000;$i%2B%2B);
echo+$i;|code-block|syntax|javascript|1439862|每次运行程序时，对程序执行...delays操作。|1439863|它可能已经检测到这是一个只需要第一次完成的计算。|1439864|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

At least it doesn't compile (or should I say optimize) the code as much as one might want it.

This code...

<pre><code>for($i=0;$i&lt;100000000;$i++);
echo $i;
</code></pre>

...delays the program equally much each time it is run.

It could have detected that it is a calculation that only needs to be done the first time.

blocks|key|1225180|text|公认的答案是彻头彻尾的错误。编译了PHP。故事到此结束。也许不是本机指令，而是解释字节码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1225181|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

The accepted answer is blatantly false. PHP IS compiled. End of story. Maybe not to native instructions but to an interpreted bytecode.

blocks|key|1225233|text|请记住，如果您每次都需要源代码来运行程序，这意味着它正在使用解释器。所以它是一种解释型语言。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1225234|另一方面，如果你编译了源代码并生成了你可以执行的编译代码，那么它就是在使用编译器。因为在这里你不需要源代码。像C、JAVA|1225235|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

Just keep in mind, if you need to source code every time to run the program, it means it is using Interpreter. So its an interpreted language.
On the other hand, if you compiled the source code and generate a compiled code which you can executed, then it is using complier. As here you don't need to source code. Like C, JAVA

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