如何在Bash中对数组进行切片
如何在Bash中对数组进行切片
提问于 2009-08-26 16:04:13
查看bash(1)手册页中的" array“部分，我找不到切分数组的方法。
所以我想出了这个过于复杂的函数：
#!/bin/bash
# @brief: slice a bash array
# @arg1: output-name
# @arg2: input-name
# @args: seq args
# ----------------------------------------------
function slice() {
local output=$1
local input=$2
shift 2
local indexes=$(seq $*)
local -i i
local tmp=$(for i in $indexes
do echo "$(eval echo \"\${$input[$i]}\")"
done)
local IFS=$'\n'
eval $output="( \$tmp )"
}如下所示：
$ A=( foo bar "a b c" 42 )
$ slice B A 1 2
$ echo "${B[0]}" # bar
$ echo "${B[1]}" # a b c有没有更好的方法来做这件事？
回答 3
Stack Overflow用户
回答已采纳
发布于 2009-08-26 17:10:34
请参阅Bash man页面中的Parameter Expansion部分。A[@]返回数组的内容，:1:2从索引1开始获取长度为2的片段。
A=( foo bar "a b c" 42 )
B=("${A[@]:1:2}")
C=("${A[@]:1}") # slice to the end of the array
echo "${B[@]}" # bar a b c
echo "${B[1]}" # a b c
echo "${C[@]}" # bar a b c 42
echo "${C[@]: -2:2}" # a b c 42 # The space before the - is necesssary注意，a b c是一个数组元素(并且它包含一个额外的空格)这一事实被保留下来。
Stack Overflow用户
发布于 2013-05-30 04:42:53
还有一个方便的快捷方式，可以获取从指定索引开始的数组的所有元素。例如，"${A@:1}“将是数组的”尾部“，即没有第一个元素的数组。
version=4.7.1
A=( ${version//\./ } )
echo "${A[@]}" # 4 7 1
B=( "${A[@]:1}" )
echo "${B[@]}" # 7 1Stack Overflow用户
发布于 2016-03-22 03:54:18
像Python中的数组切片(来自rebash库)：
array_slice() {
local __doc__='
Returns a slice of an array (similar to Python).
From the Python documentation:
One way to remember how slices work is to think of the indices as pointing
between elements, with the left edge of the first character numbered 0.
Then the right edge of the last element of an array of length n has
index n, for example:
```
+---+---+---+---+---+---+
| 0 | 1 | 2 | 3 | 4 | 5 |
+---+---+---+---+---+---+
0 1 2 3 4 5 6
-6 -5 -4 -3 -2 -1
```
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 1:-2 "${a[@]}")
1 2 3
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 0:1 "${a[@]}")
0
>>> local a=(0 1 2 3 4 5)
>>> [ -z "$(array.slice 1:1 "${a[@]}")" ] && echo empty
empty
>>> local a=(0 1 2 3 4 5)
>>> [ -z "$(array.slice 2:1 "${a[@]}")" ] && echo empty
empty
>>> local a=(0 1 2 3 4 5)
>>> [ -z "$(array.slice -2:-3 "${a[@]}")" ] && echo empty
empty
>>> [ -z "$(array.slice -2:-2 "${a[@]}")" ] && echo empty
empty
Slice indices have useful defaults; an omitted first index defaults to
zero, an omitted second index defaults to the size of the string being
sliced.
>>> local a=(0 1 2 3 4 5)
>>> # from the beginning to position 2 (excluded)
>>> echo $(array.slice 0:2 "${a[@]}")
>>> echo $(array.slice :2 "${a[@]}")
0 1
0 1
>>> local a=(0 1 2 3 4 5)
>>> # from position 3 (included) to the end
>>> echo $(array.slice 3:"${#a[@]}" "${a[@]}")
>>> echo $(array.slice 3: "${a[@]}")
3 4 5
3 4 5
>>> local a=(0 1 2 3 4 5)
>>> # from the second-last (included) to the end
>>> echo $(array.slice -2:"${#a[@]}" "${a[@]}")
>>> echo $(array.slice -2: "${a[@]}")
4 5
4 5
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice -4:-2 "${a[@]}")
2 3
If no range is given, it works like normal array indices.
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice -1 "${a[@]}")
5
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice -2 "${a[@]}")
4
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 0 "${a[@]}")
0
>>> local a=(0 1 2 3 4 5)
>>> echo $(array.slice 1 "${a[@]}")
1
>>> local a=(0 1 2 3 4 5)
>>> array.slice 6 "${a[@]}"; echo $?
1
>>> local a=(0 1 2 3 4 5)
>>> array.slice -7 "${a[@]}"; echo $?
1
'
local start end array_length length
if [[ $1 == *:* ]]; then
IFS=":"; read -r start end <<<"$1"
shift
array_length="$#"
# defaults
[ -z "$end" ] && end=$array_length
[ -z "$start" ] && start=0
(( start < 0 )) && let "start=(( array_length + start ))"
(( end < 0 )) && let "end=(( array_length + end ))"
else
start="$1"
shift
array_length="$#"
(( start < 0 )) && let "start=(( array_length + start ))"
let "end=(( start + 1 ))"
fi
let "length=(( end - start ))"
(( start < 0 )) && return 1
# check bounds
(( length < 0 )) && return 1
(( start < 0 )) && return 1
(( start >= array_length )) && return 1
# parameters start with $1, so add 1 to $start
let "start=(( start + 1 ))"
echo "${@: $start:$length}"
}
alias array.slice="array_slice"页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/1335815
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