blocks|key|1741575|text|radians+=+degrees+*+(pi/180)

degrees+=+radians+*+(180/pi)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1741576|至于实现，主要的问题是您希望对pi的值有多精确。有一些相关的讨论here|unstyled|offset|length|1741577|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/19/fastest-way-to-get-value-of-pi^0|0|W|4|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>radians = degrees * (pi/180)

degrees = radians * (180/pi)
</code></pre>

As for implementation, the main question is how precise you want to be about the value of pi. There is some related discussion <a href="https://stackoverflow.com/questions/19/fastest-way-to-get-value-of-pi">here</a>

blocks|key|1741679|text|以弧度表示的完整圆是2*pi。一个完整的圆的度数是360度。从度到弧度，它是(d/360)+*+2*pi，或d*pi/180。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1741680|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

a complete circle in radians is 2*pi. A complete circle in degrees is 360. To go from degrees to radians, it's (d/360) * 2*pi, or d*pi/180.

blocks|key|1741547|text|X+rads+(度)->+x*180/pi|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1741548|X度，以rads+->表示x*pi/180|1741549|我猜如果您想在PHP中为此创建一个函数|1741550|function+convert($type,+$num)+{
++++if+($type+==+"rads")+{
++++++++++$result+=+$num*180/pi();
++++++++}

++++if+($type+==+"degs")+{
++++++++++$result+=+$num*pi()/180;
++++++++}

++++return+$result;
++}|code-block|syntax|javascript|1741551|是的，这可能会写得更好。|1741552|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Q|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|R|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

x rads in degrees - > x*180/pi 
x degrees in rads -> x*pi/180 

I guess if you wanted to make a function for this [in PHP]:

<pre><code>function convert($type, $num) {
 if ($type == "rads") {
 $result = $num*180/pi();
 }

 if ($type == "degs") {
 $result = $num*pi()/180;
 }

 return $result;
 }
</code></pre>

Yes, that could probably be written better.

blocks|key|1526734|text|在javascript中你可以这样做。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526735|radians+=+degrees+*+(Math.PI/180);

degrees+=+radians+*+(180/Math.PI);|code-block|syntax|javascript|1526736|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In javascript you can do it this way

<pre><code>radians = degrees * (Math.PI/180);

degrees = radians * (180/Math.PI);
</code></pre>

blocks|key|1741748|text|这对我来说已经足够好用了:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1741749|//+deg2rad+*+degrees+=+radians
#define+deg2rad+(3.14159265/180.0)
//+rad2deg+*+radians+=+degrees
#define+rad2deg+(180/3.14159265)|code-block|syntax|javascript|1741750|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works well enough for me :)

<pre><code>// deg2rad * degrees = radians
#define deg2rad (3.14159265/180.0)
// rad2deg * radians = degrees
#define rad2deg (180/3.14159265)
</code></pre>

blocks|key|1741512|text|180度=+PI+*弧度|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1741513|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

blocks|key|1741623|text|360度是2*PI弧度|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1741624|您可以在http://en.wikipedia.org/wiki/Radian#Conversion_between_radians_and_degrees上找到转换公式。|offset|length|1741625|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Radian#Conversion_between_radians_and_degrees^0|0|4|22|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@$D|P|E|Q|1|R]]|A|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|M]]]]

360 degrees is 2*PI radians

You can find the conversion formulas at: <a href="http://en.wikipedia.org/wiki/Radian#Conversion_between_radians_and_degrees" rel="nofollow noreferrer">http://en.wikipedia.org/wiki/Radian#Conversion_between_radians_and_degrees</a>.

blocks|key|1741640|text|360度=2*π弧度|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1741641|即deg2rad(x)+=+x*pi/180，rad2deg(x)+=+180x/pi；|1741642|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

360 degrees = 2*pi radians

That means deg2rad(x) = x*pi/180 and rad2deg(x) = 180x/pi;

blocks|key|1526663|text|pi弧度=+180度|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526664|所以1度=π/180弧度|1526665|或1弧度=180/π度|1526666|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

pi Radians = 180 degrees

So 1 degree = pi/180 radians

or 1 radian = 180/pi degrees

blocks|key|1526756|text|对于c#中的double，这可能会很有帮助：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526757|++++++++public+static+double+Conv_DegreesToRadians(this+double+degrees)
++++++++{
++++++++++++//return+degrees+*+(Math.PI+/+180d);
++++++++++++return+degrees+*+0.017453292519943295d;
++++++++}
++++++++public+static+double+Conv_RadiansToDegrees(this+double+radians)
++++++++{
++++++++++++//return+radians+*+(180d+/+Math.PI);
++++++++++++return+radians+*+57.295779513082323d;
++++++++}|code-block|syntax|javascript|1526758|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For double in c# this might be helpful:

<pre><code> public static double Conv_DegreesToRadians(this double degrees)
 {
 //return degrees * (Math.PI / 180d);
 return degrees * 0.017453292519943295d;
 }
 public static double Conv_RadiansToDegrees(this double radians)
 {
 //return radians * (180d / Math.PI);
 return radians * 57.295779513082323d;
 }
</code></pre>

blocks|key|1741841|text|下面是一些代码，它们使用rad(deg)、deg(rad)和两个更有用的函数来扩展Object：getAngle(point1,point2)和getDistance(point1,point2)，其中一个点需要有一个x和y属性。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1741842|Object.prototype.rad+=+(deg)+=>+Math.PI/180+*+deg;
Object.prototype.deg+=+(rad)+=>+180/Math.PI+*+rad;
Object.prototype.getAngle+=+(point1,+point2)+=>+Math.atan2(point1.y+-+point2.y,+point1.x+-+point2.x);
Object.prototype.getDistance+=+(point1,+point2)+=>+Math.sqrt(Math.pow(point1.x-point2.x,+2)+%2B+Math.pow(point1.y-point2.y,+2));|code-block|syntax|javascript|1741843|entityMap^0|C|8|L|8|1C|N|20|Q|31|1|33|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|L|$]]

Here is some code which extends Object with <code>rad(deg)</code>, <code>deg(rad)</code> and also two more useful functions: <code>getAngle(point1,point2)</code> and <code>getDistance(point1,point2)</code> where a point needs to have a <code>x</code> and <code>y</code> property.

<pre><code>Object.prototype.rad = (deg) =&gt; Math.PI/180 * deg;
Object.prototype.deg = (rad) =&gt; 180/Math.PI * rad;
Object.prototype.getAngle = (point1, point2) =&gt; Math.atan2(point1.y - point2.y, point1.x - point2.x);
Object.prototype.getDistance = (point1, point2) =&gt; Math.sqrt(Math.pow(point1.x-point2.x, 2) + Math.pow(point1.y-point2.y, 2));
</code></pre>

blocks|key|1741720|text|radians+=+(degrees/360)+*+2+*+pi|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1741721|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>radians = (degrees/360) * 2 * pi
</code></pre>

I run into this occasionally and always forget how to do it.

One of those things that pop up ever so often.

Also, what's the formula to convert angles expressed in radians to degrees and back again?

What is the method for converting radians to degrees?

我偶尔会遇到这种情况，总是忘记该怎么做。一种经常出现的东西。另外，用弧度表示的角度和度之间的转换公式是什么？

问将弧度转换成度数的方法是什么？
EN

回答 12

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问将弧度转换成度数的方法是什么？EN

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问将弧度转换成度数的方法是什么？
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