blocks|key|688396|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|688397|$array+=+array_values($array);|code-block|syntax|javascript|688398|使用array_values()|offset|length|688399|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.array-values.php^0|0|0|2|E|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Try this:

<pre><code>$array = array_values($array);
</code></pre>

Using <a href="http://php.net/manual/en/function.array-values.php">array_values()</a>

blocks|key|688774|text|或者，您可以创建自己的函数，通过引用传递数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|688775|function+array_unset($unsets,+&$array)+{
++foreach+($array+as+$key+=>+$value)+{
++++foreach+($unsets+as+$unset)+{
++++++if+($value+==+$unset)+{
++++++++unset($array[$key]);
++++++++break;
++++++}
++++}
++}
++$array+=+array_values($array);
}|code-block|syntax|javascript|688776|所以你要做的就是..。|688777|$unsets+=+array(1,2);
array_unset($unsets,+$array);|688778|..。现在，您的$array没有您在$unsets中设置的值，并且密钥被重置|offset|length|style|CODE|688779|entityMap^0|0|0|0|0|8|6|I|7|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]|$M|Z|N|10|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

Or you can make your own function that passes the array by reference.

<pre><code>function array_unset($unsets, &amp;$array) {
 foreach ($array as $key =&gt; $value) {
 foreach ($unsets as $unset) {
 if ($value == $unset) {
 unset($array[$key]);
 break;
 }
 }
 }
 $array = array_values($array);
}
</code></pre>

So then all you have to do is...

<pre><code>$unsets = array(1,2);
array_unset($unsets, $array);
</code></pre>

... and now your <code>$array</code> is without the values you placed in <code>$unsets</code> and the keys are reset

blocks|key|688823|text|得到了另一个有趣的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|688824|$array+=+array('a',+'b',+'c',+'d');+
unset($array[2]);+

$array+=+array_merge($array);+|code-block|syntax|javascript|688825|现在，$array密钥被重置。|688826|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Got another interesting method: 

<pre><code>$array = array('a', 'b', 'c', 'd'); 
unset($array[2]); 

$array = array_merge($array); 
</code></pre>

Now the $array keys are reset.

blocks|key|905112|text|迟回答，但是，在PHP5.3之后可能是这样；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|905113|$array+=+array(1,+2,+3,+4,+5);
$array+=+array_values(array_filter($array,+function($v)+{
++++return+!($v+==+1+%7C%7C+$v+==+2);
}));
print_r($array);|code-block|syntax|javascript|905114|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Late answer but, after PHP 5.3 could be so;

<pre><code>$array = array(1, 2, 3, 4, 5);
$array = array_values(array_filter($array, function($v) {
 return !($v == 1 || $v == 2);
}));
print_r($array);
</code></pre>

blocks|key|688919|text|在我的情况下，我需要保留数组值的唯一键，所以我只使用了第二个数组：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|688920|$arr1+=+array("alpha"=>"bravo","charlie"=>"delta","echo"=>"foxtrot");
unset($arr1);

$arr2+=+array();
foreach($arr1+as+$key=>$value)+$arr2[$key]+=+$value;
$arr1+=+$arr2
unset($arr2);|code-block|syntax|javascript|688921|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In my situation, I needed to retain unique keys with the array values, so I just used a second array:

<pre><code>$arr1 = array("alpha"=&gt;"bravo","charlie"=&gt;"delta","echo"=&gt;"foxtrot");
unset($arr1);

$arr2 = array();
foreach($arr1 as $key=&gt;$value) $arr2[$key] = $value;
$arr1 = $arr2
unset($arr2);
</code></pre>

blocks|key|688979|text|我使用$arr+=+array_merge($arr);来改变数组的基址。简单明了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|688980|entityMap^0|3|P|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

I use <code>$arr = array_merge($arr);</code> to rebase an array. Simple and straightforward.

blocks|key|689031|text|100%25为我工作！取消设置数组中的元素后，可以使用此命令重新索引数组|type|unstyled|depth|inlineStyleRanges|entityRanges|data|689032|$result=array_combine(range(1,+count($your_array)),+array_values($your_array));|code-block|syntax|javascript|689033|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

100% working for me ! After unset elements in array you can use this for re-indexing the array 

<pre><code>$result=array_combine(range(1, count($your_array)), array_values($your_array));
</code></pre>

I have an array:

<pre><code>$array = array(1,2,3,4,5);
</code></pre>

If I were to dump the contents of the array they would look like this:

<pre><code>array(5) {
 [0] =&gt; int(1)
 [1] =&gt; int(2)
 [2] =&gt; int(3)
 [3] =&gt; int(4)
 [4] =&gt; int(5)
}
</code></pre>

When I loop through and unset certain keys, the index gets all jacked up. 

<pre><code>foreach($array as $i =&gt; $info)
{
 if($info == 1 || $info == 2)
 {
 unset($array[$i]);
 }
}
</code></pre>

Subsequently, if I did another dump now it would look like: 

<pre><code>array(3) {
 [2] =&gt; int(3)
 [3] =&gt; int(4)
 [4] =&gt; int(5)
}
</code></pre>

Is there a proper way to reset the array so it's elements are Zero based again ?? 

<pre><code>array(3) {
 [0] =&gt; int(3)
 [1] =&gt; int(4)
 [2] =&gt; int(5)
}
</code></pre>

Rebase array keys after unsetting elements

我有一个数组：$array = array(1,2,3,4,5);如果我转储数组的内容，它们将如下所示：array(5) {  [0] => int(1)  [1] => int(2)  [2] => int(3)  [3] => int(4)  [4] => int(5)}当我循环遍历和取消设置某些关键点时，索引变得...

问取消设置元素后重新设置数组键的基址
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