blocks|key|325624|text|查看Xpath+and+XSLT+with+lxml+from+the+lxml+documentation，它提供了包含文本的元素的路径|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|325625|一个例子就是|325626|import+cStringIO
from+lxml+import+etree

f+=+cStringIO.StringIO('<foo><bar><x1>hello</x1><x1>world</x1></bar></foo>')
tree+=+lxml.etree.parse(f)
find_text+=+etree.XPath("//text()")

#+and+print+out+the+required+data
print+[tree.getpath(+text.getparent())+for+text+in+find_text(tree)]

#+answer+I+get+is+
>>>+['/foo/bar/x1[1]',+'/foo/bar/x1[2]']|code-block|syntax|javascript|325627|entityMap|0|LINK|mutability|MUTABLE|url|http://lxml.de/xpathxslt.html^0|2|1G|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

See the <a href="http://lxml.de/xpathxslt.html" rel="noreferrer">Xpath and XSLT with lxml from the lxml documentation</a> This gives the path of the element containg the text

An example would be

<pre><code>import cStringIO
from lxml import etree

f = cStringIO.StringIO('&lt;foo&gt;&lt;bar&gt;&lt;x1&gt;hello&lt;/x1&gt;&lt;x1&gt;world&lt;/x1&gt;&lt;/bar&gt;&lt;/foo&gt;')
tree = lxml.etree.parse(f)
find_text = etree.XPath("//text()")

# and print out the required data
print [tree.getpath( text.getparent()) for text in find_text(tree)]

# answer I get is 
&gt;&gt;&gt; ['/foo/bar/x1[1]', '/foo/bar/x1[2]']
</code></pre>

blocks|key|3083532|text|从ElementTree对象使用getpath。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3083533|from+lxml+import+etree
++++
root+=+etree.fromstring('''
++++<foo><bar>Data</bar><bar><baz>data</baz>
++++<baz>data</baz></bar></foo>
++++''')
++++
tree+=+etree.ElementTree(root)
for+e+in+root.iter():
++++print(tree.getpath(e))|code-block|syntax|javascript|3083534|打印|3083535|/foo
/foo/bar[1]
/foo/bar[2]
/foo/bar[2]/baz[1]
/foo/bar[2]/baz[2]|3083536|entityMap|0|LINK|mutability|MUTABLE|url|http://lxml.de/api/lxml.etree._ElementTree-class.html#getpath^0|G|7|G|7|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

Use <a href="http://lxml.de/api/lxml.etree._ElementTree-class.html#getpath" rel="nofollow noreferrer"><code>getpath</code></a> from ElementTree objects.
<pre class="lang-py prettyprint-override"><code>from lxml import etree
 
root = etree.fromstring('''
 &lt;foo&gt;&lt;bar&gt;Data&lt;/bar&gt;&lt;bar&gt;&lt;baz&gt;data&lt;/baz&gt;
 &lt;baz&gt;data&lt;/baz&gt;&lt;/bar&gt;&lt;/foo&gt;
 ''')
 
tree = etree.ElementTree(root)
for e in root.iter():
 print(tree.getpath(e))
</code></pre>
Prints
<pre><code>/foo
/foo/bar[1]
/foo/bar[2]
/foo/bar[2]/baz[1]
/foo/bar[2]/baz[2]
</code></pre>

blocks|key|328238|text|root+=+etree.parse(open('tmp.txt'))

for+e+in+root.iter():
++++print+root.getpath(e)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|328239|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>root = etree.parse(open('tmp.txt'))

for e in root.iter():
 print root.getpath(e)
</code></pre>

blocks|key|327342|text|如果在您的代码段中只有元素，并且您想要元素的xpath，那么element.getroottree().getpath(element)就可以完成这项工作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|327343|from+lxml+import+etree

xml+=+'''
<test>
++++<a/>
++++
+++++++
+++++++<ii/>
++++
</test>
'''
tree+=+etree.fromstring(xml)

for+element+in+tree.iter():
++++print+element.getroottree().getpath(element)|code-block|syntax|javascript|327344|entityMap^0|U|12|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

If all you have in your section of code is the element and you want the element's xpath do then <code>element.getroottree().getpath(element)</code> will do the job.

<pre><code>from lxml import etree

xml = '''
&lt;test&gt;
 &lt;a/&gt;
 &lt;b&gt;
 &lt;i/&gt;
 &lt;ii/&gt;
 &lt;/b&gt;
&lt;/test&gt;
'''
tree = etree.fromstring(xml)

for element in tree.iter():
 print element.getroottree().getpath(element)
</code></pre>

I'm searching in a HTML document using XPath from lxml in python. How can I get the path to a certain element? Here's the example from ruby nokogiri:

<pre><code>page.xpath('//text()').each do |textnode|
 path = textnode.path
 puts path
end
</code></pre>

print for example '/html/body/div/div[1]/div[1]/p/text()[1]' and this is the string I want to get in python.

How to get path of an element in lxml?

我在python中使用lxml中的XPath在一个HTML文档中搜索。如何获取某个元素的路径？下面是ruby nokogiri的例子：page.xpath('//text()').each do |textnode|    path = textnode.path    puts pathend例如，打印'/html/...

问如何在lxml中获取元素的路径？
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