blocks|key|1744928|text|您可以使用Double.isInfinite(double)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1744929|这是double+doc|1744930|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/7/docs/api/java/lang/Double.html^0|5|P|0|2|A|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@$9|T|A|U|1|V]]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

You can use <code>Double.isInfinite(double)</code>
Here's <a href="http://docs.oracle.com/javase/7/docs/api/java/lang/Double.html" rel="noreferrer">double doc</a>

blocks|key|1958212|text|上面的代码产生|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1958213|ArithmeticException:+/+by+zero|code-block|syntax|javascript|1958214|您可以在try/catch块中捕获此异常。|1958215|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The above code produces

<pre><code>ArithmeticException: / by zero
</code></pre>

You can catch this exception in a try/catch block.

blocks|key|1958180|text|在Double类中有两个表示无穷大的字段：POSITIVE_INFINITY和NEGATIVE_INFINITY，您可以检查它们。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1958181|请注意，整数除以0会抛出一个ArithmeticException，因此您的代码行必须是4.0/0、4/0.0或4.0/0.0，因为4和0是整数，因此会导致整数数学运算。|1958182|entityMap^0|1|6|L|H|13|H|0|E|J|18|5|1E|5|1K|7|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|I|$]]

There are two fields for infinity in the <code>Double</code> class: <code>POSITIVE_INFINITY</code> and <code>NEGATIVE_INFINITY</code> which you can check for.

Note that integer division by zero would throw an <code>ArithmeticException</code> thus your line would have to be <code>4.0/0</code>, <code>4/0.0</code> or <code>4.0/0.0</code> since 4 and 0 are integers and thus result in integer math.

blocks|key|1744850|text|请查看是否等于Double.POSITIVE_INFINITY|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1744851|double+result;
result+=+4.0+/+0.0;|code-block|syntax|javascript|1744852|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Please see if it equal to Double.POSITIVE_INFINITY

<pre><code>double result;
result = 4.0 / 0.0;
</code></pre>

blocks|key|1745003|text|我复活了一个非常老的问题，因为它出现在我的Java类中。因此，我确信您尝试了他们都建议的try/catch，但您发现，像我一样，它在Double上不起作用。带有ArithmeticException的try/catch在Double或Float上不起作用，因为它们返回“无限”而不是返回异常。(注意，删除了我以前的“答案”，因为它不是答案)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1745004|将几个不同的问题/答案拼凑在一起，我提出了以下试验。|1745005|public+class+trial
{
++public+static+void+main(String[]+args)
++{
++++++double+a;
+++++try+{
++++++++++a+=+4/0;
+++++++++System.out.println("+The+answer+is+"+%2Ba);
++++++}+catch(ArithmeticException+e)+{
+++++System.out.println("+You+can't+divide+by+zero.+Please+try+again.");
++++++}
++}
}|code-block|syntax|javascript|1745006|上面的代码应该会给出“答案是无限”的结果。至少对我来说是这样的，因为它是一个double。|1745007|有了int，它就不需要下面的if语句了，因为它会抛出异常。但由于它是一个Double，下面的if语句将导致它抛出一个异常，catch将...好吧..。接住。|1745008|public+class+trial
{
public+static+void+main(String[]+args)
++{
++++++double+a;
++++++++++try+{
++++++++a+=+4/0;
+++//+if+statement+to+throw+an+AtithmeticException+if+ans+equals+infinity
++++++if(a+==+Double.POSITIVE_INFINITY){
++++++++++throw+new+ArithmeticException();

++++++++}
++++++++else{

++++++++++System.out.println("+The+answer+is+"+%2Ba);
++++++++}

++}+catch(ArithmeticException+e)+{
+++++System.out.println("+You+can't+divide+by+zero.+Please+try+again.");
++++}
++}
}|1745009|entityMap^0|1U|6|32|6|39|5|0|0|0|12|6|0|2|3|E|2|10|6|1A|2|1P|5|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]|$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|J|7|1H|8|@]|D|@]|E|$K|L]]|$1|S|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]]|T|$]]

Resurrecting a super old question because it came up in my Java class. So I'm sure you tried the try/catch like they all suggested, but you found, like me, that it didn't work with <code>Double</code>. The try/catch with ArithmeticException doesn't work on <code>Double</code> or <code>Float</code> since they return "Infinity" instead of returning an exception. (note, delted myold "answer" since it wasn't an answer).

Piecing together a few different questions/answers on this, I came up with the following trials.

<pre><code>public class trial
{
 public static void main(String[] args)
 {
 double a;
 try {
 a = 4/0;
 System.out.println(" The answer is " +a);
 } catch(ArithmeticException e) {
 System.out.println(" You can't divide by zero. Please try again.");
 }
 }
}
</code></pre>

The above code should give you the result "The answer is Infinity." At least it did for me since it is a <code>double</code>.

With an <code>int</code>, it would not need the below <code>if</code> statement since it would throw an exception. But since it is a <code>Double</code>, the <code>if</code> statement below will cause it to throw an exception which the <code>catch</code> will... well... catch.

<pre><code>public class trial
{
public static void main(String[] args)
 {
 double a;
 try {
 a = 4/0;
 // if statement to throw an AtithmeticException if ans equals infinity
 if(a == Double.POSITIVE_INFINITY){
 throw new ArithmeticException();

 }
 else{

 System.out.println(" The answer is " +a);
 }

 } catch(ArithmeticException e) {
 System.out.println(" You can't divide by zero. Please try again.");
 }
 }
}
</code></pre>

blocks|key|1744954|text|Jacek+Kwiecień试试这段代码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1744955|double+result;
try{
++++result=4.0/0.0;
}catch(ArithmeticException+e){

++++System.out.println("Math+error+"%2B+e.getMessage())
}|code-block|syntax|javascript|1744956|`|1744957|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Jacek Kwiecień try this code

<pre><code>double result;
try{
 result=4.0/0.0;
}catch(ArithmeticException e){

 System.out.println("Math error "+ e.getMessage())
}
</code></pre>

`

blocks|key|1744943|text|这种类型的错误称为异常。您可以使用try-catch块来捕获此异常。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1744944|+try{
++++++result+=+4/0;
+}
+catch(ArithmeticException+e){
+++++System.out.println("You+divided+by+zero");
+}|code-block|syntax|javascript|1744945|您可以阅读有关异常处理here的内容。|offset|length|1744946|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/tutorial/essential/exceptions/^0|0|0|B|4|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

This kind of errors are called exceptions. You can use try-catch block to catch this exception.

<pre><code> try{
 result = 4/0;
 }
 catch(ArithmeticException e){
 System.out.println("You divided by zero");
 }
</code></pre>

you can read about exception handling <a href="http://docs.oracle.com/javase/tutorial/essential/exceptions/" rel="nofollow">here</a>.

I'm making a simple calculator for this homework, and Java is returning "Infinity" when divided by 0.

I need to display some error message, when I get infinity. The problem is I don't know how to do the condition

<pre><code>double result;
result = 4/0;
//if result == infinity then some message - need help with this
</code></pre>

Check if a double is infinite in Java

Java

我正在为这个作业做一个简单的计算器，Java在除以0的时候会返回"Infinity“。当我得到无穷大时，我需要显示一些错误信息。问题是我不知道如何处理这个条件double result;result = 4/0;//if result == infinity then some message - need help with this

问检查double在Java中是否为无穷大
EN

回答 7

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问检查double在Java中是否为无穷大EN

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问检查double在Java中是否为无穷大
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