blocks|key|737884|text|查看静态java.util.Arrays.equals()方法系列。有一个可以做你想要的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|737885|entityMap|0|LINK|mutability|MUTABLE|url|http://download.oracle.com/javase/6/docs/api/java/util/Arrays.html#equals%2528byte%255B%255D,%2520byte%255B%255D%2529^0|4|P|4|P|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

Check out the static <a href="http://download.oracle.com/javase/6/docs/api/java/util/Arrays.html#equals%28byte%5B%5D,%20byte%5B%5D%29"><code>java.util.Arrays.equals()</code></a> family of methods. There's one that does exactly what you want.

blocks|key|737932|text|Java不重载运算符，因此您通常需要一个用于非基本类型的方法。尝试Arrays.equals()方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|737933|entityMap|0|LINK|mutability|MUTABLE|url|http://download.oracle.com/javase/1.4.2/docs/api/java/util/Arrays.html#equals%2528byte%255B%255D,%2520byte%255B%255D%2529^0|X|F|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Java doesn't overload operators, so you'll usually need a method for non-basic types. Try the <a href="http://download.oracle.com/javase/1.4.2/docs/api/java/util/Arrays.html#equals%28byte%5B%5D,%20byte%5B%5D%29" rel="noreferrer">Arrays.equals()</a> method.

blocks|key|953981|text|当然，Arrays.equal(+byte[]+first，byte[]+second+)的公认答案是正确的。我喜欢在较低的级别上工作，但我无法找到一个低级的有效函数来执行相等的测试范围。我不得不自己动手，如果有人需要的话：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|953982|public+static+boolean+ArraysAreEquals(
+byte[]+first,
+int+firstOffset,
+int+firstLength,
+byte[]+second,
+int+secondOffset,
+int+secondLength
)+{
++++if(+firstLength+!=+secondLength+)+{
++++++++return+false;
++++}

++++for(+int+index+=+0;+index+<+firstLength;+%2B%2Bindex+)+{
++++++++if(+first[firstOffset%2Bindex]+!=+second[secondOffset%2Bindex])+{
++++++++++++return+false;
++++++++}
++++}

++++return+true;
}|code-block|syntax|javascript|953983|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Of course, the accepted answer of Arrays.equal( byte[] first, byte[] second ) is correct.
I like to work at a lower level, but I was unable to find a low level efficient function to perform equality test ranges. I had to whip up my own, if anyone needs it:

<pre><code>public static boolean ArraysAreEquals(
 byte[] first,
 int firstOffset,
 int firstLength,
 byte[] second,
 int secondOffset,
 int secondLength
) {
 if( firstLength != secondLength ) {
 return false;
 }

 for( int index = 0; index &lt; firstLength; ++index ) {
 if( first[firstOffset+index] != second[secondOffset+index]) {
 return false;
 }
 }

 return true;
}
</code></pre>

blocks|key|954029|text|您可以同时使用Arrays.equals()和MessageDigest.isEqual()。但这两种方法有一些不同之处。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|954030|MessageDigest.isEqual()是一种时间常数比较方法，而Arrays.equals()是非时间常数的，如果在安全应用中使用它可能会带来一些安全问题。|954031|有关差异的详细信息，请访问Arrays.equals()+vs+MessageDigest.isEqual()|954032|entityMap|0|LINK|mutability|MUTABLE|url|http://www.pixelstech.net/article/1431658986-Arrays-equals%2528%2529-vs-MessageDigest-isEqual%2528%2529^0|7|F|N|N|0|0|N|10|F|0|D|16|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|11|8|@]|D|@$9|12|A|13|1|14]]|E|$]]|$1|J|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|K|$L|$5|M|N|O|E|$P|Q]]]]

You can use both <code>Arrays.equals()</code> and <code>MessageDigest.isEqual()</code>. These two methods have some differences though.

<code>MessageDigest.isEqual()</code> is a time-constant comparison method and <code>Arrays.equals()</code> is non time-constant and it may bring some security issues if you use it in a security application.

The details for the difference can be read at <a href="http://www.pixelstech.net/article/1431658986-Arrays-equals%28%29-vs-MessageDigest-isEqual%28%29">Arrays.equals() vs MessageDigest.isEqual()</a>

blocks|key|738209|text|因为我想在单元测试中比较两个数组，并且我得到了这个答案，所以我想我可以分享一下。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|738210|您也可以使用以下命令执行此操作：|738211|@Test
public+void+testTwoArrays()+{
++byte[]+array+=+new+BigInteger("1111000011110001",+2).toByteArray();
++byte[]+secondArray+=+new+BigInteger("1111000011110001",+2).toByteArray();

++Assert.assertArrayEquals(array,+secondArray);
}|code-block|syntax|javascript|738212|你可以在Comparing+arrays+in+JUnit+assertions上查看更多的信息。|offset|length|738213|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/4228161/comparing-arrays-in-junit-assertions-concise-built-in-way^0|0|0|0|4|10|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@$K|Y|L|Z|1|10]]|A|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Since I wanted to compare two arrays for a unit Test and I arrived on this answer I thought I could share.

You can also do it with:

<pre class="lang-java prettyprint-override"><code>@Test
public void testTwoArrays() {
 byte[] array = new BigInteger("1111000011110001", 2).toByteArray();
 byte[] secondArray = new BigInteger("1111000011110001", 2).toByteArray();

 Assert.assertArrayEquals(array, secondArray);
}
</code></pre>

And you could check on <a href="https://stackoverflow.com/questions/4228161/comparing-arrays-in-junit-assertions-concise-built-in-way">Comparing arrays in JUnit assertions</a> for more infos.

I have a byte array with a ~known binary sequence in it. I need to confirm that the binary sequence is what it's supposed to be. I have tried <code>.equals</code> in addition to <code>==</code>, but neither worked. 

<pre><code>byte[] array = new BigInteger("1111000011110001", 2).toByteArray();
if (new BigInteger("1111000011110001", 2).toByteArray() == array){
 System.out.println("the same");
} else {
 System.out.println("different'");
}
</code></pre>

Compare two Byte Arrays? (Java)

单元测试

Java

我有一个字节数组，其中包含一个已知的二进制序列。我需要确认二进制序列就是它应该是的样子。除了==之外，我还尝试过.equals，但都不起作用。byte[] array = new BigInteger("1111000011110001", 2).toByteArray();if (new BigInteger("11...

问比较两个字节数组？(Java)
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