blocks|key|1167993|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1167994|function+week_start_date($wk_num,+$yr,+$first+=+1,+$format+=+'F+d,+Y')
{
++++$wk_ts++=+strtotime('%2B'+.+$wk_num+.+'+weeks',+strtotime($yr+.+'0101'));
++++$mon_ts+=+strtotime('-'+.+date('w',+$wk_ts)+%2B+$first+.+'+days',+$wk_ts);
++++return+date($format,+$mon_ts);
}

$sStartDate+=+week_start_date($week_number,+$year);
$sEndDate+++=+date('F+d,+Y',+strtotime('%2B6+days',+strtotime($sStartDate)));|code-block|syntax|javascript|1167995|(来自this+forum+thread)|offset|length|1167996|entityMap|0|LINK|mutability|MUTABLE|url|http://www.phpbuilder.com/board/showthread.php?t=10222903^0|0|0|3|H|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Try this:

<pre><code>function week_start_date($wk_num, $yr, $first = 1, $format = 'F d, Y')
{
 $wk_ts = strtotime('+' . $wk_num . ' weeks', strtotime($yr . '0101'));
 $mon_ts = strtotime('-' . date('w', $wk_ts) + $first . ' days', $wk_ts);
 return date($format, $mon_ts);
}

$sStartDate = week_start_date($week_number, $year);
$sEndDate = date('F d, Y', strtotime('+6 days', strtotime($sStartDate)));
</code></pre>

(from <a href="http://www.phpbuilder.com/board/showthread.php?t=10222903" rel="nofollow noreferrer">this forum thread</a>)

blocks|key|1382979|text|您可以使用strptime()解析日期并对结果使用date()：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1382980|date('N',+strptime('%25m-%25d-%25g',+$dateString));|code-block|syntax|javascript|1382981|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.strptime.php|1|http://php.net/manual/en/function.date.php^0|5|A|P|6|5|A|0|P|6|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]|$9|12|A|13|1|14]]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

You parse the date using <a href="http://php.net/manual/en/function.strptime.php" rel="nofollow noreferrer"><code>strptime()</code></a> and use <a href="http://php.net/manual/en/function.date.php" rel="nofollow noreferrer"><code>date()</code></a> on the result:

<pre><code>date('N', strptime('%m-%d-%g', $dateString));
</code></pre>

blocks|key|1168050|text|$givenday+=+date("w",+mktime(0,+0,+0,+MM,+dd,+yyyy));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1168051|这将为您提供给定日期本身的星期几，其中0+=星期日，6+=星期六。从那里你可以简单地向后计算到你想要的那一天。|unstyled|offset|length|style|CODE|1168052|entityMap^0|0|J|1|Q|1|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>$givenday = date("w", mktime(0, 0, 0, MM, dd, yyyy));
</code></pre>

This gives you the day of the week of the given date itself where <code>0</code> = Sunday and <code>6</code> = Saturday. From there you can simply calculate backwards to the day you want.

blocks|key|1383046|text|这个怎么样？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383047|$first_day_of_week+=+date('m-d-Y',+strtotime('Last+Monday',+time()));
$last_day_of_week+=+date('m-d-Y',+strtotime('Next+Sunday',+time()));|code-block|syntax|javascript|1383048|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about this? 

<pre><code>$first_day_of_week = date('m-d-Y', strtotime('Last Monday', time()));
$last_day_of_week = date('m-d-Y', strtotime('Next Sunday', time()));
</code></pre>

blocks|key|1383079|text|strtotime('this+week',+time());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1383080|替换time()。下周日/上周一，当当前日期是周日/周一时，方法将不起作用。|unstyled|1383081|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>strtotime('this week', time());
</code></pre>

Replace time(). Next sunday/last monday methods won't work when the current day is sunday/monday.

blocks|key|1383092|text|这个怎么样？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383093|$day_of_week+=+date('N',+strtotime($string_date));
$week_first_day+=+date('Y-m-d',+strtotime($string_date+.+"+-+"+.+($day_of_week+-+1)+.+"+days"));
$week_last_day+=+date('Y-m-d',+strtotime($string_date+.+"+%2B+"+.+(7+-+$day_of_week)+.+"+days"));|code-block|syntax|javascript|1383094|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about this?

<pre><code>$day_of_week = date('N', strtotime($string_date));
$week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
$week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
</code></pre>

blocks|key|1168171|text|我已经几次遇到这个问题，总是感到惊讶的是，日期函数并没有让这个问题变得更容易或更清晰。下面是我使用DateTime类的PHP5解决方案：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1168172|/**
+*+@param+DateTime+$date+A+given+date
+*+@param+int+$firstDay+0-6,+Sun-Sat+respectively
+*+@return+DateTime
+*/
function+getFirstDayOfWeek(DateTime+$date,+$firstDay+=+0)+{
++++$offset+=+7+-+$firstDay;
++++$ret+=+clone+$date;
++++$ret->modify(-(($date->format('w')+%2B+$offset)+%25+7)+.+'days');
++++return+$ret;
}|code-block|syntax|javascript|1168173|必须克隆以避免更改原始日期。|1168174|entityMap^0|1D|8|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

I've come against this question a few times and always surprised the date functions don't make this easier or clearer. Here's my solution for PHP5 that uses the <code>DateTime</code> class:

<pre><code>/**
 * @param DateTime $date A given date
 * @param int $firstDay 0-6, Sun-Sat respectively
 * @return DateTime
 */
function getFirstDayOfWeek(DateTime $date, $firstDay = 0) {
 $offset = 7 - $firstDay;
 $ret = clone $date;
 $ret-&gt;modify(-(($date-&gt;format('w') + $offset) % 7) . 'days');
 return $ret;
}
</code></pre>

Necessary to clone to avoid altering the original date.

blocks|key|1168201|text|保持简单：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1168202|<?php++++
$dateTime+=+new+\DateTime('2020-04-01');
$monday+=+clone+$dateTime->modify(('Sunday'+==+$dateTime->format('l'))+?+'Monday+last+week'+:+'Monday+this+week');
$sunday+=+clone+$dateTime->modify('Sunday+this+week');++++
?>|code-block|syntax|javascript|1168203|来源：PHP+manual|offset|length|1168204|注意:正如一些用户评论的那样，$dateTime的值将会被修改。|1168205|entityMap|0|LINK|mutability|MUTABLE|url|http://fr2.php.net/manual/en/datetime.formats.relative.php^0|0|0|3|A|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@$I|X|J|Y|1|Z]]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

Keep it simple :

<pre><code>&lt;?php 
$dateTime = new \DateTime('2020-04-01');
$monday = clone $dateTime-&gt;modify(('Sunday' == $dateTime-&gt;format('l')) ? 'Monday last week' : 'Monday this week');
$sunday = clone $dateTime-&gt;modify('Sunday this week'); 
?&gt;
</code></pre>

Source : <a href="http://fr2.php.net/manual/en/datetime.formats.relative.php" rel="noreferrer">PHP manual</a>

NB: as some user commented the $dateTime value will be modified.

blocks|key|1383204|text|以下代码应该适用于任何自定义日期，只需使用所需的日期格式即可。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383205|$custom_date+=+strtotime(+date('d-m-Y',+strtotime('31-07-2012'))+);+
$week_start+=+date('d-m-Y',+strtotime('this+week+last+monday',+$custom_date));
$week_end+=+date('d-m-Y',+strtotime('this+week+next+sunday',+$custom_date));
echo+' Start:+'.+$week_start;
echo+' End:+'.+$week_end;|code-block|syntax|javascript|1383206|我用PHP+5.2.17测试了代码的结果：|1383207|Start:+30-07-2012
End:+05-08-2012|1383208|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The following code should work with any custom date, just uses the desired date format. 

<pre><code>$custom_date = strtotime( date('d-m-Y', strtotime('31-07-2012')) ); 
$week_start = date('d-m-Y', strtotime('this week last monday', $custom_date));
$week_end = date('d-m-Y', strtotime('this week next sunday', $custom_date));
echo '&lt;br&gt;Start: '. $week_start;
echo '&lt;br&gt;End: '. $week_end;
</code></pre>

I tested the code with PHP 5.2.17 Results:

<pre><code>Start: 30-07-2012
End: 05-08-2012
</code></pre>

blocks|key|1168251|text|在这里，我认为周日是一周的第一天，周六是一周的最后一天。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1168252|$m+=+strtotime('06-08-2012');++
$today+=+++date('l',+$m);++
$custom_date+=+strtotime(+date('d-m-Y',+$m)+);+++
if+($today+==+'Sunday')+{++
+++$week_start+=+date("d-m-Y",+$m);++
}+else+{++
++$week_start+=+date('d-m-Y',+strtotime('this+week+last+sunday',+$custom_date));++
}++

if+($today+==+'Saturday')+{++
++$week_end+=+date("d-m-Y",+$m);
}+else+{++
++$week_end+=+date('d-m-Y',+strtotime('this+week+next+saturday',+$custom_date));++
}
echo+' Start:+'.+$week_start;++
echo+' End:+'.+$week_end;++|code-block|syntax|javascript|1168253|输出：|1168254|开始时间:+05-08-2012|1168255|End:+11-08-2012|1168256|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Here I am considering Sunday as first &amp; Saturday as last day of the week. 

<pre><code>$m = strtotime('06-08-2012'); 
$today = date('l', $m); 
$custom_date = strtotime( date('d-m-Y', $m) ); 
if ($today == 'Sunday') { 
 $week_start = date("d-m-Y", $m); 
} else { 
 $week_start = date('d-m-Y', strtotime('this week last sunday', $custom_date)); 
} 

if ($today == 'Saturday') { 
 $week_end = date("d-m-Y", $m);
} else { 
 $week_end = date('d-m-Y', strtotime('this week next saturday', $custom_date)); 
}
echo '&lt;br&gt;Start: '. $week_start; 
echo '&lt;br&gt;End: '. $week_end; 
</code></pre>

Output :

Start: 05-08-2012 
 End: 11-08-2012

blocks|key|1383264|text|下面是什么：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383265|$date+=+"2013-03-18";+
$searchRow+=+date("d.m.Y",+strtotime('last+monday',strtotime($date."+%2B+1+day")));
echo+"for+date+"+.$date+."+we+get+this+monday:+"+;echo+$searchRow;+echo+' ';|code-block|syntax|javascript|1383266|这不是最好的方法，但我测试过了，如果我在这周，我会得到正确的周一，如果我在周一，我会得到那个周一。|1383267|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

What about:

<pre><code>$date = "2013-03-18"; 
$searchRow = date("d.m.Y", strtotime('last monday',strtotime($date." + 1 day")));
echo "for date " .$date ." we get this monday: " ;echo $searchRow; echo '&lt;br&gt;';
</code></pre>

Its not the best way but i tested and if i am in this week i get the correct monday, and if i am on a monday i will get that monday.

blocks|key|1168312|text|给定PHP+5.3之前的版本，下面的函数会给出给定日期的星期的第一天(在本例中是-星期日，2013-02-03)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1168313|<?php
++function+startOfWeek($aDate){
++++$d=strtotime($aDate);
++++return+strtotime(date('Y-m-d',$d).'+-+'.date("w",$d).'+days');
++}

++echo(date('Y-m-d',startOfWeek("2013-02-07")).'
');
?>|code-block|syntax|javascript|1168314|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Given PHP version pre 5.3 following function gives you a first day of the week of given date (in this case - Sunday, 2013-02-03):

<pre><code>&lt;?php
 function startOfWeek($aDate){
 $d=strtotime($aDate);
 return strtotime(date('Y-m-d',$d).' - '.date("w",$d).' days');
 }

 echo(date('Y-m-d',startOfWeek("2013-02-07")).'
');
?&gt;
</code></pre>

blocks|key|1383325|text|这个问题需要一个好的DateTime答案：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1383326|function+firstDayOfWeek($date)
{
++++$day+=+DateTime::createFromFormat('m-d-Y',+$date);
++++$day->setISODate((int)$day->format('o'),+(int)$day->format('W'),+1);
++++return+$day->format('m-d-Y');
}

var_dump(firstDayOfWeek('06-13-2013'));|code-block|syntax|javascript|1383327|输出：-|1383328|string+'06-10-2013'+(length=10)|1383329|这将处理年份边界和闰年。|1383330|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/datetime^0|A|8|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|11|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|C|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

This question needs a good <a href="http://php.net/datetime" rel="noreferrer">DateTime</a> answer:-

<pre><code>function firstDayOfWeek($date)
{
 $day = DateTime::createFromFormat('m-d-Y', $date);
 $day-&gt;setISODate((int)$day-&gt;format('o'), (int)$day-&gt;format('W'), 1);
 return $day-&gt;format('m-d-Y');
}

var_dump(firstDayOfWeek('06-13-2013'));
</code></pre>

Output:-

<pre><code>string '06-10-2013' (length=10)
</code></pre>

This will deal with year boundaries and leap years.

blocks|key|1168336|text|只需使用date($format,+strtotime($date,'+LAST+SUNDAY+%2B+1+DAY'));即可|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1168337|entityMap^0|4|1J|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Just use <code>date($format, strtotime($date,' LAST SUNDAY + 1 DAY'));</code>

blocks|key|1168353|text|$today_day+=+date('D');+//Or+add+your+own+date
$start_of_week+=+date('Ymd');
$end_of_week+=+date('Ymd');

if($today_day+!=+"Mon")
++++$start_of_week+=+date('Ymd',+strtotime("last+monday"));

if($today_day+!=+"Sun")
++++++++++++++++++++$end_of_week+=+date('Ymd',+strtotime("next+sunday"));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1168354|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$today_day = date('D'); //Or add your own date
$start_of_week = date('Ymd');
$end_of_week = date('Ymd');

if($today_day != "Mon")
 $start_of_week = date('Ymd', strtotime("last monday"));

if($today_day != "Sun")
 $end_of_week = date('Ymd', strtotime("next sunday"));
</code></pre>

blocks|key|1168364|text|另一种方法……|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1168365|$year+=+'2014';
$month+=+'02';
$day+=+'26';

$date+=+DateTime::createFromFormat('Y-m-d+H:i:s',+$year+.+'-'+.+$month+.+'-'+.+$day+.+'00:00:00');
$day+=+date('w',+$date->getTimestamp());

//+0=Sunday+6=Saturday
if($day!=0){

+++$newdate+=+$date->getTimestamp()+-+$day+*+86400;++//86400+seconds+in+a+day

+++//+Look+for+DST+change+
+++if($old+=+date('I',+$date->getTimestamp())+!=+$new+=+date('I',+$newdate)){
+++++++if($old+==+0){
+++++++++++$newdate+-=+3600;++//3600+seconds+in+an+hour
+++++++}+else+{
+++++++++++$newdate+%2B=+3600;
+++++++}
+++}

+++$date->setTimestamp($newdate);
}

echo+$date->format('D+Y-m-d+H:i:s');|code-block|syntax|javascript|1168366|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another way to do it....

<pre><code>$year = '2014';
$month = '02';
$day = '26';

$date = DateTime::createFromFormat('Y-m-d H:i:s', $year . '-' . $month . '-' . $day . '00:00:00');
$day = date('w', $date-&gt;getTimestamp());

// 0=Sunday 6=Saturday
if($day!=0){

 $newdate = $date-&gt;getTimestamp() - $day * 86400; //86400 seconds in a day

 // Look for DST change 
 if($old = date('I', $date-&gt;getTimestamp()) != $new = date('I', $newdate)){
 if($old == 0){
 $newdate -= 3600; //3600 seconds in an hour
 } else {
 $newdate += 3600;
 }
 }

 $date-&gt;setTimestamp($newdate);
}

echo $date-&gt;format('D Y-m-d H:i:s');
</code></pre>

blocks|key|1383408|text|我发现这个解决方案很有帮助。如果不是星期一，就减去前一个星期一的值。我使用$lower_date作为从查询中提取的日期，然后需要与前一个星期一进行核对。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383409|//set+this+up+to+go+backwards+until+you+find+monday
while(date('D',strtotime($lower_date))!='Mon'){
++++$lower_date+=+date('Y-m-d',+strtotime($lower_date+.+'+-+1+day'));+//increase+the+upper+spec
}|code-block|syntax|javascript|1383410|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I found this solution helpful. Just subtract if it isn't monday to get the previous Monday. I am using $lower_date as the date I pulled from a query that I then need to reconcile to the previous Monday.

<pre><code>//set this up to go backwards until you find monday
while(date('D',strtotime($lower_date))!='Mon'){
 $lower_date = date('Y-m-d', strtotime($lower_date . ' - 1 day')); //increase the upper spec
}
</code></pre>

blocks|key|1168431|text|这是为今天星期一准备的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1168432|function+lastMonday(\DateTime+$date)+{

++++$timestamp+=+$date->getTimestamp();

++++$monday+=+(+1+==+date(+'N',+$timestamp+));

++++if+($monday)+{
++++++++return+$timestamp;
++++}+else+{
++++++++return+strtotime(+'last+monday',+$timestamp+);
++++}
}|code-block|syntax|javascript|1168433|如果您想让它获得时间戳而不是DateTime，请更改前两行(去掉date->getTimestamp)，只需如下所示|1168434|function+lastMonday($timestamp)+{|1168435|如果您想让它输入字符串，请将前两行改为以下内容|1168436|function+lastMonday($dateString)+{

++++$timestamp+=+strtotime($dateString);|1168437|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

this one is prepared for today is monday

<pre><code>function lastMonday(\DateTime $date) {

 $timestamp = $date-&gt;getTimestamp();

 $monday = ( 1 == date( 'N', $timestamp ));

 if ($monday) {
 return $timestamp;
 } else {
 return strtotime( 'last monday', $timestamp );
 }
}
</code></pre>

if you want it to get timestamp instead of DateTime change first two lines 
(get rid of date->getTimestamp) 
change them to just this

<pre><code>function lastMonday($timestamp) {
</code></pre>

and if you want it to input string change first two lines to this

<pre><code>function lastMonday($dateString) {

 $timestamp = strtotime($dateString);
</code></pre>

blocks|key|1383517|text|我一直在寻找与此类似的解决方案，我终于想出了一个在本周的每一天都会返回的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383518|//set+current+timestamp
$today+=+time();
//calculate+the+number+of+days+since+Monday
$dow+=+date('w',+$today);
++$offset+=+$dow+-+1;
if+($offset+<+0)+{
++$offset+=+6;
++}
//calculate+timestamp+for+Monday+and+Sunday
$monday+=+$today+-+($offset+*+86400);
$tuesday+=+$monday+%2B+(1+*+86400);
$wednesday+=+$monday+%2B+(2+*+86400);
$thursday+=+$monday+%2B+(3+*+86400);
$friday+=+$monday+%2B+(4+*+86400);
$saturday+=+$monday+%2B+(5+*+86400);
$sunday+=+$monday+%2B+(6+*+86400);
//print+dates+for+Monday+and+Sunday+in+the+current+week
print+date("Y-m-d",+$monday)+.+"\n";
print+date("Y-m-d",+$tuesday)+.+"\n";
print+date("Y-m-d",+$wednesday)+.+"\n";
print+date("Y-m-d",+$thursday)+.+"\n";
print+date("Y-m-d",+$friday)+.+"\n";
print+date("Y-m-d",+$saturday)+.+"\n";
print+date("Y-m-d",+$sunday)+.+"\n";|code-block|syntax|javascript|1383519|感谢在这里发表文章的dbunic：http://www.redips.net/php/week-list-current-date/#comments|offset|length|1383520|entityMap|0|LINK|mutability|MUTABLE|url|http://www.redips.net/php/week-list-current-date/#comments^0|0|0|H|1M|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

I was searching for a solution similar to this and I finally came up with something that will return each day of the current week.

<pre><code>//set current timestamp
$today = time();
//calculate the number of days since Monday
$dow = date('w', $today);
 $offset = $dow - 1;
if ($offset &lt; 0) {
 $offset = 6;
 }
//calculate timestamp for Monday and Sunday
$monday = $today - ($offset * 86400);
$tuesday = $monday + (1 * 86400);
$wednesday = $monday + (2 * 86400);
$thursday = $monday + (3 * 86400);
$friday = $monday + (4 * 86400);
$saturday = $monday + (5 * 86400);
$sunday = $monday + (6 * 86400);
//print dates for Monday and Sunday in the current week
print date("Y-m-d", $monday) . "\n";
print date("Y-m-d", $tuesday) . "\n";
print date("Y-m-d", $wednesday) . "\n";
print date("Y-m-d", $thursday) . "\n";
print date("Y-m-d", $friday) . "\n";
print date("Y-m-d", $saturday) . "\n";
print date("Y-m-d", $sunday) . "\n";
</code></pre>

Thank you to dbunic who posted this here: <a href="http://www.redips.net/php/week-list-current-date/#comments" rel="nofollow">http://www.redips.net/php/week-list-current-date/#comments</a>

blocks|key|1383575|text|$monday+=+date('d-m-Y',strtotime('last+monday',strtotime('next+monday',strtotime($date))));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1383576|你必须先得到下周一，然后才能得到下周一的最后一个星期一。因此，如果给定的日期是星期一，它将返回相同的日期，而不是上周的星期一。|unstyled|1383577|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$monday = date('d-m-Y',strtotime('last monday',strtotime('next monday',strtotime($date))));
</code></pre>

You have to get next monday first then get the 'last monday' of next monday. So if the given date is monday it will return the same date not last week monday.

blocks|key|1168551|text|我使用它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1168552|$firstDate+=+date(+'Y-m-d',+strtotime(+'Last+Monday',+strtotime('-1+week')+));
$lastDate+=+date(+'Y-m-d',+strtotime(+'First+Sunday',+strtotime('-1+week')+));|code-block|syntax|javascript|1168553|希望这对你有帮助！|1168554|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I use it:

<pre><code>$firstDate = date( 'Y-m-d', strtotime( 'Last Monday', strtotime('-1 week') ));
$lastDate = date( 'Y-m-d', strtotime( 'First Sunday', strtotime('-1 week') ));
</code></pre>

Hope this help you!

blocks|key|1383648|text|获取当前周的第一天(星期一)的最简单方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383649|strtotime("next+Monday")+-+604800;|code-block|syntax|javascript|1383650|其中604800+-是一周内的秒数(60*60*24*7)。|1383651|这段代码将在下周一开始，并将其减少一周。这段代码在一周中的任何一天都能很好地工作。即使今天是星期一。|1383652|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The easiest way to get first day(Monday) of current week is: 

<pre><code>strtotime("next Monday") - 604800;
</code></pre>

where 604800 - is count of seconds in 1 week(60*60*24*7).

This code get next Monday and decrease it for 1 week. This code will work well in any day of week. Even if today is Monday.

blocks|key|1383704|text|这是我找到的最短且最具可读性的解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383705|++++<?php
++++$weekstart+=+strtotime('monday+this+week');
++++$weekstop+=+strtotime('sunday+this+week+23:59:59');
++++//echo+date('d.m.Y+H:i:s',+$weekstart)+.'+-+'.+date('d.m.Y+H:i:s',+$weekstop);
++++?>|code-block|syntax|javascript|1383706|strtotime比new+DateTime()->getTimestamp()更快。|offset|length|style|CODE|1383707|entityMap^0|0|0|0|9|A|U|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

This is the shortest and most readable solution I found:

<pre><code> &lt;?php
 $weekstart = strtotime('monday this week');
 $weekstop = strtotime('sunday this week 23:59:59');
 //echo date('d.m.Y H:i:s', $weekstart) .' - '. date('d.m.Y H:i:s', $weekstop);
 ?&gt;
</code></pre>

<code>strtotime</code> is faster than <code>new DateTime()-&gt;getTimestamp()</code>.

blocks|key|1383768|text|如果你想把周一作为一周的开始，你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383769|$date+=+'2015-10-12';
$day+=+date('N',+strtotime($date));
$week_start+=+date('Y-m-d',+strtotime('-'.($day-1).'+days',+strtotime($date)));
$week_end+=+date('Y-m-d',+strtotime('%2B'.(7-$day).'+days',+strtotime($date)));|code-block|syntax|javascript|1383770|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you want Monday as the start of your week, do this:

<pre><code>$date = '2015-10-12';
$day = date('N', strtotime($date));
$week_start = date('Y-m-d', strtotime('-'.($day-1).' days', strtotime($date)));
$week_end = date('Y-m-d', strtotime('+'.(7-$day).' days', strtotime($date)));
</code></pre>

blocks|key|1168808|text|假设星期一是一周的第一天，这是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1168809|echo+date("M-d-y",+strtotime('last+monday',+strtotime('next+week',+time())));|code-block|syntax|javascript|1168810|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Assuming Monday as the first day of the week, this works:

<pre><code>echo date("M-d-y", strtotime('last monday', strtotime('next week', time())));
</code></pre>

blocks|key|1383931|text|您也可以使用Carbon库|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1383932|$dateString+=+'02-21-2015';+//+example+in+format+MM-dd-yyyy
$date+=+Carbon::createFromFormat('m-d-Y',+$dateString);
$date->hour(0)->minute(0)->second(0)->startOfWeek();
$dateString+=+$date->Format('m-d-Y');+//+and+you+have+got+a+string+value+"02-16-2015"|code-block|syntax|javascript|1383933|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use Carbon library as well

<pre><code>$dateString = '02-21-2015'; // example in format MM-dd-yyyy
$date = Carbon::createFromFormat('m-d-Y', $dateString);
$date-&gt;hour(0)-&gt;minute(0)-&gt;second(0)-&gt;startOfWeek();
$dateString = $date-&gt;Format('m-d-Y'); // and you have got a string value "02-16-2015"
</code></pre>

blocks|key|1384050|text|这样做的一个聪明方法是让PHP处理时区差异和夏令时(DST)。让我向您展示如何做到这一点。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1384051|此函数将生成从周一到周五的所有天(包括周一到周五)(便于生成工作日)：|1384052|class+DateTimeUtilities+{
++++public+static+function+getPeriodFromMondayUntilFriday($offset+=+'now')+{
++++++++$now+=+new+\DateTimeImmutable($offset,+new+\DateTimeZone('UTC'));
++++++++$today+=+$now->setTime(0,+0,+1);

++++++++$daysFromMonday+=+$today->format('N')+-+1;

++++++++$monday+=+$today->sub(new+\DateInterval(sprintf('P%25dD',+$daysFromMonday)));
++++++++$saturday+=+$monday->add(new+\DateInterval('P5D'));

++++++++return+new+\DatePeriod($monday,+new+\DateInterval('P1D'),+$saturday);
++++}
}

foreach+(DateTimeUtilities::getPeriodFromMondayUntilFriday()+as+$day)+{
++++print+$day->format('c');
++++print+PHP_EOL;
}|code-block|syntax|javascript|1384053|这将返回当前周的星期一到星期五的日期时间。要对任意日期执行相同的操作，请将日期作为参数传递给DateTimeUtilities+::getPeriodFromMondayUntilFriday，如下所示：|offset|length|style|CODE|1384054|foreach+(DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21%2B00:00')+as+$day)+{
++++print+$day->format('c');
++++print+PHP_EOL;
}

//prints+
//2017-01-02T00:00:01%2B00:00
//2017-01-03T00:00:01%2B00:00
//2017-01-04T00:00:01%2B00:00
//2017-01-05T00:00:01%2B00:00
//2017-01-06T00:00:01%2B00:00|1384055|只对星期一感兴趣，就像特工问的那样？|1384056|$monday+=+DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21%2B00:00')->getStartDate()->format('c');
print+$monday;
//+prints
//2017-01-02T00:00:01%2B00:00|1384057|entityMap^0|0|0|0|1A|1E|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|Z|8|@$K|10|L|11|M|N]]|9|@]|A|$]]|$1|O|3|P|5|F|7|12|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|F|7|14|8|@]|9|@]|A|$G|H]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

A smart way of doing this is to let PHP handle timezone differences and Daylight Savings Time (DST). Let me show you how to do this.

This function will generate all days from Monday until Friday, inclusive (handy for generating work week days):

<pre><code>class DateTimeUtilities {
 public static function getPeriodFromMondayUntilFriday($offset = 'now') {
 $now = new \DateTimeImmutable($offset, new \DateTimeZone('UTC'));
 $today = $now-&gt;setTime(0, 0, 1);

 $daysFromMonday = $today-&gt;format('N') - 1;

 $monday = $today-&gt;sub(new \DateInterval(sprintf('P%dD', $daysFromMonday)));
 $saturday = $monday-&gt;add(new \DateInterval('P5D'));

 return new \DatePeriod($monday, new \DateInterval('P1D'), $saturday);
 }
}

foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday() as $day) {
 print $day-&gt;format('c');
 print PHP_EOL;
}
</code></pre>

This will return datetimes Monday-Friday for current week. To do the same for an arbitrary date, pass a date as a parameter to <code>DateTimeUtilities ::getPeriodFromMondayUntilFriday</code>, thus:

<pre><code>foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00') as $day) {
 print $day-&gt;format('c');
 print PHP_EOL;
}

//prints 
//2017-01-02T00:00:01+00:00
//2017-01-03T00:00:01+00:00
//2017-01-04T00:00:01+00:00
//2017-01-05T00:00:01+00:00
//2017-01-06T00:00:01+00:00
</code></pre>

Only interested in Monday, as the OP asked?

<pre><code>$monday = DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00')-&gt;getStartDate()-&gt;format('c');
print $monday;
// prints
//2017-01-02T00:00:01+00:00
</code></pre>

blocks|key|1384145|text|应该行得通：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1384146|/**
+*+Returns+start+of+most+recent+Sunday.
+*+
+*+@param+null%7Cint+$timestamp
+*+@return+int
+*/
public+static+function+StartOfWeek($timestamp+=+null)+{
++++if($timestamp+===+null)+$timestamp+=+time();
++++$dow+=+idate('w',+$timestamp);+//+Sunday+=+0,+Monday+=+1,+etc.
++++return+mktime(0,+0,+0,+idate('m',+$timestamp),+idate('d',+$timestamp)+-+$dow,+idate('Y',+$timestamp));
}|code-block|syntax|javascript|1384147|输入和输出是unix时间戳。使用date格式化。|offset|length|style|CODE|1384148|entityMap^0|0|0|G|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Should work:

<pre><code>/**
 * Returns start of most recent Sunday.
 * 
 * @param null|int $timestamp
 * @return int
 */
public static function StartOfWeek($timestamp = null) {
 if($timestamp === null) $timestamp = time();
 $dow = idate('w', $timestamp); // Sunday = 0, Monday = 1, etc.
 return mktime(0, 0, 0, idate('m', $timestamp), idate('d', $timestamp) - $dow, idate('Y', $timestamp));
}
</code></pre>

Input and output are unix timestamps. Use <code>date</code> to format.

blocks|key|1169155|text|这是作为DateTime对象的上周第一天和上周最后一天的一行代码。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1169156|$firstDay+=+(new+\DateTime())->modify(sprintf('-%25d+day',+date('w')+%2B+7))
+++++++++++++++++++++++++++++->setTime(0,+0,+0);
$lastDay+=+(new+\DateTime())->modify(sprintf('-%25d+day',+date('w')+%2B+1))
++++++++++++++++++++++++++++->setTime(23,+59,+59);|code-block|syntax|javascript|1169157|entityMap^0|4|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Here's a one liner for the first day of last week, and the last day of last week as a <code>DateTime</code> object.

<pre><code>$firstDay = (new \DateTime())-&gt;modify(sprintf('-%d day', date('w') + 7))
 -&gt;setTime(0, 0, 0);
$lastDay = (new \DateTime())-&gt;modify(sprintf('-%d day', date('w') + 1))
 -&gt;setTime(23, 59, 59);
</code></pre>

blocks|key|1384227|text|$string_date+=+'2019-07-31';
echo+$day_of_week+=+date('N',+strtotime($string_date));
echo+$week_first_day+=+date('Y-m-d',+strtotime($string_date+.+"+-+"+.+($day_of_week+-+1)+.+"+days"));
echo+$week_last_day+=+date('Y-m-d',+strtotime($string_date+.+"+%2B+"+.+(7+-+$day_of_week)+.+"+days"));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1384228|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$string_date = '2019-07-31';
echo $day_of_week = date('N', strtotime($string_date));
echo $week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
echo $week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
</code></pre>

blocks|key|1384279|text|为了拥有最简单的代码和从周一开始的几周时间，我使用了以下方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1384280|$day+=+(date('w')%2B6)%257;+//transform+week+start+from+sunday+to+monday
$time+=+strtotime('-'.$day.'+days');|code-block|syntax|javascript|1384281|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In order to have the simplest code and have weeks starting on monday, I used this method:

<pre><code>$day = (date('w')+6)%7; //transform week start from sunday to monday
$time = strtotime('-'.$day.' days');
</code></pre>

blocks|key|1169219|text|只需简单地回答一句话;)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1169220|$mondayThisWeek+=+new+Date($date+.+'this+week+monday');|code-block|syntax|javascript|1169221|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

just simply oneline answer ;)

<pre><code>$mondayThisWeek = new Date($date . 'this week monday');
</code></pre>

Given a date <code>MM-dd-yyyy</code> format, can someone help me get the first day of the week?

Get first day of week in PHP?

给出一个日期MM-dd-yyyy格式，有人能帮我得到一周的第一天吗？

问在PHP中获取一周的第一天？
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