blocks|key|278219|text|也许你想要做的是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|278220|string+combindedString+=+string.Join(+",",+myList.ToArray()+);|code-block|syntax|javascript|278221|您可以将"，“替换为要拆分列表中的元素的内容。|278222|编辑：正如评论中提到的，你也可以这样做|offset|length|style|BOLD|278223|string+combindedString+=+string.Join(+",",+myList);|278224|参考资料：|278225|Join<T>(String,+IEnumerable<T>)+
Concatenates+the+members+of+a+collection,+using+the+specified+separator+between+each+member.|278226|entityMap^0|0|0|0|0|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|Z|8|@$K|10|L|11|M|N]]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

Maybe you are trying to do 

<pre><code>string combindedString = string.Join( ",", myList.ToArray() );
</code></pre>

You can replace "," with what you want to split the elements in the list by.

Edit: As mention in the comments you could also do

<pre><code>string combindedString = string.Join( ",", myList);
</code></pre>

Reference:

<pre><code>Join&lt;T&gt;(String, IEnumerable&lt;T&gt;) 
Concatenates the members of a collection, using the specified separator between each member.
</code></pre>

blocks|key|283787|text|我将根据我的直觉，假设您想要连接在列表的每个元素上调用ToString的结果。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|283788|var+result+=+string.Join(",",+list.ToArray());|code-block|syntax|javascript|283789|entityMap^0|R|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I am going to go with my gut feeling and assume you want to concatenate the result of calling <code>ToString</code> on each element of the list.

<pre><code>var result = string.Join(",", list.ToArray());
</code></pre>

blocks|key|281896|text|您可以使用string.Join|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|281897|List<string>+list+=+new+List<string>()
{
++++"Red",
++++"Blue",
++++"Green"
};

string+output+=+string.Join(Environment.NewLine,+list.ToArray());++++
Console.Write(output);|code-block|syntax|javascript|281898|结果将是：|BOLD|281899|Red++++
Blue++++
Green|281900|作为Environment.NewLine的替代，您可以将其替换为您选择的基于字符串的行分隔符。|281901|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/57a79xd0%2528v=vs.110%2529.aspx|1|http://msdn.microsoft.com/en-us/library/system.environment.newline.aspx^0|5|B|5|B|0|0|0|0|5|0|0|2|J|2|J|1|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|F|3|G|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|18|8|@$9|19|A|1A|B|M]]|D|@]|E|$]]|$1|N|3|O|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|P|3|Q|5|6|7|1C|8|@$9|1D|A|1E|B|C]]|D|@$9|1F|A|1G|1|1H]]|E|$]]|$1|R|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]]|S|$T|$5|U|V|W|E|$X|Y]]|Z|$5|U|V|W|E|$X|10]]]]

You could use <a href="http://msdn.microsoft.com/en-us/library/57a79xd0%28v=vs.110%29.aspx" rel="noreferrer"><code>string.Join</code></a>:

<pre><code>List&lt;string&gt; list = new List&lt;string&gt;()
{
 "Red",
 "Blue",
 "Green"
};

string output = string.Join(Environment.NewLine, list.ToArray()); 
Console.Write(output);
</code></pre>

The result would be:

<pre><code>Red 
Blue 
Green
</code></pre>

As an alternative to <a href="http://msdn.microsoft.com/en-us/library/system.environment.newline.aspx" rel="noreferrer"><code>Environment.NewLine</code></a>, you can replace it with a string based line-separator of your choosing.

blocks|key|278267|text|如果你想要比简单的连接稍微复杂一点的东西，你可以使用LINQ。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|278268|var+result+=+myList.Aggregate((total,+part)+=>+total+%2B+"("+%2B+part.ToLower()+%2B+")");|code-block|syntax|javascript|278269|将取"A“、"B”、"C“并产生"(a)(b)(c)”|278270|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you want something slightly more complex than a simple join you can use LINQ e.g.

<pre><code>var result = myList.Aggregate((total, part) =&gt; total + "(" + part.ToLower() + ")");
</code></pre>

Will take ["A", "B", "C"] and produce "(a)(b)(c)"

blocks|key|2990111|text|String.Join("+",+myList)或String.Join("+",+myList.ToArray())。第一个参数是子字符串之间的分隔符。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2990112|var+myList+=+new+List<String>+{+"foo","bar","baz"};
Console.WriteLine(String.Join("-",+myList));+//+prints+"foo-bar-baz"|code-block|syntax|javascript|2990113|根据您的.NET版本，您可能需要首先在列表中使用ToArray()。|2990114|entityMap^0|0|O|P|Y|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

<code>String.Join(" ", myList)</code> or <code>String.Join(" ", myList.ToArray())</code>. The first argument is the separator between the substrings.

<pre><code>var myList = new List&lt;String&gt; { "foo","bar","baz"};
Console.WriteLine(String.Join("-", myList)); // prints "foo-bar-baz"
</code></pre>

Depending on your version of .NET you might need to use ToArray() on the list first..

blocks|key|280140|text|你有一个List<string>+--所以如果你想把它们连接起来，就像这样|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|280141|string+s+=+string.Join("",+list);|code-block|syntax|javascript|280142|可以工作(至少在.NET+4.0中)。第一个参数是分隔符。所以你也可以用逗号分隔等等。|280143|您可能还希望考虑使用StringBuilder来执行运行连接，而不是形成一个列表。|280144|entityMap^0|4|C|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|V|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

You have a <code>List&lt;string&gt;</code> - so if you want them concatenated, something like

<pre><code>string s = string.Join("", list);
</code></pre>

would work (in .NET 4.0 at least). The first parameter is the delimiter. So you could also comma-delimit etc.

You might also want to look at using StringBuilder to do running concatenations, rather than forming a list.

blocks|key|280134|text|除非在派生类型中重写引用类型的.ToString()方法(可能使用内置类型的扩展方法)，否则它通常会解析回System.Object.ToString()。此方法的默认行为是输出调用它的类型的名称。所以你看到的是预期的行为。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|280135|你可以尝试像string.Join(",+",+myList.ToArray());这样的东西来实现这一点。这是一个额外的步骤，但可以将其放在System.Collections.Generic.List<T>的扩展方法中，以使其更容易一些。如下所示：|280136|public+static+class+GenericListExtensions
{
++++public+static+string+ToString<T>(this+IList<T>+list)
++++{
++++++++return+string.Join(",+",+list);
++++}
}|code-block|syntax|javascript|280137|(请注意，这是徒手编写的未经测试的代码。目前我手头还没有编译器。因此，您将希望对其进行一点实验。)|280138|entityMap^0|F|B|1H|O|0|6|10|1Z|Y|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|11|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|P|$]]

The <code>.ToString()</code> method for reference types usually resolves back to <code>System.Object.ToString()</code> unless you override it in a derived type (possibly using extension methods for the built-in types). The default behavior for this method is to output the name of the type on which it's called. So what you're seeing is expected behavior.

You could try something like <code>string.Join(", ", myList.ToArray());</code> to achieve this. It's an extra step, but it could be put in an extension method on <code>System.Collections.Generic.List&lt;T&gt;</code> to make it a bit easier. Something like this:

<pre><code>public static class GenericListExtensions
{
 public static string ToString&lt;T&gt;(this IList&lt;T&gt; list)
 {
 return string.Join(", ", list);
 }
}
</code></pre>

(Note that this is free-hand and untested code. I don't have a compiler handy at the moment. So you'll want to experiment with it a little.)

blocks|key|2990011|text|很难说，但也许你正在寻找类似这样的东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2990012|var+myString+=+String.Join(String.Empty,+myList.ToArray());|code-block|syntax|javascript|2990013|这将对列表中的每个项目隐式调用ToString()方法，并将它们连接起来。|2990014|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

It's hard to tell, but perhaps you're looking for something like:

<pre><code>var myString = String.Join(String.Empty, myList.ToArray());
</code></pre>

This will implicitly call the ToString() method on each of the items in the list and concatenate them.

blocks|key|2989961|text|如果您希望将列表中的项转换为一个很长的字符串，请执行以下操作：String.Join("",+myList)。有些旧版本的框架不允许将IEnumerable作为第二个参数传递，因此可能需要通过调用.ToArray()将列表转换为数组。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2989962|entityMap^0|V|N|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

If you're looking to turn the items in a list into a big long string, do this: <code>String.Join("", myList)</code>. Some older versions of the framework don't allow you to pass an IEnumerable as the second parameter, so you may need to convert your list to an array by calling .ToArray().

blocks|key|2990149|text|正如其他人所提到的，对您的问题的直接答案是String.Join。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2990150|但是，如果您需要一些操作，则可以使用Aggregate|2990151|List<string>+employees+=+new+List<string>();
employees.Add("e1");
employees.Add("e2");
employees.Add("e3");

string+employeesString+=+"'"+%2B+employees.Aggregate((x,+y)+=>+x+%2B+"','"+%2B+y)+%2B+"'";
Console.WriteLine(employeesString);
Console.ReadLine();|code-block|syntax|javascript|2990152|entityMap^0|L|B|0|I|9|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|U|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

The direct answer to your question is <code>String.Join</code> as others have mentioned.

However, if you need some manipulations, you can use <code>Aggregate</code>:

<pre><code>List&lt;string&gt; employees = new List&lt;string&gt;();
employees.Add("e1");
employees.Add("e2");
employees.Add("e3");

string employeesString = "'" + employees.Aggregate((x, y) =&gt; x + "','" + y) + "'";
Console.WriteLine(employeesString);
Console.ReadLine();
</code></pre>

blocks|key|2990166|text|在尝试从文本文件中检索数据并将其存储在Array中，然后将其分配给string+avariable时，此方法很有帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2990167|string[]+lines+=+File.ReadAllLines(Environment.CurrentDirectory+%2B+"\\Notes.txt");++
string+marRes+=+string.Join(Environment.NewLine,+lines.ToArray());|code-block|syntax|javascript|2990168|希望能帮助到一些人！|2990169|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This method helped me when trying to retrieve data from Text File and store it in Array then Assign it to a string avariable.

<pre><code>string[] lines = File.ReadAllLines(Environment.CurrentDirectory + "\\Notes.txt"); 
string marRes = string.Join(Environment.NewLine, lines.ToArray());
</code></pre>

Hopefully may help Someone!!!!

blocks|key|3203871|text|这似乎对我很有效。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3203872|var+combindedString+=+new+string(list.ToArray());|code-block|syntax|javascript|3203873|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This seems to work for me.

<pre><code>var combindedString = new string(list.ToArray());
</code></pre>

blocks|key|281931|text|如果您的列表包含字段/属性，并且您希望使用特定值(例如FirstName)，则可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|281932|string+combindedString+=+string.Join(+",",+myList.Select(t=>t.FirstName).ToArray()+);|code-block|syntax|javascript|281933|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If your list has fields/properties and you want to use a specific value (e.g. FirstName), then you can do this:
<pre><code>string combindedString = string.Join( &quot;,&quot;, myList.Select(t=&gt;t.FirstName).ToArray() );
</code></pre>

blocks|key|3203909|text|string+strs="111,222,333"
string.Join(",",strs.Split(',').ToList().Select(x=>x.PadLeft(6,'0')).ToArray());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3203910|输出|unstyled|3203911|000111,000222,000333|3203912|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>string strs=&quot;111,222,333&quot;
string.Join(&quot;,&quot;,strs.Split(',').ToList().Select(x=&gt;x.PadLeft(6,'0')).ToArray());
</code></pre>
The output
<pre><code>000111,000222,000333
</code></pre>

How do I convert a list to a string in C#?

When I execute <code>toString</code> on a List object, I get:

<blockquote>
 System.Collections.Generic.List`1[System.String]
</blockquote>

Convert a list to a string in C#

编译器

如何在C#中将列表转换为字符串？当我在List对象上执行toString时，我得到： System.Collections.Generic.List`1System.String

问在C#中将列表转换为字符串
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回答 14

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