blocks|key|606263|text|我认为您应该使用hasClass()|type|unstyled|depth|inlineStyleRanges|entityRanges|data|606264|$('li.menu').hasClass('active');|code-block|syntax|javascript|606265|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I think you want to use hasClass()

<pre><code>$('li.menu').hasClass('active');
</code></pre>

blocks|key|821525|text|您可以使用以下命令检索具有“active”类的所有元素：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|821526|$('.active')|code-block|syntax|javascript|821527|看看有没有，我相信，有没有|821528|if($('.active').length+>+0)
{
++++//+code
}|821529|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can retrieve all elements having the 'active' class using the following:

<pre><code>$('.active')
</code></pre>

Checking wether or not there are any would, i belief, be with 

<pre><code>if($('.active').length &gt; 0)
{
 // code
}
</code></pre>

blocks|key|821502|text|$('li.menu.active')|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|821503|是最简单的方法。这将返回包含两个类的所有元素。|unstyled|821504|或已应答的jQuery+hasClass()+-+check+for+more+than+one+class|offset|length|821505|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/2214952/jquery-hasclass-check-for-more-than-one-class/2214962#2214962^0|0|0|5|1D|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|F|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

<pre><code>$('li.menu.active')
</code></pre>

is the simplest way. This will return all elements with both classes.

Or an already answered <a href="https://stackoverflow.com/questions/2214952/jquery-hasclass-check-for-more-than-one-class/2214962#2214962">jQuery hasClass() - check for more than one class</a>

blocks|key|606403|text|你可以使用hasClass方法，例如。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|606404|$('li.menu').hasClass('active')+//+true%7Cfalse|code-block|syntax|javascript|606405|或者，如果你想一次选择它，你可以使用：|606406|$('li.menu.active')|606407|entityMap^0|5|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

You can use the <code>hasClass</code> method, eg.

<pre><code>$('li.menu').hasClass('active') // true|false
</code></pre>

Or if you want to select it in one go, you can use:

<pre><code>$('li.menu.active')
</code></pre>

blocks|key|606477|text|++++if($('selector').hasClass('active')){+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|606478|我想这会检查选择器hasClass是否激活...|unstyled|606479|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code> if($('selector').hasClass('active')){ }
</code></pre>

i think this will check if the selector hasClass active ...

blocks|key|821704|text|$(document).ready(function()
{
++changeColor+=+$(.active).css("color","any+color");
++if($(".classname").hasClass('active'))+{
++$(this).eq(changeColor);
++}
});|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|821705|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$(document).ready(function()
{
 changeColor = $(.active).css("color","any color");
 if($(".classname").hasClass('active')) {
 $(this).eq(changeColor);
 }
});
</code></pre>

blocks|key|821450|text|使用hasClass+jQuery方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|821451|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

blocks|key|606457|text|如果要检查条件，当前类是否处于活动状态|type|unstyled|depth|inlineStyleRanges|entityRanges|data|606458|$('#next').click(function(){
++++if($('p:last').hasClass('active'){
+++++++$('.active').removeClass();
++++}else{
+++++++$('.active').addClass();
++++}
});|code-block|syntax|javascript|606459|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<h2>If Condition to check, currently class active or not</h2>

<pre><code>$('#next').click(function(){
 if($('p:last').hasClass('active'){
 $('.active').removeClass();
 }else{
 $('.active').addClass();
 }
});
</code></pre>

blocks|key|821682|text|我编写了一个helper方法来帮助我遍历所有选定的元素并删除活动类。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|821683|++++function+removeClassFromElem(classSelect,+classToRemove){
++++++$(classSelect).each(function(){
++++++++var+currElem=$(this);
++++++++if(currElem.hasClass(classToRemove)){
++++++++++currElem.removeClass(classToRemove);
++++++++}
++++++});
++++}

++++//usage
++++removeClassFromElem('.someclass',+'active');|code-block|syntax|javascript|821684|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

i wrote a helper method to help me go through all my selected elements and remove the active class.

<pre><code> function removeClassFromElem(classSelect, classToRemove){
 $(classSelect).each(function(){
 var currElem=$(this);
 if(currElem.hasClass(classToRemove)){
 currElem.removeClass(classToRemove);
 }
 });
 }

 //usage
 removeClassFromElem('.someclass', 'active');
</code></pre>

Check if a class <code>active</code> exist on an <code>li</code> with a class <code>menu</code>

For example

<pre><code>&lt;li class="menu active"&gt;something...&lt;/li&gt;
</code></pre>

Check if a class `active` exist on element with jquery

jQuery

检查具有类active的li上是否存在类menu例如<li class="menu active">something...</li>

问使用jquery检查元素上是否存在类`active`
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