blocks|key|1785944|text|将ll+(el-el)+long-long修饰符与u(无符号)转换一起使用。(适用于windows、GNU)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1785945|printf("%25llu",+285212672);|code-block|syntax|javascript|1785946|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use the ll (el-el) long-long modifier with the u (unsigned) conversion. (Works in windows, GNU).

<pre><code>printf("%llu", 285212672);
</code></pre>

blocks|key|1571210|text|您可能希望尝试使用为您提供int32_t、int64_t、uint64_t等类型的inttypes.h库。然后，您可以使用其宏，例如：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1571211|uint64_t+x;
uint32_t+y;

printf("x:+%25"PRId64",+y:+%25"PRId32"\n",+x,+y);|code-block|syntax|javascript|1571212|这“保证”不会给你带来与long、unsigned+long+long等相同的麻烦，因为你不必猜测每种数据类型有多少位。|1571213|entityMap^0|D|7|L|7|T|8|0|0|C|4|H|I|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|N|$]]

You may want to try using the inttypes.h library that gives you types such as
<code>int32_t</code>, <code>int64_t</code>, <code>uint64_t</code> etc.
You can then use its macros such as:

<pre><code>uint64_t x;
uint32_t y;

printf("x: %"PRId64", y: %"PRId32"\n", x, y);
</code></pre>

This is "guaranteed" to not give you the same trouble as <code>long</code>, <code>unsigned long long</code> etc, since you don't have to guess how many bits are in each data type.

blocks|key|1571503|text|用于int的%25d-->|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1571504|用于unsigned+int的%25u-->|1571505|用于long+int或long的%25ld-->|1571506|%25lu-->适用于unsigned+long+int、long+unsigned+int或unsigned+long|1571507|用于long+long+int或long+long的%25lld-->|1571508|用于unsigned+long+long+int或unsigned+long+long的%25llu-->|1571509|entityMap^0|2|3|6|2|0|2|C|F|2|0|2|8|B|4|G|3|0|0|3|9|H|R|H|19|D|0|2|D|G|9|Q|4|0|2|M|P|I|18|4|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|18|8|@$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]|$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|L|3|M|5|6|7|1H|8|@$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]]|D|@]|E|$]]|$1|N|3|O|5|6|7|1O|8|@$9|1P|A|1Q|B|C]|$9|1R|A|1S|B|C]|$9|1T|A|1U|B|C]]|D|@]|E|$]]|$1|P|3|-4|5|6|7|1V|8|@]|D|@]|E|$]]]|Q|$]]

<code>%d</code>--> for <code>int</code>

<code>%u</code>--> for <code>unsigned int</code>

<code>%ld</code>--> for <code>long int</code> or <code>long</code>

<code>%lu</code>--> for <code>unsigned long int</code> or <code>long unsigned int</code> or <code>unsigned long</code>

<code>%lld</code>--> for <code>long long int</code> or <code>long long</code>

<code>%llu</code>--> for <code>unsigned long long int</code> or <code>unsigned long long</code>

blocks|key|1571455|text|对于使用MSVS的long+long+(或__int64)，您应该使用%25I64d：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1571456|__int64+a;
time_t+b;
...
fprintf(outFile,"%25I64d,%25I64d\n",a,b);++++//I+is+capital+i|code-block|syntax|javascript|1571457|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For long long (or __int64) using MSVS, you should use %I64d:

<pre><code>__int64 a;
time_t b;
...
fprintf(outFile,"%I64d,%I64d\n",a,b); //I is capital i
</code></pre>

blocks|key|1786208|text|这是因为%25llu在Windows下无法正常工作，并且%25d无法处理64位整数。我建议使用PRIu64，你会发现它也可以移植到Linux上。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1786209|试着这样做：|1786210|#include+<stdio.h>
#include+<inttypes.h>

int+main()+{
++++unsigned+long+long+int+num+=+285212672;+//FYI:+fits+in+29+bits
++++int+normalInt+=+5;
++++/*+NOTE:+PRIu64+is+a+preprocessor+macro+and+thus+should+go+outside+the+quoted+string.+*/
++++printf("My+number+is+%25d+bytes+wide+and+its+value+is+%25"+PRIu64+".+A+normal+number+is+%25d.\n",+sizeof(num),+num,+normalInt);
++++return+0;
}|code-block|syntax|javascript|1786211|输出|1786212|My+number+is+8+bytes+wide+and+its+value+is+285212672.+A+normal+number+is+5.|1786213|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

That is because %llu doesn't work properly under Windows and %d can't handle 64 bit integers. I suggest using PRIu64 instead and you'll find it's portable to Linux as well.

Try this instead:

<pre><code>#include &lt;stdio.h&gt;
#include &lt;inttypes.h&gt;

int main() {
 unsigned long long int num = 285212672; //FYI: fits in 29 bits
 int normalInt = 5;
 /* NOTE: PRIu64 is a preprocessor macro and thus should go outside the quoted string. */
 printf("My number is %d bytes wide and its value is %" PRIu64 ". A normal number is %d.\n", sizeof(num), num, normalInt);
 return 0;
}
</code></pre>

Output

<pre><code>My number is 8 bytes wide and its value is 285212672. A normal number is 5.
</code></pre>

blocks|key|1571356|text|在Linux中是%25llu，在Windows中是%25I64u。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1571357|虽然我发现它在Windows2000中不起作用，但那里似乎有一个bug！|1571358|entityMap^0|8|4|N|5|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|P|8|@]|D|@]|E|$]]]|I|$]]

In Linux it is <code>%llu</code> and in Windows it is <code>%I64u</code>

Although I have found it doesn't work in Windows 2000, there seems to be a bug there!

blocks|key|1571086|text|非标准的东西总是很奇怪:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1571087|在GNU下，长长的部分是L、ll或q|offset|length|style|CODE|1571088|在windows下，我相信它只有ll|1571089|entityMap^0|0|C|1|E|2|H|1|0|G|2|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]|$D|P|E|Q|F|G]|$D|R|E|S|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|T|8|@$D|U|E|V|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|K|$]]

Non-standard things are always strange :)

for the long long portion
under GNU it's <code>L</code>, <code>ll</code> or <code>q</code>

and under windows I believe it's <code>ll</code> only

blocks|key|1571134|text|一种方法是使用VS2008将其编译为x64|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1571135|这将按照您的预期运行：|1571136|int+normalInt+=+5;+
unsigned+long+long+int+num=285212672;
printf(
++++"My+number+is+%25d+bytes+wide+and+its+value+is+%25ul.+
++++A+normal+number+is+%25d+\n",+
++++sizeof(num),+
++++num,+
++++normalInt);|code-block|syntax|javascript|1571137|对于32位代码，我们需要使用正确的__int64格式说明符%25I64u。所以它变成了。|1571138|int+normalInt+=+5;+
unsigned+__int64+num=285212672;
printf(
++++"My+number+is+%25d+bytes+wide+and+its+value+is+%25I64u.+
++++A+normal+number+is+%25d",+
++++sizeof(num),
++++num,+normalInt);|1571139|此代码适用于32位和64位VS编译器。|1571140|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Well, one way is to compile it as x64 with VS2008

This runs as you would expect:

<pre><code>int normalInt = 5; 
unsigned long long int num=285212672;
printf(
 "My number is %d bytes wide and its value is %ul. 
 A normal number is %d \n", 
 sizeof(num), 
 num, 
 normalInt);
</code></pre>

For 32 bit code, we need to use the correct __int64 format specifier %I64u. So it becomes. 

<pre><code>int normalInt = 5; 
unsigned __int64 num=285212672;
printf(
 "My number is %d bytes wide and its value is %I64u. 
 A normal number is %d", 
 sizeof(num),
 num, normalInt);
</code></pre>

This code works for both 32 and 64 bit VS compiler.

blocks|key|1786477|text|十六进制：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1786478|printf("64bit:+%25llp",+0xffffffffffffffff);|code-block|syntax|javascript|1786479|输出：|1786480|64bit:+FFFFFFFFFFFFFFFF|1786481|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Hex:

<pre><code>printf("64bit: %llp", 0xffffffffffffffff);
</code></pre>

Output:

<pre><code>64bit: FFFFFFFFFFFFFFFF
</code></pre>

<pre><code>#include &lt;stdio.h&gt;
int main() {
 unsigned long long int num = 285212672; //FYI: fits in 29 bits
 int normalInt = 5;
 printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt);
 return 0;
}
</code></pre>

Output:

<pre><code>My number is 8 bytes wide and its value is 285212672l. A normal number is 0.
</code></pre>

I assume this unexpected result is from printing the <code>unsigned long long int</code>. How do you <code>printf()</code> an <code>unsigned long long int</code>?

How do you format an unsigned long long int using printf?

编译器

Windows

Linux

#include <stdio.h>int main() { unsigned long long int num = 285212672; //FYI: fits in 29 bits int normalInt = 5; printf("My number is %d bytes wide and its value is %ul. A normal number is %d

问如何使用printf格式化一个无符号的long long int？
EN

回答 9

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问如何使用printf格式化一个无符号的long long int？
EN