blocks|key|3008573|text|grep+-r+db-connect.php+.+%7C+grep+version|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3008574|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>grep -r db-connect.php . | grep version
</code></pre>

blocks|key|289951|text|如果您希望grep文件中具有不同行的多个字符串，请使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|289952|grep+-rl+expr1+%7C+xargs+grep+-l+expr2+%7C+xargs+grep+-l+expr3|code-block|syntax|javascript|289953|这将为您提供包含expr1、expr2和expr3的文件列表。|289954|请注意，如果目录中的任何文件名包含空格，则这些文件将产生错误。这个问题可以通过在grep和xargs中添加-0来解决。|289955|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you want to grep for several strings in a file which have different lines, use the following command:

<pre><code>grep -rl expr1 | xargs grep -l expr2 | xargs grep -l expr3
</code></pre>

This will give you a list of files that contain expr1, expr2, and expr3.

Note that if any of the file names in the directory contains spaces, these files will produce errors. This can be fixed by adding -0 I think to grep and xargs.

blocks|key|3222602|text|grep+"db-connect.php“*%7C剪切版本：-f1+%7C+xargs+grep”-d“|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3222603|我没有在递归模式下尝试它，但它应该是相同的。|3222604|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

grep "db-connect.php" * | cut -d: -f1 | xargs grep "version"

I didn't try it in recursive mode but it should be the same.

blocks|key|289921|text|要将多个搜索组合在一起，请使用多个and断言，除了最后一个断言外，每个查找的东西都有一个断言：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|289922|而不是写作|289923|grep+-P+A++*+%7C+grep+B|code-block|syntax|javascript|289924|你写|289925|grep+-P+'(?=.*A)B'+*

grep+-Pr+'(?=.*db-connect\.php)version'+.|289926|不要写|289927|grep+-P+'A.*B%7CB.*A'+*|289928|因为这在重叠上失败了，而(?=…)(?=…)技术不会。|289929|您还可以添加NOT运算符。要搜索与X不匹配的行，通常通常在命令行上使用-v。但是如果它是一个更大的模式的一部分，你就不能这样做。在此情况下，将(?=(?!X).)*$)添加到模式中，以排除其中包含X的任何内容。|289930|想象一下，你想要匹配A，B，C或D中的所有三个，但其中没有X或Y的行。你所需要的就是：|289931|grep+-P+'(?=%5E.*A)(?=%5E.*B)(?=%5E(?:(?!X).)*$)(?=%5E(?:(?!Y).)*$)C%7CD'+*|289932|在某些shell和某些设置中。如果!是您的历史替换字符，则必须对其进行转义。|289933|看，这不是很酷吗？|289934|entityMap^0|H|3|0|0|0|0|0|0|0|C|A|0|6|3|H|1|Z|2|1Z|D|2Q|1|0|0|0|H|1|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1B|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1D|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1E|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|1F|8|@]|D|@]|E|$]]|$1|S|3|T|5|J|7|1G|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|6|7|1H|8|@$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|W|3|X|5|6|7|1K|8|@$9|1L|A|1M|B|C]|$9|1N|A|1O|B|C]|$9|1P|A|1Q|B|C]|$9|1R|A|1S|B|C]|$9|1T|A|1U|B|C]]|D|@]|E|$]]|$1|Y|3|Z|5|6|7|1V|8|@]|D|@]|E|$]]|$1|10|3|11|5|J|7|1W|8|@]|D|@]|E|$K|L]]|$1|12|3|13|5|6|7|1X|8|@$9|1Y|A|1Z|B|C]]|D|@]|E|$]]|$1|14|3|15|5|6|7|20|8|@]|D|@]|E|$]]|$1|16|3|-4|5|6|7|21|8|@]|D|@]|E|$]]]|17|$]]

To <code>and</code> together multiple searches, use multiple lookahead assertions, one per thing looked for apart from the last one:

instead of writing

<pre><code>grep -P A * | grep B
</code></pre>

you write

<pre><code>grep -P '(?=.*A)B' *

grep -Pr '(?=.*db-connect\.php)version' .
</code></pre>

Don’t write

<pre><code>grep -P 'A.*B|B.*A' *
</code></pre>

because that fails on overlaps, whereas the <code>(?=…)(?=…)</code> technique does not.

You can also add in <code>NOT</code> operators as well. To search for lines that don’t match <code>X</code>, you normally of course use <code>-v</code> on the command line. But you can’t do that if it is part of a larger pattern. When it is, you add <code>(?=(?!X).)*$)</code> to the pattern to exclude anything with <code>X</code> in it.

So imagine you want to match lines with all three of A, B, and then either of C or D, but which don’t have X or Y in them. All you need is this:

<pre><code>grep -P '(?=^.*A)(?=^.*B)(?=^(?:(?!X).)*$)(?=^(?:(?!Y).)*$)C|D' *
</code></pre>

In some shells and in some settings. you’ll have to escape the <code>!</code> if it’s your history-substitution character.

There, isn’t that pretty cool?

blocks|key|293158|text|在我的cygwin中，给定的答案不起作用，但以下答案起作用了：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|293159|grep+-l+firststring+`grep+-r+-l+secondstring+.+`|code-block|syntax|javascript|293160|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In my cygwin the given answers didn't work, but the following did:

<pre><code>grep -l firststring `grep -r -l secondstring . `
</code></pre>

blocks|key|290767|text|你的意思是"string1“和"string2”在同一行吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|290768|grep+'string1.*string2'|code-block|syntax|javascript|290769|在同一行上，但顺序不确定？|290770|grep+'(string1.*string2)%7C(string2.*string1)'|290771|或者两个字符串必须同时出现在文件中的任何位置？|290772|grep+-e+string1+-e+string2|290773|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Do you mean "string1" and "string2" on the same line?

<pre><code>grep 'string1.*string2'
</code></pre>

On the same line but in indeterminate order?

<pre><code>grep '(string1.*string2)|(string2.*string1)'
</code></pre>

Or both strings must appear in the file anywhere?

<pre><code>grep -e string1 -e string2
</code></pre>

blocks|key|290775|text|使用PCRE+(与Perl兼容的正则表达式)进行多行匹配，并返回同时包含两个字符串(AND而不是OR)的文件的文件名。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|290776|grep+-Plr+'(?m)db-connect\.php(.*\n)*version%7Cversion(.*\n)*db-connect\.php'+.|code-block|syntax|javascript|290777|entityMap^0|16|3|1C|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

The uses PCRE (Perl-Compatible Regular Expressions) with multiline matching and returns the filenames of files that contain both strings (<code>AND</code> rather than <code>OR</code>).

<pre><code>grep -Plr '(?m)db-connect\.php(.*\n)*version|version(.*\n)*db-connect\.php' .
</code></pre>

blocks|key|3008761|text|为什么只使用grep：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3008762|perl+-lne+'print+if(/db-connect.php/&/version/)'+*|code-block|syntax|javascript|3008763|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Why to stick to only grep:

<pre><code>perl -lne 'print if(/db-connect.php/&amp;/version/)' *
</code></pre>

How can I make use of grep in cygwin to find all files that contain BOTH words.

This is what I use to search all files in a directory recursively for one word:

<pre><code>grep -r "db-connect.php" .
</code></pre>

How can I extend the above to look for files that contain both "db-connect.php" AND "version".

I tried this: <code>grep -r "db-connect.php\|version" .</code> but this is an OR i.e. it gets file that contain one or the other.

Thanks all for any help

Grep Search all files in directory for string1 AND string2

Perl

如何使用cygwin中的grep查找包含和单词的所有文件。这是我用来递归搜索一个目录中的所有文件的一个单词：grep -r "db-connect.php" .如何扩展以上代码以查找同时包含"db-connect.php“和"version”的文件。我尝试过这个：grep -r "db-connect.php\|version" .，但这是一个OR，即它得到的文件包含一个或另一个。感谢所有人的帮助

问Grep在目录中的所有文件中搜索string1和string2
EN

回答 8

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