blocks|key|792188|text|试试这个正则表达式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|792189|'(.*?)"|code-block|syntax|javascript|792190|作为Java字符串文字，您必须将其编写为：|792191|"'(.*?)\""|792192|下面是一个更完整的示例，演示了如何将此正则表达式与Matcher一起使用|offset|length|style|CODE|792193|Pattern+pattern+=+Pattern.compile("'(.*?)\"");
Matcher+matcher+=+pattern.matcher(str);
if+(matcher.find())+{
++++System.out.println(matcher.group(1));
}|792194|在线查看它的工作方式：ideone|792195|entityMap|0|LINK|mutability|MUTABLE|url|http://ideone.com/Iyafu^0|0|0|0|0|P|7|0|0|B|6|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|14|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|16|8|@$M|17|N|18|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1A|8|@]|9|@$M|1B|N|1C|1|1D]]|A|$]]|$1|U|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

Try this regular expression:

<pre><code>'(.*?)"
</code></pre>

As a Java string literal you will have to write it as follows:

<pre><code>"'(.*?)\""
</code></pre>

Here is a more complete example demonstrating how to use this regular expression with a <code>Matcher</code>:

<pre><code>Pattern pattern = Pattern.compile("'(.*?)\"");
Matcher matcher = pattern.matcher(str);
if (matcher.find()) {
 System.out.println(matcher.group(1));
}
</code></pre>

See it working online: <a href="http://ideone.com/Iyafu">ideone</a>

blocks|key|792219|text|如果你总是有这样的字符串(有3个部分)，那么这就足够了：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|792220|+String+str=+"21*90'89\"";
+String+between+=+str.split("\"%7C'")[1];|code-block|syntax|javascript|792221|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you'll always have a string like that (with 3 parts) then this is enough:

<pre><code> String str= "21*90'89\"";
 String between = str.split("\"|'")[1];
</code></pre>

blocks|key|1006231|text|另一种选择是，如果您可以确保字符串始终采用您提供的格式，则可以使用快捷的子串/indexOf解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1006232|str.substring(str.indexOf("'")+%2B+1,+str.indexOf("\""));|code-block|syntax|javascript|1006233|为了得到你想要的第二个数据：|1006234|str.substring(0,+str.indexOf("*"));|1006235|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Another option, if you can assure that your strings will always be in the format you provide, you can use a quick-and-dirty substring/indexOf solution:

<pre><code>str.substring(str.indexOf("'") + 1, str.indexOf("\""));
</code></pre>

And to get the second piece of data you asked for:

<pre><code>str.substring(0, str.indexOf("*"));
</code></pre>

blocks|key|792380|text|public+static+void+main(final+String[]+args)+{
++++final+String+str+=+"21*90'89\"";
++++final+Pattern+pattern+=+Pattern.compile("[\\*'\"]");
++++final+String[]+result+=+pattern.split(str);
++++System.out.println(Arrays.toString(result));
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|792381|就是你要找的..。上面描述的程序产生：|unstyled|792382|[21,+90,+89]|792383|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>public static void main(final String[] args) {
 final String str = "21*90'89\"";
 final Pattern pattern = Pattern.compile("[\\*'\"]");
 final String[] result = pattern.split(str);
 System.out.println(Arrays.toString(result));
}
</code></pre>

Is what you are looking for... The program described above produces:

<pre><code>[21, 90, 89]
</code></pre>

blocks|key|792387|text|String+str=+21*90'89;
String+part=+str.split("[*%7C']");
System.out.println(part[0]+%2B""%2Bpart[1]);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|792388|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>String str= 21*90'89;
String part= str.split("[*|']");
System.out.println(part[0] +""+part[1]);
</code></pre>

blocks|key|792390|text|++++String+str="abc#defg@lmn!tp?pqr*tsd";+++++++++++++++
++++String+special="!?@#$%25%5E&*()/<>{}[]:;'`~";+++++++++++
++++ArrayList<Integer>+al=new+ArrayList<Integer>();+++++++++
++++for(int+i=0;i<str.length();i%2B%2B)
++++{
++++++++for(int+j=0;j<special.length();j%2B%2B)
++++++++++++if(str.charAt(i)==special.charAt(j))++++++++
++++++++++++++++al.add(i);
++++}
++++for(int+i=0;i<al.size()-1;i%2B%2B)
++++{
++++++++int+start=al.get(i);
++++++++int+end=al.get(i%2B1);
++++++++for(int+j=start%2B1;j<end;j%2B%2B)
++++++++++++System.out.print(str.charAt(j));
++++++++System.out.print("+");
++++}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|792391|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> String str="abc#defg@lmn!tp?pqr*tsd"; 
 String special="!?@#$%^&amp;*()/&lt;&gt;{}[]:;'`~"; 
 ArrayList&lt;Integer&gt; al=new ArrayList&lt;Integer&gt;(); 
 for(int i=0;i&lt;str.length();i++)
 {
 for(int j=0;j&lt;special.length();j++)
 if(str.charAt(i)==special.charAt(j)) 
 al.add(i);
 }
 for(int i=0;i&lt;al.size()-1;i++)
 {
 int start=al.get(i);
 int end=al.get(i+1);
 for(int j=start+1;j&lt;end;j++)
 System.out.print(str.charAt(j));
 System.out.print(" ");
 }
</code></pre>

I have been trying to figure out how to extract a portion of a string between two special characters ' and " I've been looking into regex, but frankly I cannot understand it. 
Example in Java code:

<pre><code>String str="21*90'89\""; 
</code></pre>

I would like to pull out 89

In general I would just like to know how to extract part of a string between two specific characters please.

Also it would be nice to know how to extract part of the string from the beginning to a specific character like to get 21.

Java- Extract part of a string between two special characters

Java

我一直在尝试找出如何在两个特殊字符‘和’之间提取字符串的一部分，“我一直在研究regex，但坦率地说，我无法理解它。Java代码中的示例：String str="21*90'89\""; 我想拔出89一般来说，我只想知道如何在两个特定字符之间提取字符串的一部分。此外，如果知道如何将字符串的一部分从开头提取到某个特定字符...

问Java-提取字符串中两个特殊字符之间的部分
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