blocks|key|1375733|text|怎么样|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1375734|[x+%2B+y+for+x+in+list1+for+y+in+list2]+%2B+[y+%2B+x+for+x+in+list1+for+y+in+list2]|code-block|syntax|javascript|1375735|IPython交互示例：|1375736|In+[3]:+list1+=+['square',+'circle',+'triangle']

In+[4]:+list2+=+['red',+'green']

In+[5]:+[x+%2B+y+for+x+in+list1+for+y+in+list2]+%2B+[y+%2B+x+for+x+in+list1+for+y+in+list2]
Out[5]:+
['squarered',
+'squaregreen',
+'circlered',
+'circlegreen',
+'trianglered',
+'trianglegreen',
+'redsquare',
+'greensquare',
+'redcircle',
+'greencircle',
+'redtriangle',
+'greentriangle']|1375737|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

How about

<pre><code>[x + y for x in list1 for y in list2] + [y + x for x in list1 for y in list2]
</code></pre>

Example IPython interaction:

<pre><code>In [3]: list1 = ['square', 'circle', 'triangle']

In [4]: list2 = ['red', 'green']

In [5]: [x + y for x in list1 for y in list2] + [y + x for x in list1 for y in list2]
Out[5]: 
['squarered',
 'squaregreen',
 'circlered',
 'circlegreen',
 'trianglered',
 'trianglegreen',
 'redsquare',
 'greensquare',
 'redcircle',
 'greencircle',
 'redtriangle',
 'greentriangle']
</code></pre>

blocks|key|1160483|text|在任何情况下，您都可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1160484|perms+=+[]
for+shape+in+list1:
++for+color+in+list2:
++++perms.append(shape%2Bcolor)|code-block|syntax|javascript|1160485|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can in any case do something like:

<pre><code>perms = []
for shape in list1:
 for color in list2:
 perms.append(shape+color)
</code></pre>

blocks|key|1375810|text|我认为您正在寻找的是两个列表的乘积，而不是排列：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1375811|#!/usr/bin/env+python
import+itertools
list1=['square','circle','triangle']+
list2=['red','green']
for+shape,color+in+itertools.product(list1,list2):
++++print(shape%2Bcolor)|code-block|syntax|javascript|1375812|收益率|1375813|squarered
squaregreen
circlered
circlegreen
trianglered
trianglegreen|1375814|如果你想同时使用squarered和redsquare，那么你可以这样做：|offset|length|style|CODE|1375815|for+pair+in+itertools.product(list1,list2):
++++for+a,b+in+itertools.permutations(pair,2):
++++++++print(a%2Bb)|1375816|或者，将其添加到列表中：|1375817|l=[a%2Bb+for+pair+in+itertools.product(list1,list2)
+++for+a,b+in+itertools.permutations(pair,2)]
print(l)|1375818|1375819|['squarered',+'redsquare',+'squaregreen',+'greensquare',+'circlered',+'redcircle',+'circlegreen',+'greencircle',+'trianglered',+'redtriangle',+'trianglegreen',+'greentriangle']|1375820|entityMap^0|0|0|0|0|8|9|I|9|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|13|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|15|8|@$M|16|N|17|O|P]|$M|18|N|19|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1B|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|W|3|H|5|6|7|1D|8|@]|9|@]|A|$]]|$1|X|3|Y|5|D|7|1E|8|@]|9|@]|A|$E|F]]|$1|Z|3|-4|5|6|7|1F|8|@]|9|@]|A|$]]]|10|$]]

I think what you are looking for is the product of two lists, not the permutations:

<pre><code>#!/usr/bin/env python
import itertools
list1=['square','circle','triangle'] 
list2=['red','green']
for shape,color in itertools.product(list1,list2):
 print(shape+color)
</code></pre>

yields

<pre><code>squarered
squaregreen
circlered
circlegreen
trianglered
trianglegreen
</code></pre>

If you'd like both <code>squarered</code> and <code>redsquare</code>, then you could do something like this:

<pre><code>for pair in itertools.product(list1,list2):
 for a,b in itertools.permutations(pair,2):
 print(a+b)
</code></pre>

or, to make it into a list: 

<pre><code>l=[a+b for pair in itertools.product(list1,list2)
 for a,b in itertools.permutations(pair,2)]
print(l)
</code></pre>

yields 

<pre><code>['squarered', 'redsquare', 'squaregreen', 'greensquare', 'circlered', 'redcircle', 'circlegreen', 'greencircle', 'trianglered', 'redtriangle', 'trianglegreen', 'greentriangle']
</code></pre>

blocks|key|1160582|text|>>>+import+itertools
>>>+map(''.join,+itertools.chain(itertools.product(list1,+list2),+itertools.product(list2,+list1)))
['squarered',+'squaregreen',+'circlered',
'circlegreen',+'trianglered',+'trianglegreen',
'redsquare',+'redcircle',+'redtriangle',+'greensquare',
'greencircle',+'greentriangle']|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1160583|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>&gt;&gt;&gt; import itertools
&gt;&gt;&gt; map(''.join, itertools.chain(itertools.product(list1, list2), itertools.product(list2, list1)))
['squarered', 'squaregreen', 'circlered',
'circlegreen', 'trianglered', 'trianglegreen',
'redsquare', 'redcircle', 'redtriangle', 'greensquare',
'greencircle', 'greentriangle']
</code></pre>

I have two lists like:

<pre><code>list1 = ['square','circle','triangle']
list2 = ['red','green']
</code></pre>

How can I create all permutations of these lists, like this:

<pre><code>[
 'squarered', 'squaregreen',
 'redsquare', 'greensquare',
 'circlered', 'circlegreen',
 'redcircle', 'greencircle',
 'trianglered', 'trianglegreen',
 'redtriangle', 'greentriangle'
]
</code></pre>

Can I use <code>itertools</code> for this?

permutations of two lists in python

我有两个列表，如：list1 = ['square','circle','triangle']list2 = ['red','green']如何创建这些列表的所有排列，如下所示：[  'squarered', 'squaregreen',  'redsquare', 'greensquare',  'circlered...

问python中两个列表的排列
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