blocks|key|846968|text|它已经是一个列表了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|846969|type(my_set)
>>>+<type+'list'>|code-block|syntax|javascript|846970|你想要像这样的东西吗|846971|my_set+=+set([1,2,3,4])
my_list+=+list(my_set)
print+my_list
>>+[1,+2,+3,+4]|846972|编辑:最后一条评论的输出|846973|>>>+my_list+=+[1,2,3,4]
>>>+my_set+=+set(my_list)
>>>+my_new_list+=+list(my_set)
>>>+print+my_new_list
[1,+2,+3,+4]|846974|我想知道你有没有做过这样的事情：|846975|>>>+set=set()
>>>+set([1,2])
Traceback+(most+recent+call+last):
++File+"<stdin>",+line+1,+in+<module>
TypeError:+'set'+object+is+not+callable|846976|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

It is already a list

<pre><code>type(my_set)
&gt;&gt;&gt; &lt;type 'list'&gt;
</code></pre>

Do you want something like 

<pre><code>my_set = set([1,2,3,4])
my_list = list(my_set)
print my_list
&gt;&gt; [1, 2, 3, 4]
</code></pre>

EDIT : 
Output of your last comment

<pre><code>&gt;&gt;&gt; my_list = [1,2,3,4]
&gt;&gt;&gt; my_set = set(my_list)
&gt;&gt;&gt; my_new_list = list(my_set)
&gt;&gt;&gt; print my_new_list
[1, 2, 3, 4]
</code></pre>

I'm wondering if you did something like this : 

<pre><code>&gt;&gt;&gt; set=set()
&gt;&gt;&gt; set([1,2])
Traceback (most recent call last):
 File "&lt;stdin&gt;", line 1, in &lt;module&gt;
TypeError: 'set' object is not callable
</code></pre>

blocks|key|847046|text|我不确定您是否正在使用这种([1,+2])语法创建一个集合，而是一个列表。要创建set，您应该使用set([1,+2])。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|847047|这些括号只是用来包围你的表达式，就像你会写下：|847048|if+(condition1
++++and+condition2+==+3):
++++print+something|code-block|syntax|javascript|847049|这并不是真的被忽略了，但对你的表达式没有任何影响。|847050|注意：(something,+something_else)将创建一个元组(但仍然没有列表)。|847051|entityMap^0|D|8|1D|B|0|0|0|0|3|R|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

I'm not sure that you're creating a set with this <code>([1, 2])</code> syntax, rather a list. To create a set, you should use <code>set([1, 2])</code>.

These brackets are just envelopping your expression, as if you would have written:

<pre><code>if (condition1
 and condition2 == 3):
 print something
</code></pre>

There're not really ignored, but do nothing to your expression. 

Note: <code>(something, something_else)</code> will create a tuple (but still no list).

blocks|key|847102|text|复习你的第一行。您的堆栈跟踪显然不是来自您在这里粘贴的代码，所以我不知道您到底做了什么。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|847103|>>>+my_set=([1,2,3,4])
>>>+my_set
[1,+2,+3,+4]
>>>+type(my_set)
<type+'list'>
>>>+list(my_set)
[1,+2,+3,+4]
>>>+type(_)
<type+'list'>|code-block|syntax|javascript|847104|你想要的是set([1,+2,+3,+4])。|offset|length|style|CODE|847105|>>>+my_set+=+set([1,+2,+3,+4])
>>>+my_set
set([1,+2,+3,+4])
>>>+type(my_set)
<type+'set'>
>>>+list(my_set)
[1,+2,+3,+4]
>>>+type(_)
<type+'list'>|847106|“不可调用”异常意味着你正在做类似set()()的事情--试图调用一个set实例。|847107|entityMap^0|0|0|5|H|0|0|H|7|Z|3|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@$I|Z|J|10|K|L]|$I|11|J|12|K|L]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

Review your first line. Your stack trace is clearly not from the code you've pasted here, so I don't know precisely what you've done.

<pre><code>&gt;&gt;&gt; my_set=([1,2,3,4])
&gt;&gt;&gt; my_set
[1, 2, 3, 4]
&gt;&gt;&gt; type(my_set)
&lt;type 'list'&gt;
&gt;&gt;&gt; list(my_set)
[1, 2, 3, 4]
&gt;&gt;&gt; type(_)
&lt;type 'list'&gt;
</code></pre>

What you wanted was <code>set([1, 2, 3, 4])</code>.

<pre><code>&gt;&gt;&gt; my_set = set([1, 2, 3, 4])
&gt;&gt;&gt; my_set
set([1, 2, 3, 4])
&gt;&gt;&gt; type(my_set)
&lt;type 'set'&gt;
&gt;&gt;&gt; list(my_set)
[1, 2, 3, 4]
&gt;&gt;&gt; type(_)
&lt;type 'list'&gt;
</code></pre>

The "not callable" exception means you were doing something like <code>set()()</code> - attempting to call a <code>set</code> instance.

blocks|key|630736|text|编辑看起来你之前已经重新定义了"list"，使用它作为变量名，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|630737|list+=+set([1,2,3,4])+#+oops
#...
first_list+=+[1,2,3,4]
my_set=set(first_list)
my_list+=+list(my_set)|code-block|syntax|javascript|630738|你就会得到|630739|Traceback+(most+recent+call+last):
++File+"<console>",+line+1,+in+<module>
TypeError:+'set'+object+is+not+callable|630740|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

[EDITED]
It's seems you earlier have redefined "list", using it as a variable name, like this:

<pre><code>list = set([1,2,3,4]) # oops
#...
first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
</code></pre>

And you'l get

<pre><code>Traceback (most recent call last):
 File "&lt;console&gt;", line 1, in &lt;module&gt;
TypeError: 'set' object is not callable
</code></pre>

blocks|key|630786|text|Python是一种动态类型语言，这意味着您不能像在C或C%2B%2B中那样定义变量的类型：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|630787|type+variable+=+value|code-block|syntax|javascript|630788|或|630789|type+variable(value)|630790|在Python中，如果更改类型，则可以使用强制，或者使用类型的init函数(构造函数)来声明类型的变量：|630791|my_set+=+set([1,2,3])
type+my_set|630792|将会给你一个答案是<type+'set'>。|offset|length|style|CODE|630793|如果您有一个列表，请执行以下操作：|630794|my_list+=+[1,2,3]
my_set+=+set(my_list)|630795|entityMap^0|0|0|0|0|0|0|9|C|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|14|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|16|8|@$Q|17|R|18|S|T]]|9|@]|A|$]]|$1|U|3|V|5|6|7|19|8|@]|9|@]|A|$]]|$1|W|3|X|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|Y|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|Z|$]]

Python is a dynamically typed language, which means that you cannot define the type of the variable as you do in C or C++:

<pre><code>type variable = value
</code></pre>

or 

<pre><code>type variable(value)
</code></pre>

In Python, you use coercing if you change types, or the init functions (constructors) of the types to declare a variable of a type:

<pre><code>my_set = set([1,2,3])
type my_set
</code></pre>

will give you <code>&lt;type 'set'&gt;</code> for an answer. 

If you have a list, do this:

<pre><code>my_list = [1,2,3]
my_set = set(my_list)
</code></pre>

blocks|key|847278|text|嗯，我敢打赌，在前面的一些代码行中，你会看到这样的内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|847279|list+=+set(something)|code-block|syntax|javascript|847280|我说错了吗？|847281|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Hmmm I bet that in some previous lines you have something like:

<pre><code>list = set(something)
</code></pre>

Am I wrong ?

blocks|key|847324|text|而不是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|847325|first_list+=+[1,2,3,4]
my_set=set(first_list)
my_list+=+list(my_set)|code-block|syntax|javascript|847326|为什么不简化这个过程：|847327|my_list+=+list(set([1,2,3,4])|847328|这将从您的列表中删除复制并返回一个列表给您。|847329|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Instead of: 

<pre><code>first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
</code></pre>

Why not shortcut the process:

<pre><code>my_list = list(set([1,2,3,4])
</code></pre>

This will remove the dupes from you list and return a list back to you.

blocks|key|630954|text|每当遇到这种类型的问题时，尝试通过使用以下命令来查找要首先转换的元素的数据类型：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|630955|type(my_set)|code-block|syntax|javascript|630956|然后，使用：|630957|++list(my_set)+|630958|将其转换为列表。现在，您可以像使用python中的任何普通列表一样使用新构建的列表。|630959|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Whenever you are stuck in such type of problems, try to find the datatype of the element you want to convert first by using : 

<pre><code>type(my_set)
</code></pre>

Then, Use:

<pre><code> list(my_set) 
</code></pre>

to convert it to a list. You can use the newly built list like any normal list in python now.

blocks|key|847431|text|只需键入：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|847432|list(my_set)|code-block|syntax|javascript|847433|这会将{'1'，'2'}形式的集合转换为'1'，'2‘形式的列表。|847434|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Simply type:

<pre><code>list(my_set)
</code></pre>

This will turn a set in the form {'1','2'} into a list in the form ['1','2'].

I am trying to convert a set to a list in Python 2.6. I'm using this syntax:

<pre><code>first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
</code></pre>

However, I get the following stack trace:

<pre><code>Traceback (most recent call last):
 File "&lt;console&gt;", line 1, in &lt;module&gt;
TypeError: 'set' object is not callable
</code></pre>

How can I fix this?

How to convert a set to a list in python?

Python

我正在尝试在Python2.6中将集合转换为列表。我使用的语法是：first_list = [1,2,3,4]my_set=set(first_list)my_list = list(my_set)但是，我得到了以下堆栈跟踪：Traceback (most recent call last): File "<cons...

问如何在python中将集合转换为列表？
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