blocks|key|2988039|text|如果你需要覆盖这些，很可能以后你会需要更多的定制。最干净的做法是使用user+profile+models，而不是接触用户模型|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2988040|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.djangoproject.com/en/dev/topics/auth/#storing-additional-information-about-users^0|Y|J|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

If you need to override these, chances are you would need more customizations later on. 
The cleanest practice would be using a <a href="http://docs.djangoproject.com/en/dev/topics/auth/#storing-additional-information-about-users" rel="nofollow">user profile models</a> instead of touching the User model

blocks|key|282842|text|创建代理用户类。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|282843|class+UserProxy(User):
++++class+Meta:
++++++++proxy+=+True
++++++++ordering+=+['last_name',+'first_name']

++++def+__unicode__(self):
++++++++return+u'%25s,+%25s'+%25+(self.last_name,+self.first_name)|code-block|syntax|javascript|282844|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Create a proxy User class.

<pre><code>class UserProxy(User):
 class Meta:
 proxy = True
 ordering = ['last_name', 'first_name']

 def __unicode__(self):
 return u'%s, %s' % (self.last_name, self.first_name)
</code></pre>

blocks|key|3201593|text|如果你只是想在管理界面中显示全名(这正是我所需要的)，你可以很容易地在运行时修补它。只需在您的admin.py中执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3201594|from+django.contrib+import+admin
from+django.contrib.auth.models+import+User

def+user_unicode(self):
++++return++u'%25s,+%25s'+%25+(self.last_name,+self.first_name)

User.__unicode__+=+user_unicode

admin.site.unregister(User)
admin.site.register(User)|code-block|syntax|javascript|3201595|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you simply want to show the full name in the admin interface (which is what I needed), you can easily monkey-patch it during runtime. Just do something like this in your admin.py:

<pre><code>from django.contrib import admin
from django.contrib.auth.models import User

def user_unicode(self):
 return u'%s, %s' % (self.last_name, self.first_name)

User.__unicode__ = user_unicode

admin.site.unregister(User)
admin.site.register(User)
</code></pre>

blocks|key|3201613|text|Django的代理模型解决了这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3201614|这是我的解决方案：|3201615|form.fields['students'].queryset+=+Student.objects.filter(id__in+=+school.students.all())|code-block|syntax|javascript|3201616|这里school.students是一个m2m(用户)，学生是用户的代理模型。|3201617|class+Student(User):
++++class+Meta:
++++++++proxy+=+True
++++def+__unicode__(self):
++++++++return+'what+ever+you+want+to+return'|3201618|如果您想在您的自定义方法中显示您的用户ForeignKey，以上所有这些都可以帮助您解决问题。如果您只是想在管理视图中更改它，有一个简单的解决方案：|3201619|def+my_unicode(self):
++++return+'what+ever+you+want+to+return'

User.__unicode__+=+my_unicode

admin.site.unregister(User)
admin.site.register(User)|3201620|将这些代码添加到admin.py中，它就可以工作。|3201621|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

Django's Proxy Model solved this problem.

This is my solution:

<pre><code>form.fields['students'].queryset = Student.objects.filter(id__in = school.students.all())
</code></pre>

Here school.students is a m2m(User), Student is a proxy model of User. 

<pre><code>class Student(User):
 class Meta:
 proxy = True
 def __unicode__(self):
 return 'what ever you want to return'
</code></pre>

All above helps you to solve if your want to show your User ForeignKey in your custom method. If your just want to change it in admin view, there is a simple solution:

<pre><code>def my_unicode(self):
 return 'what ever you want to return'

User.__unicode__ = my_unicode

admin.site.unregister(User)
admin.site.register(User)
</code></pre>

add these codes to admin.py, it works.

blocks|key|280847|text|我刚刚在django+1.5上找到了这个简单的方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|280848|def+__unicode__(self):
+++a+=+self.last_name
+++b+=+self.first_name+
+++c+=+a%2B+"-"+%2Bb
+++return+c+|code-block|syntax|javascript|280849|它将返回您想要的内容|280850|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I just found this simple method on django 1.5

<pre><code>def __unicode__(self):
 a = self.last_name
 b = self.first_name 
 c = a+ "-" +b
 return c 
</code></pre>

it will return what you want

Currently, Django 1.2.3 User model unicode is

<pre><code>def __unicode__(self):
 return self.username
</code></pre>

and I'd like to override it so its:

<pre><code>def __unicode__(self):
 return u'%s, %s' % (self.last_name, self.first_name)
</code></pre>

How to?

To similar effect:

<pre><code>User._meta.ordering = ['last_name', 'first_name']
</code></pre>

works when defined <code>anywhere</code>

Override Django User model __unicode__

Django

目前，Django 1.2.3用户模型unicode是def __unicode__(self):    return self.username我想要覆盖它，所以它：def __unicode__(self):    return u'%s, %s' % (self.last_name, self.first_nam...

问覆盖Django用户模型unicode
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