blocks|key|608142|text|相对于类路径根。也就是说，您的WEB-INF/classes+%2B+WEB-INF/lib中的所有jars|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|608143|entityMap^0|F|F|X|B|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

Relative to the classpath root. That is, your <code>WEB-INF/classes</code> + all the jars in <code>WEB-INF/lib</code>

blocks|key|823190|text|在Play框架中，"conf“目录位于类路径上，因此您可以将文件放在那里并使用getResourceAsStream打开它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|823191|例如，如果您创建了一个文件"conf/foo.txt“，您可以使用以下命令打开它|823192|Play.classloader.getResourceAsStream("foo.txt");|code-block|syntax|javascript|823193|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

In the Play Framework the "conf" directory is on the classpath, so you can put your file there and open it with getResourceAsStream.

For example if you create a file "conf/foo.txt" you can open it using

<pre><code>Play.classloader.getResourceAsStream("foo.txt");
</code></pre>

blocks|key|823238|text|作为使用conf目录(应该仅用于与配置相关的文件)的替代方法，您可以使用public目录并通过以下方式访问它：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|823239|+Play.classloader.getResourceAsStream("public/foo.txt")|code-block|syntax|javascript|823240|或者在Scala中使用：|823241|+Play.resourceAsStream("public/foo.txt")|823242|entityMap^0|4|4|10|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

As an alternative to using the <code>conf</code> dir (which should only be used for configuration-related files), you can use the <code>public</code> dir and access it with:

<pre><code> Play.classloader.getResourceAsStream("public/foo.txt")
</code></pre>

Or in Scala with:

<pre><code> Play.resourceAsStream("public/foo.txt")
</code></pre>

blocks|key|608327|text|被接受的答案在Play+2.5.x中被弃用，因为对类加载器之类的东西的全局访问正在慢慢被淘汰。处理这个问题的推荐方法是注入一个play.api.Environment，然后使用它的classLoader来获取InputStream，例如|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|608328|class+Controller+@Inject()(env:+Environment,+...){

++def+readFile+=+Action+{++req+=>
++++...

++++//if+the+path+is+bad,+this+will+return+null,+so+best+to+wrap+in+an+Option
++++val+inputStream+=+Option(env.classLoader.getResourceAsStream(path))

++++...
++}
}|code-block|syntax|javascript|608329|entityMap^0|1R|K|2I|B|2W|B|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

The accepted answer is deprecated in Play 2.5.x as global access to things like a classloader is slowly being phased out. The recommended way to handling this moving forward is to inject a <code>play.api.Environment</code> then using its <code>classLoader</code> to get the <code>InputStream</code>, e.g.

<pre><code>class Controller @Inject()(env: Environment, ...){

 def readFile = Action { req =&gt;
 ...

 //if the path is bad, this will return null, so best to wrap in an Option
 val inputStream = Option(env.classLoader.getResourceAsStream(path))

 ...
 }
}
</code></pre>

blocks|key|608372|text|注入Environment，然后调用environment.resourceAsStream("filename");|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|608373|示例：|608374|import+javax.inject.Inject;

public+class+ExampleResource+extends+Controller{

+++++private+final+Environment+environment;
+++++
+++++@Inject
+++++public+ExampleResource(Environment+environment){
++++++++++this.environment+=+environment;
+++++}

+++++public+void+readResourceAsStream()+{
++++++++++InputStream+resource+=+environment.resourceAsStream("filename");
++++++++++//+Do+what+you+want+with+the+stream+here
+++++}
}|code-block|syntax|javascript|608375|文档：https://www.playframework.com/documentation/2.8.0/api/java/play/Environment.html#resourceAsStream-java.lang.String-|608376|entityMap|0|LINK|mutability|MUTABLE|url|https://www.playframework.com/documentation/2.8.0/api/java/play/Environment.html#resourceAsStream-java.lang.String-^0|2|B|I|15|0|0|0|3|37|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|D|@$9|14|A|15|1|16]]|E|$]]|$1|O|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

Inject <code>Environment</code> and then call <code>environment.resourceAsStream(&quot;filename&quot;);</code>
Example:
<pre><code>import javax.inject.Inject;

public class ExampleResource extends Controller{

 private final Environment environment;
 
 @Inject
 public ExampleResource(Environment environment){
 this.environment = environment;
 }

 public void readResourceAsStream() {
 InputStream resource = environment.resourceAsStream(&quot;filename&quot;);
 // Do what you want with the stream here
 }
}
</code></pre>
Documentation: <a href="https://www.playframework.com/documentation/2.8.0/api/java/play/Environment.html#resourceAsStream-java.lang.String-" rel="nofollow noreferrer">https://www.playframework.com/documentation/2.8.0/api/java/play/Environment.html#resourceAsStream-java.lang.String-</a>

<pre><code>Play.classloader.getResourceAsStream(filepath); 
</code></pre>

filepath - relative to what? project root? playframework root? absolute path?

Or maybe the usage Play.classloader.getResourceAsStream is wrong?

Getting a resource file as an InputStream in Playframework

Play.classloader.getResourceAsStream(filepath); 文件路径-相对于什么？项目根？playframework root？绝对路径？或者可能Play.classloader.getResourceAsStream的用法是错误的？

问在Playframework中以InputStream的形式获取资源文件
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在Playframework中以InputStream的形式获取资源文件EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在Playframework中以InputStream的形式获取资源文件
EN