blocks|key|1433120|text|这应该涵盖了你：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1433121|String+lines[]+=+string.split("\\r?\\n");|code-block|syntax|javascript|1433122|实际上只有两个换行符(UNIX和Windows)是您需要担心的。|1433123|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This should cover you:

<pre><code>String lines[] = string.split("\\r?\\n");
</code></pre>

There's only really two newlines (UNIX and Windows) that you need to worry about.

blocks|key|1433170|text|如果您不想要空行：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1433171|String.split("[\\r\\n]%2B")|code-block|syntax|javascript|1433172|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you don’t want empty lines:

<pre><code>String.split("[\\r\\n]+")
</code></pre>

blocks|key|1648110|text|上面的代码实际上并没有做任何可见的事情-它只是计算然后转储计算。这是你使用的代码，还是这个问题的一个例子？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1648111|尝试在末尾执行textAreaDoc.insertString(int，String，AttributeSet)？|1648112|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

The above code doesnt actually do anything visible - it just calcualtes then dumps the calculation. Is it the code you used, or just an example for this question? 

try doing textAreaDoc.insertString(int, String, AttributeSet) at the end?

blocks|key|1648176|text|也许这能行得通：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1648177|从split方法的参数中删除双反斜杠：|1648178|split+=+docStr.split("\n");|code-block|syntax|javascript|1648179|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Maybe this would work:

Remove the double backslashes from the parameter of the split method:

<pre><code>split = docStr.split("\n");
</code></pre>

blocks|key|1433340|text|您不必在字符组中使用两个转义字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1433341|对于所有非空行，请使用：|1433342|String.split("[\r\n]%2B")|code-block|syntax|javascript|1433343|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You don't have to double escape characters in character groups.

For all non empty lines use:

<pre><code>String.split("[\r\n]+")
</code></pre>

blocks|key|1648262|text|String.split(System.lineSeparator());|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1648263|这应该是独立于系统的|unstyled|1648264|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>String.split(System.lineSeparator());
</code></pre>
This should be system independent

blocks|key|1648288|text|package+in.javadomain;

public+class+JavaSplit+{

++++public+static+void+main(String[]+args)+{
++++++++String+input+=+"chennai\nvellore\ncoimbatore\nbangalore\narcot";
++++++++System.out.println("Before+split:\n");
++++++++System.out.println(input);

++++++++String[]+inputSplitNewLine+=+input.split("\\n");
++++++++System.out.println("\n+After+split:\n");
++++++++for(int+i=0;+i<inputSplitNewLine.length;+i%2B%2B){
++++++++++++System.out.println(inputSplitNewLine[i]);
++++++++}
++++}

}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1648289|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>package in.javadomain;

public class JavaSplit {

 public static void main(String[] args) {
 String input = "chennai\nvellore\ncoimbatore\nbangalore\narcot";
 System.out.println("Before split:\n");
 System.out.println(input);

 String[] inputSplitNewLine = input.split("\\n");
 System.out.println("\n After split:\n");
 for(int i=0; i&lt;inputSplitNewLine.length; i++){
 System.out.println(inputSplitNewLine[i]);
 }
 }

}
</code></pre>

blocks|key|1648295|text|String+lines[]+=String.split(+System.lineSeparator())|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1648296|entityMap^0|0|1H|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>String lines[] =String.split( System.lineSeparator())</code>

blocks|key|1433466|text|为了防止空行被挤压使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1433467|String+lines[]+=+String.split("\\r?\\n",+-1);|code-block|syntax|javascript|1433468|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For preserving empty lines from getting squashed use:

<pre><code>String lines[] = String.split("\\r?\\n", -1);
</code></pre>

blocks|key|1433542|text|在所有给定解决方案的基础上失败的尝试之后。我用一些特殊的单词替换了\n，然后拆分。对我来说，下面的技巧做到了：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1433543|article+=+"Alice+phoned\n+bob.";
article+=+article.replace("\\n",+"+NEWLINE+");
String+sen+[]+=+article.split("+NEWLINE+");|code-block|syntax|javascript|1433544|我不能重复问题中给出的例子。但是，我想这个逻辑是可以应用的。|1433545|entityMap^0|X|2|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

After failed attempts on the basis of all given solutions. I replace <code>\n</code> with some special word and then split. For me following did the trick:

<pre><code>article = "Alice phoned\n bob.";
article = article.replace("\\n", " NEWLINE ");
String sen [] = article.split(" NEWLINE ");
</code></pre>

I couldn't replicate the example given in the question. But, I guess this logic can be applied.

blocks|key|1433613|text|作为前面答案的替代方案，如果要对结果行应用其他操作，如修剪行或过滤空行，则可以使用guava的Splitter应用程序接口：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1433614|import+com.google.common.base.Splitter;

Iterable<String>+split+=+Splitter.onPattern("\r?\n").trimResults().omitEmptyStrings().split(docStr);|code-block|syntax|javascript|1433615|注意，结果是一个Iterable，而不是一个数组。|1433616|entityMap^0|1B|8|0|0|8|8|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

As an alternative to the previous answers, guava's <code>Splitter</code> API can be used if other operations are to be applied to the resulting lines, like trimming lines or filtering empty lines :

<pre><code>import com.google.common.base.Splitter;

Iterable&lt;String&gt; split = Splitter.onPattern("\r?\n").trimResults().omitEmptyStrings().split(docStr);
</code></pre>

Note that the result is an <code>Iterable</code> and not an array.

blocks|key|1648488|text|如果，由于某种原因，您不想使用String.split+(例如，因为regular+expressions)，并且您想在Java8或更高版本上使用函数式编程：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1648489|List<String>+lines+=+new+BufferedReader(new+StringReader(string))
++++++++.lines()
++++++++.collect(Collectors.toList());|code-block|syntax|javascript|1648490|entityMap|0|LINK|mutability|MUTABLE|url|http://regex.info/blog/2006-09-15/247^0|F|C|Y|J|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

If, for some reason, you don't want to use <code>String.split</code> (for example, because of <a href="http://regex.info/blog/2006-09-15/247" rel="noreferrer">regular expressions</a>) and you want to use functional programming on Java 8 or newer:

<pre><code>List&lt;String&gt; lines = new BufferedReader(new StringReader(string))
 .lines()
 .collect(Collectors.toList());
</code></pre>

blocks|key|1648528|text|上面的答案对我在安卓系统上没有帮助，这要归功于我在安卓系统上的Pshemo响应。我将在这里留下一些Pshemo's+answer：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1648529|split("\\\\n")|code-block|syntax|javascript|1648530|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/25068483/10807406|1^0|V|6|0|1D|F|1|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@$A|S|B|T|1|U]|$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|Z|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]|Q|$5|L|M|N|C|$O|P]]]]

The above answers did not help me on Android, thanks to the <a href="https://stackoverflow.com/a/25068483/10807406">Pshemo</a> response that worked for me on Android. I will leave some of <a href="https://stackoverflow.com/a/25068483/10807406">Pshemo's answer</a> here :

<pre><code>split("\\\\n")
</code></pre>

I'm trying to split text in a <code>JTextArea</code> using a regex to split the String by <code>\n</code> However, this does not work and I also tried by <code>\r\n|\r|n</code> and many other combination of regexes.
Code:

<pre><code>public void insertUpdate(DocumentEvent e) {
 String split[], docStr = null;
 Document textAreaDoc = (Document)e.getDocument();

 try {
 docStr = textAreaDoc.getText(textAreaDoc.getStartPosition().getOffset(), textAreaDoc.getEndPosition().getOffset());
 } catch (BadLocationException e1) {
 // TODO Auto-generated catch block
 e1.printStackTrace();
 }

 split = docStr.split("\\n");
}
</code></pre>

Split Java String by New Line

Windows

我正在尝试使用正则表达式来拆分JTextArea中的文本，以按\n拆分字符串。但是，这不起作用，我也尝试了\r\n|\r|n和许多其他正则表达式的组合。代码：public void insertUpdate(DocumentEvent e) {    String split[], docStr = null;    ...

问按新行拆分Java字符串
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