blocks|key|3164270|text|据我所知，Python在2.5版本之前只支持十六进制和八进制字面量。我确实发现了一些关于将二进制添加到未来版本中的讨论，但没有明确的内容。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3164271|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

As far as I can tell Python, up through 2.5, only supports hexadecimal &amp; octal literals. I did find some discussions about adding binary to future versions but nothing definite.

blocks|key|366122|text|我非常确定这是Python3.0中的变化之一，可能是与hex()和oct()一起使用的bin()。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|366123|编辑:lbrandy的答案在所有情况下都是正确的。|366124|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

I am pretty sure this is one of the things due to change in Python 3.0 with perhaps bin() to go with hex() and oct().

EDIT:
lbrandy's answer is correct in all cases.

blocks|key|366126|text|>>>+print+int('01010101111',2)
687
>>>+print+int('11111111',2)
255|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|366127|另一种方式。|unstyled|366128|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>&gt;&gt;&gt; print int('01010101111',2)
687
&gt;&gt;&gt; print int('11111111',2)
255
</code></pre>

Another way.

blocks|key|367615|text|参考-未来Python的可能性：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|367616|从Python2.6开始，您可以使用前缀0b或0B来表示二进制文字|offset|length|style|BOLD|367617|>>>+0b101111
47|code-block|syntax|javascript|367618|您还可以使用新的bin函数来获取数字的二进制表示：|367619|>>>+bin(173)
'0b10101101'|367620|文档的开发版本：What's+New+in+Python+2.6|367621|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/dev/whatsnew/2.6.html#pep-3127-integer-literal-support-and-syntax^0|0|K|2|N|2|0|0|8|3|0|0|8|O|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@$D|12|E|13|F|G]|$D|14|E|15|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|16|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|17|8|@$D|18|E|19|F|G]]|9|@]|A|$]]|$1|O|3|P|5|J|7|1A|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|1B|8|@]|9|@$D|1C|E|1D|1|1E]]|A|$]]|$1|S|3|-4|5|6|7|1F|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

For reference&mdash;future Python possibilities: 
Starting with Python 2.6 you can express binary literals using the prefix 0b or 0B:

<pre><code>&gt;&gt;&gt; 0b101111
47
</code></pre>

You can also use the new bin function to get the binary representation of a number:

<pre><code>&gt;&gt;&gt; bin(173)
'0b10101101'
</code></pre>

Development version of the documentation: <a href="http://docs.python.org/dev/whatsnew/2.6.html#pep-3127-integer-literal-support-and-syntax" rel="noreferrer">What's New in Python 2.6</a>

blocks|key|366251|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|366252|如何在Python语言中表达二进制文字？|blockquote|366253|366254|366255|它们不是“二进制”字面值，而是“整型字面值”。您可以使用0后跟B或b后跟一系列0和1的二进制格式来表示整数文字，例如：|offset|length|style|CODE|366256|>>>+0b0010101010
170
>>>+0B010101
21|code-block|syntax|javascript|366257|在Python3+docs中，以下是在Python语言中提供整数文字的方法：|366258|366259|整数文字由以下词法定义描述：|366260|366261|366262|除了可以存储在可用内存中的内容之外，对整型文字的长度没有限制。|366263|请注意，非零十进制数中不允许使用前导零。这是为了消除C风格的八进制字面量的歧义，Python在3.0版之前使用了这种字面量。|366264|整数字面量的一些示例：|366265|7+2147483647+0o177+0b100110111+3+79228162514264337593543950336+0o377+0xDeadBeans+100_000_000_000+0b_1110_0101|366266|版本3.6中的更改:现在允许使用下划线对文字进行分组。|366267|366268|表示二进制的其他方式：|366269|你可以在一个字符串对象中包含0和1，它是可以操作的(尽管在大多数情况下，你可能只需要对整数进行逐位操作)--只需传递int，0和1组成的字符串以及你要转换的基数(2)：|366270|>>>+int('010101',+2)
21|366271|您可以选择使用0b或0B前缀：|366272|>>>+int('0b0010101010',+2)
170|366273|如果你将它作为基数传递给0，如果字符串没有指定前缀，它将假定基数为10：|366274|>>>+int('10101',+0)
10101
>>>+int('0b10101',+0)
21|366275|将int转换回人类可读的二进制：|366276|您可以将一个整数传递给bin，以查看二进制文字的字符串表示：|366277|>>>+bin(21)
'0b10101'|366278|您可以结合使用bin和int来来回切换：|366279|>>>+bin(int('010101',+2))
'0b10101'|366280|如果您想要最小宽度和前面的零，您也可以使用格式规范：|366281|>>>+format(int('010101',+2),+'{fill}{width}b'.format(width=10,+fill=0))
'0000010101'
>>>+format(int('010101',+2),+'010b')
'0000010101'|366282|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/reference/lexical_analysis.html#integer-literals^0|0|0|0|0|S|1|V|1|X|1|0|0|9|4|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|7|2|A|2|0|0|C|1|0|0|0|0|0|7|3|B|3|0|0|0|0^^$0|@$1|2|3|-4|4|5|6|28|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|29|7|@]|8|@]|9|$]]|$1|D|3|-4|4|5|6|2A|7|@]|8|@]|9|$]]|$1|E|3|-4|4|5|6|2B|7|@]|8|@]|9|$]]|$1|F|3|G|4|5|6|2C|7|@$H|2D|I|2E|J|K]|$H|2F|I|2G|J|K]|$H|2H|I|2I|J|K]]|8|@]|9|$]]|$1|L|3|M|4|N|6|2J|7|@]|8|@]|9|$O|P]]|$1|Q|3|R|4|5|6|2K|7|@]|8|@$H|2L|I|2M|1|2N]]|9|$]]|$1|S|3|-4|4|5|6|2O|7|@]|8|@]|9|$]]|$1|T|3|U|4|C|6|2P|7|@]|8|@]|9|$]]|$1|V|3|-4|4|5|6|2Q|7|@]|8|@]|9|$]]|$1|W|3|-4|4|5|6|2R|7|@]|8|@]|9|$]]|$1|X|3|Y|4|5|6|2S|7|@]|8|@]|9|$]]|$1|Z|3|10|4|5|6|2T|7|@]|8|@]|9|$]]|$1|11|3|12|4|5|6|2U|7|@]|8|@]|9|$]]|$1|13|3|14|4|5|6|2V|7|@]|8|@]|9|$]]|$1|15|3|16|4|5|6|2W|7|@]|8|@]|9|$]]|$1|17|3|-4|4|5|6|2X|7|@]|8|@]|9|$]]|$1|18|3|19|4|5|6|2Y|7|@]|8|@]|9|$]]|$1|1A|3|1B|4|5|6|2Z|7|@]|8|@]|9|$]]|$1|1C|3|1D|4|N|6|30|7|@]|8|@]|9|$O|P]]|$1|1E|3|1F|4|5|6|31|7|@$H|32|I|33|J|K]|$H|34|I|35|J|K]]|8|@]|9|$]]|$1|1G|3|1H|4|N|6|36|7|@]|8|@]|9|$O|P]]|$1|1I|3|1J|4|5|6|37|7|@$H|38|I|39|J|K]]|8|@]|9|$]]|$1|1K|3|1L|4|N|6|3A|7|@]|8|@]|9|$O|P]]|$1|1M|3|1N|4|5|6|3B|7|@]|8|@]|9|$]]|$1|1O|3|1P|4|5|6|3C|7|@]|8|@]|9|$]]|$1|1Q|3|1R|4|N|6|3D|7|@]|8|@]|9|$O|P]]|$1|1S|3|1T|4|5|6|3E|7|@$H|3F|I|3G|J|K]|$H|3H|I|3I|J|K]]|8|@]|9|$]]|$1|1U|3|1V|4|N|6|3J|7|@]|8|@]|9|$O|P]]|$1|1W|3|1X|4|5|6|3K|7|@]|8|@]|9|$]]|$1|1Y|3|1Z|4|N|6|3L|7|@]|8|@]|9|$O|P]]|$1|20|3|-4|4|5|6|3M|7|@]|8|@]|9|$]]]|21|$22|$4|23|24|25|9|$26|27]]]]

<blockquote>
 <h1>How do you express binary literals in Python?</h1>
</blockquote>

They're not "binary" literals, but rather, "integer literals". You can express integer literals with a binary format with a <code>0</code> followed by a <code>B</code> or <code>b</code> followed by a series of zeros and ones, for example:

<pre><code>&gt;&gt;&gt; 0b0010101010
170
&gt;&gt;&gt; 0B010101
21
</code></pre>

From the Python 3 <a href="https://docs.python.org/3/reference/lexical_analysis.html#integer-literals" rel="noreferrer">docs</a>, these are the ways of providing integer literals in Python:

<blockquote>
 Integer literals are described by the following lexical definitions:

<pre><code>integer ::= decinteger | bininteger | octinteger | hexinteger
decinteger ::= nonzerodigit (["_"] digit)* | "0"+ (["_"] "0")*
bininteger ::= "0" ("b" | "B") (["_"] bindigit)+
octinteger ::= "0" ("o" | "O") (["_"] octdigit)+
hexinteger ::= "0" ("x" | "X") (["_"] hexdigit)+
nonzerodigit ::= "1"..."9"
digit ::= "0"..."9"
bindigit ::= "0" | "1"
octdigit ::= "0"..."7"
hexdigit ::= digit | "a"..."f" | "A"..."F"
</code></pre>
 
 There is no limit for the length of integer literals apart from what
 can be stored in available memory.
 
 Note that leading zeros in a non-zero decimal number are not allowed.
 This is for disambiguation with C-style octal literals, which Python
 used before version 3.0.
 
 Some examples of integer literals:

<pre><code>7 2147483647 0o177 0b100110111
3 79228162514264337593543950336 0o377 0xdeadbeef
 100_000_000_000 0b_1110_0101
</code></pre>
 
 Changed in version 3.6: Underscores are now allowed for grouping purposes in literals.
</blockquote>

<h2>Other ways of expressing binary:</h2>

You can have the zeros and ones in a string object which can be manipulated (although you should probably just do bitwise operations on the integer in most cases) - just pass int the string of zeros and ones and the base you are converting from (2):

<pre><code>&gt;&gt;&gt; int('010101', 2)
21
</code></pre>

You can optionally have the <code>0b</code> or <code>0B</code> prefix:

<pre><code>&gt;&gt;&gt; int('0b0010101010', 2)
170
</code></pre>

If you pass it <code>0</code> as the base, it will assume base 10 if the string doesn't specify with a prefix:

<pre><code>&gt;&gt;&gt; int('10101', 0)
10101
&gt;&gt;&gt; int('0b10101', 0)
21
</code></pre>

<h2>Converting from int back to human readable binary:</h2>

You can pass an integer to bin to see the string representation of a binary literal:

<pre><code>&gt;&gt;&gt; bin(21)
'0b10101'
</code></pre>

And you can combine <code>bin</code> and <code>int</code> to go back and forth:

<pre><code>&gt;&gt;&gt; bin(int('010101', 2))
'0b10101'
</code></pre>

You can use a format specification as well, if you want to have minimum width with preceding zeros:

<pre><code>&gt;&gt;&gt; format(int('010101', 2), '{fill}{width}b'.format(width=10, fill=0))
'0000010101'
&gt;&gt;&gt; format(int('010101', 2), '010b')
'0000010101'
</code></pre>

blocks|key|371090|text|开始处的0指定基数是8(而不是10)，这很容易看出：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|371091|>>>+int('010101',+0)
4161|code-block|syntax|javascript|371092|如果不是以0开头，那么python会假定数字是以10为基数的。|371093|>>>+int('10101',+0)
10101|371094|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

0 in the start here specifies that the base is 8 (not 10), which is pretty easy to see: 

<pre><code>&gt;&gt;&gt; int('010101', 0)
4161
</code></pre>

If you don't start with a 0, then python assumes the number is base 10.

<pre><code>&gt;&gt;&gt; int('10101', 0)
10101
</code></pre>

blocks|key|3164658|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3164659|如下所示：|3164660|def+getInt(binNum+=+0):
++++return+eval(eval('0b'+%2B+str(n)))|code-block|syntax|javascript|3164661|我想这也是一种方法。我希望这是一个令人满意的答案：|3164662|entityMap^0|0|0|0|0^^$0|@$1|2|3|-4|4|5|6|L|7|@]|8|@]|9|$]]|$1|A|3|B|4|5|6|M|7|@]|8|@]|9|$]]|$1|C|3|D|4|E|6|N|7|@]|8|@]|9|$F|G]]|$1|H|3|I|4|5|6|O|7|@]|8|@]|9|$]]|$1|J|3|-4|4|5|6|P|7|@]|8|@]|9|$]]]|K|$]]

Another good method to get an integer representation from binary is to use eval()
Like so:
<pre><code>def getInt(binNum = 0):
 return eval(eval('0b' + str(n)))
</code></pre>
I guess this is a way to do it too.
I hope this is a satisfactory answer :D

blocks|key|368204|text|我已经在+3.6.9中尝试过了|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|368205|将二进制转换为十进制|368206|>>>+0b101111
47

>>>+int('101111',2)
47|code-block|syntax|javascript|368207|将十进制转换为二进制|368208|>>>+bin(47)
'0b101111'|368209|将0作为第二个参数，并假定其为十进制。|368210|>>>+int('101111',0)
101111|368211|entityMap^0|4|6|0|0|A|0|0|0|A|0|0|0|J|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|O|3|P|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|S|3|T|5|J|7|1A|8|@]|D|@]|E|$K|L]]|$1|U|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|V|$]]

I've tried this in Python 3.6.9
Convert Binary to Decimal
<pre><code>&gt;&gt;&gt; 0b101111
47

&gt;&gt;&gt; int('101111',2)
47
</code></pre>
Convert Decimal to binary
<pre><code>&gt;&gt;&gt; bin(47)
'0b101111'
</code></pre>
Place a 0 as the second parameter python assumes it as decimal.
<pre><code>&gt;&gt;&gt; int('101111',0)
101111
</code></pre>

How do you express an integer as a binary number with Python literals?

I was easily able to find the answer for hex:

<pre><code>&gt;&gt;&gt; 0x12AF
4783
&gt;&gt;&gt; 0x100
256
</code></pre>

and octal:

<pre><code>&gt;&gt;&gt; 01267
695
&gt;&gt;&gt; 0100
64
</code></pre>

How do you use literals to express binary in Python?

<hr>

Summary of Answers

<ul>
<li>Python 2.5 and earlier: can express binary using <code>int('01010101111',2)</code> but not with a literal.</li>
<li>Python 2.5 and earlier: there is no way to express binary literals.</li>
<li>Python 2.6 beta: You can do like so: <code>0b1100111</code> or <code>0B1100111</code>.</li>
<li>Python 2.6 beta: will also allow <code>0o27</code> or <code>0O27</code> (second character is the letter O) to represent an octal.</li>
<li>Python 3.0 beta: Same as 2.6, but will no longer allow the older <code>027</code> syntax for octals.</li>
</ul>

How do you express binary literals in Python?

Python

如何使用Python文字将整数表示为二进制数？我很容易就能找到十六进制的答案：>>> 0x12AF4783>>> 0x100256和八进制：>>> 01267695>>> 010064在中如何使用文字来表示二进制？答案摘要literals.Python Python2.5和更早版本:可以使用int('010101011...

问如何在Python中表达二进制文字？
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