blocks|key|1043396|text|您可以使用%25s格式的字符串，使用datetime.strftime获取纪元格式的时间：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1043397|def+expires():
++++future+=+datetime.datetime.now()+%2B+datetime.timedelta(seconds=5*60)
++++return+int(future.strftime("%25s"))|code-block|syntax|javascript|1043398|注意:这只在linux下有效，此方法不适用于时区。|1043399|entityMap^0|5|2|G|H|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

You can use <code>datetime.strftime</code> to get the time in Epoch form, using the <code>%s</code> format string:

<pre><code>def expires():
 future = datetime.datetime.now() + datetime.timedelta(seconds=5*60)
 return int(future.strftime("%s"))
</code></pre>

Note:
 This only works under linux, and this method doesn't work with timezones.

blocks|key|1258391|text|另一种方法是使用calendar.timegm|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1258392|future+=+datetime.datetime.utcnow()+%2B+datetime.timedelta(minutes=5)
return+calendar.timegm(future.timetuple())|code-block|syntax|javascript|1258393|它也比strftime的%25s标志更容易移植(这在Windows上不起作用)。|1258394|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/3.3/library/calendar.html#calendar.timegm^0|8|F|8|F|0|0|0|3|8|C|2|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Another way is to use <a href="http://docs.python.org/3.3/library/calendar.html#calendar.timegm" rel="noreferrer"><code>calendar.timegm</code></a>:

<pre><code>future = datetime.datetime.utcnow() + datetime.timedelta(minutes=5)
return calendar.timegm(future.timetuple())
</code></pre>

It's also more portable than <code>%s</code> flag to <code>strftime</code> (which doesn't work on Windows).

blocks|key|1258419|text|刚刚发现了这个，而且更短。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1258420|import+time
def+expires():
++++'''return+a+UNIX+style+timestamp+representing+5+minutes+from+now'''
++++return+int(time.time()%2B300)|code-block|syntax|javascript|1258421|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just found this, and its even shorter.

<pre><code>import time
def expires():
 '''return a UNIX style timestamp representing 5 minutes from now'''
 return int(time.time()+300)
</code></pre>

blocks|key|1258912|text|关键是要确保在开始转换之前，您正在使用的所有日期都在utc时区内。请参阅http://pytz.sourceforge.net/以了解如何正确执行此操作。通过标准化到utc，您可以消除夏令时转换的模糊性。然后，您可以安全地使用timedelta计算与unix纪元的距离，然后将其转换为秒或毫秒。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1258913|请注意，生成的unix时间戳本身位于UTC时区。如果您希望查看本地化时区中的时间戳，则需要进行另一次转换。|1258914|还要注意，这只适用于1970年之后的日期。|1258915|+++import+datetime
+++import+pytz

+++UNIX_EPOCH+=+datetime.datetime(1970,+1,+1,+0,+0,+tzinfo+=+pytz.utc)
+++def+EPOCH(utc_datetime):
++++++delta+=+utc_datetime+-+UNIX_EPOCH
++++++seconds+=+delta.total_seconds()
++++++ms+=+seconds+*+1000
++++++return+ms|code-block|syntax|javascript|1258916|entityMap|0|LINK|mutability|MUTABLE|url|http://pytz.sourceforge.net/^0|10|S|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|6|7|Y|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|Z|8|@]|9|@]|C|$]]|$1|H|3|I|5|J|7|10|8|@]|9|@]|C|$K|L]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

The key is to ensure all the dates you are using are in the utc timezone before you start converting. See <a href="http://pytz.sourceforge.net/" rel="nofollow">http://pytz.sourceforge.net/</a> to learn how to do that properly. By normalizing to utc, you eliminate the ambiguity of daylight savings transitions. Then you can safely use timedelta to calculate distance from the unix epoch, and then convert to seconds or milliseconds.

Note that the resulting unix timestamp is itself in the UTC timezone. If you wish to see the timestamp in a localized timezone, you will need to make another conversion.

Also note that this will only work for dates after 1970.

<pre><code> import datetime
 import pytz

 UNIX_EPOCH = datetime.datetime(1970, 1, 1, 0, 0, tzinfo = pytz.utc)
 def EPOCH(utc_datetime):
 delta = utc_datetime - UNIX_EPOCH
 seconds = delta.total_seconds()
 ms = seconds * 1000
 return ms
</code></pre>

blocks|key|1258925|text|def+in_unix(input):
++start+=+datetime.datetime(year=1970,month=1,day=1)
++diff+=+input+-+start
++return+diff.total_seconds()|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1258926|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>def in_unix(input):
 start = datetime.datetime(year=1970,month=1,day=1)
 diff = input - start
 return diff.total_seconds()
</code></pre>

blocks|key|1044051|text|下面是一个从datetime对象转换为posix的较好的datetime-based解决方案：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1044052|future+=+datetime.datetime.utcnow()+%2B+datetime.timedelta(minutes=5)
return+(future+-+datetime.datetime(1970,+1,+1)).total_seconds()|code-block|syntax|javascript|1044053|欲了解更多详情，请访问Converting+datetime.date+to+UTC+timestamp+in+Python。|1044054|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/8778548/4279^0|S|8|0|0|B|1F|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Here's a less broken <code>datetime</code>-based solution to convert from datetime object to posix timestamp:

<pre><code>future = datetime.datetime.utcnow() + datetime.timedelta(minutes=5)
return (future - datetime.datetime(1970, 1, 1)).total_seconds()
</code></pre>

See more details at <a href="https://stackoverflow.com/a/8778548/4279">Converting datetime.date to UTC timestamp in Python</a>.

blocks|key|1044058|text|def+expiration_time():
++++import+datetime,calendar
++++timestamp+=+calendar.timegm(datetime.datetime.now().timetuple())
++++returnValue+=+datetime.timedelta(minutes=5).total_seconds()+%2B+timestamp
++++return+returnValue|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1044059|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>def expiration_time():
 import datetime,calendar
 timestamp = calendar.timegm(datetime.datetime.now().timetuple())
 returnValue = datetime.timedelta(minutes=5).total_seconds() + timestamp
 return returnValue
</code></pre>

blocks|key|1044078|text|这就是你所需要的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1044079|import+time
import+datetime
n+=+datetime.datetime.now()
unix_time+=+time.mktime(n.timetuple())|code-block|syntax|javascript|1044080|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is what you need:

<pre><code>import time
import datetime
n = datetime.datetime.now()
unix_time = time.mktime(n.timetuple())
</code></pre>

blocks|key|1044110|text|下面是基于上面的答案(加上毫秒的校正)，并在使用时区的情况下模拟Python3.3之前版本的datetime.timestamp()。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1044111|def+datetime_timestamp(datetime):
++++'''
++++Equivalent+to+datetime.timestamp()+for+pre-3.3
++++'''
++++try:
++++++++return+datetime.timestamp()
++++except+AttributeError:
++++++++utc_datetime+=+datetime.astimezone(utc)
++++++++return+timegm(utc_datetime.timetuple())+%2B+utc_datetime.microsecond+/+1e6|code-block|syntax|javascript|1044112|严格地回答这个问题，你会想要：|1044113|datetime_timestamp(my_datetime)+%2B+5+*+60|1044114|datetime_timestamp是simple-date的一部分。但是如果你使用的是这个包，你可能会输入：|1044115|SimpleDate(my_datetime).timestamp+%2B+5+*+60|1044116|它为my_datetime处理更多的格式/类型。|1044117|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/andrewcooke/simple-date^0|1A|K|0|0|0|0|0|I|J|B|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|16|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@$9|1B|A|1C|1|1D]]|E|$]]|$1|Q|3|R|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1F|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]]|V|$W|$5|X|Y|Z|E|$10|11]]]]

The following is based on the answers above (plus a correction for the milliseconds) and emulates <code>datetime.timestamp()</code> for Python 3 before 3.3 when timezones are used.

<pre><code>def datetime_timestamp(datetime):
 '''
 Equivalent to datetime.timestamp() for pre-3.3
 '''
 try:
 return datetime.timestamp()
 except AttributeError:
 utc_datetime = datetime.astimezone(utc)
 return timegm(utc_datetime.timetuple()) + utc_datetime.microsecond / 1e6
</code></pre>

To strictly answer the question as asked, you'd want:

<pre><code>datetime_timestamp(my_datetime) + 5 * 60
</code></pre>

<code>datetime_timestamp</code> is part of <a href="https://github.com/andrewcooke/simple-date" rel="nofollow">simple-date</a>. But if you were using that package you'd probably type:

<pre><code>SimpleDate(my_datetime).timestamp + 5 * 60
</code></pre>

which handles many more formats / types for my_datetime.

blocks|key|1044161|text|请注意，使用timedelta.total_seconds()的解决方案可以在python-2.7%2B上运行。对于较低版本的Python，请使用calendar.timegm(future.utctimetuple())。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1044162|entityMap^0|6|P|1Z|12|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

Note that solutions with <code>timedelta.total_seconds()</code> work on python-2.7+.
Use <code>calendar.timegm(future.utctimetuple())</code> for lower versions of Python.

blocks|key|1259116|text|使用内置时间戳函数的这种方法怎么样？代码片段在不同的时间(不只是当前时间)工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1259117|import+datetime

a+=+"2017-01-01+14:30:00"
b+=+datetime.datetime.strptime(a,+'%25Y-%25m-%25d+%25H:%25M:%25S')
c+=+int(b.timestamp()/60.0)
alarm_time+=+c+%2B+5|code-block|syntax|javascript|1259118|运行环境和操作系统:+Ubuntu+16.04和Python+3.6|1259119|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

How about this method using built-in timestamp function? The snippet is working for different time (not just current time).
<pre><code>import datetime

a = &quot;2017-01-01 14:30:00&quot;
b = datetime.datetime.strptime(a, '%Y-%m-%d %H:%M:%S')
c = int(b.timestamp()/60.0)
alarm_time = c + 5
</code></pre>
Runtime environment
  OS: Ubuntu 16.04
  Python 3.6

I have to create an "Expires" value 5 minutes in the future, but I have to supply it in UNIX Timestamp format. I have this so far, but it seems like a hack.

<pre><code>def expires():
 '''return a UNIX style timestamp representing 5 minutes from now'''
 epoch = datetime.datetime(1970, 1, 1)
 seconds_in_a_day = 60 * 60 * 24
 five_minutes = datetime.timedelta(seconds=5*60)
 five_minutes_from_now = datetime.datetime.now() + five_minutes
 since_epoch = five_minutes_from_now - epoch
 return since_epoch.days * seconds_in_a_day + since_epoch.seconds
</code></pre>

Is there a module or function that does the timestamp conversion for me?

Python Create unix timestamp five minutes in the future

Windows

Python

Ubuntu

我必须在未来5分钟内创建一个"Expires“值，但我必须以UNIX时间戳格式提供它。到目前为止，我有这个，但它看起来像是一个黑客。def expires():    '''return a UNIX style timestamp representing 5 minutes from now'''    epoch...

问Python在未来五分钟内创建unix时间戳
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