blocks|key|446116|text|尝试以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|446117|mystring=+mystring.replace(/"/g,+"").replace(/'/g,+"").replace(/$%7C$/g,+"");|code-block|syntax|javascript|446118|用一点REGEX来抓取那些讨厌的括号。|446119|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Try the following:

<pre><code>mystring= mystring.replace(/"/g, "").replace(/'/g, "").replace(/$|$/g, "");
</code></pre>

A little bit of REGEX to grab those pesky parentheses.

blocks|key|446169|text|这应该是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|446170|mystring=+mystring.replace(/"/g,+"").replace(/'/g,+"").replace(/$/g,+"").replace(/$/g,+"");|code-block|syntax|javascript|446171|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

That should work :

<pre><code>mystring= mystring.replace(/"/g, "").replace(/'/g, "").replace(/$/g, "").replace(/$/g, "");
</code></pre>

blocks|key|660683|text|你应该使用更像这样的东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|660684|mystring+=+mystring.replace(/["'()]/g,"");|code-block|syntax|javascript|660685|它不适用于其他的原因是因为您忘记了"global“参数(g)|660686|请注意，[...]是一个字符类。这些括号之间的任何内容都将被替换。|offset|length|style|CODE|660687|entityMap^0|0|0|0|4|5|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@$K|U|L|V|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You should use something more like this:

<pre><code>mystring = mystring.replace(/["'()]/g,"");
</code></pre>

The reason it wasn't working for the others is because you forgot the "global" argument (g)

note that <code>[...]</code> is a character class. anything between those brackets is replaced.

blocks|key|446349|text|这是因为要替换多个匹配项，必须使用正则表达式作为使用字符串文字的搜索字符串。正如您已经发现的，按字符串搜索只会替换第一个匹配项。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|446350|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

That's because to replace multiple occurrences you must use a regex as the search string where you are using a string literal. As you have found searching by strings will only replace the first occurrence.

blocks|key|660845|text|如果你正在寻找括号，你也可以使用常规的专家，你只需要对它们进行转义。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|660846|mystring+=+mystring.replace(/$%7C$/g,+'');|code-block|syntax|javascript|660847|这将删除整个字符串中的所有(和)。|offset|length|style|CODE|660848|entityMap^0|0|0|D|1|F|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

You can also use a regular experession if you're looking for parenthesis, you just need to escape them.

<pre><code>mystring = mystring.replace(/$|$/g, '');
</code></pre>

This will remove all <code>(</code> and <code>)</code> in the entire string.

blocks|key|660885|text|基于字符串的替换方法不会全局替换。因此，您可能希望使用基于regex的替换方法。需要注意的是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|660886|您需要转义(和)，因为它们用于组匹配：|offset|length|style|CODE|660887|mystring=+mystring.replace(/"/g,+"").replace(/'/g,+"").replace(/$/g,+"").replace(/$/g,+"");|code-block|syntax|javascript|660888|entityMap^0|0|5|1|7|1|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]|$D|S|E|T|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|U|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

The string-based replace method will not replace globally. As such, you probably want to use the regex-based replacing method. It should be noted:

You need to escape <code>(</code> and <code>)</code> as they are used for group matching:

<pre><code>mystring= mystring.replace(/"/g, "").replace(/'/g, "").replace(/$/g, "").replace(/$/g, "");
</code></pre>

blocks|key|446492|text|只需替换一次即可：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|446493|"\"a(b)c'd{e}f[g]".replace(/[\[\]{}'"]/g,"")|code-block|syntax|javascript|446494|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just one replace will do: 

<pre><code>"\"a(b)c'd{e}f[g]".replace(/[\[\]{}'"]/g,"")
</code></pre>

blocks|key|660954|text|这可以解决这个问题：myString+=+myString.replace(/\"%7C\'%7C$%7C$/)+Example|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|660955|entityMap|0|LINK|mutability|MUTABLE|url|https://jsfiddle.net/xztf5ers/^0|A|16|1H|7|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

This can solve the problem:
<code>myString = myString.replace(/\"|\'|$|$/)</code>
<a href="https://jsfiddle.net/xztf5ers/" rel="nofollow noreferrer">Example</a>

I tried this:

<pre><code>mystring= mystring.replace(/"/g, "").replace(/'/g, "").replace("(", "").replace(")", "");
</code></pre>

It works for all double and single quotes but for parentheses, this only replaces the first parenthesis in the string.

How can I make it work to replace all parentheses in the string using JavaScript? Or replace all special characters in a string?

jQuery - Replace all parentheses in a string

我试过这个：mystring= mystring.replace(/"/g, "").replace(/'/g, "").replace("(", "").replace(")", "");它适用于所有双引号和单引号，但对于圆括号，它只替换字符串中的第一个圆括号。如何使用JavaScript替换字符串中的所有括号？或者...

问jQuery -替换字符串中的所有括号
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