blocks|key|1948795|text|可能是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1948796|String+s+=+"abcd,fg;ijkl,+cas";
String+result+=+s.substring(s.lastIndexOf(',')+%2B+1).trim();|code-block|syntax|javascript|1948797|也就是说，我取最后一个逗号后面的子字符串，然后删除周围的空格...|1948798|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Perhaps something like:

<pre><code>String s = "abcd,fg;ijkl, cas";
String result = s.substring(s.lastIndexOf(',') + 1).trim();
</code></pre>

That is, I take the substring occurring after the last comma and remove surrounding white space afterwards...

blocks|key|1735362|text|你可以试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1735363|public+static+void+main(String[]+args)+{
++++String+s+=+"+abcd,fg;ijkl,+cas";
++++String[]+words+=+s.split(",");
++++System.out.println(words[words.length-1].trim());
}|code-block|syntax|javascript|1735364|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could try this:

<pre><code>public static void main(String[] args) {
 String s = " abcd,fg;ijkl, cas";
 String[] words = s.split(",");
 System.out.println(words[words.length-1].trim());
}
</code></pre>

blocks|key|1735414|text|只有一个空格：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1735415|String[]+aux+=+theInputString.split(",\\s");
string+result+=+aux[aux.length-1];|code-block|syntax|javascript|1735416|0到n个空格：|1735417|String[]+aux+=+theInputString.split(",\\s*");
string+result+=+aux[aux.length-1];|1735418|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Only one space:

<pre><code>String[] aux = theInputString.split(",\\s");
string result = aux[aux.length-1];
</code></pre>

0 to n spaces:

<pre><code>String[] aux = theInputString.split(",\\s*");
string result = aux[aux.length-1];
</code></pre>

blocks|key|1735424|text|str.split(",");|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1735425|然后|unstyled|1735426|str.trim()|1735427|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>str.split(",");
</code></pre>

then 

<pre><code>str.trim()
</code></pre>

blocks|key|1735502|text|下面是什么呢？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1735503|String+a+=+"abcd,fg;ijkl,+cas";
String[]+result+=+a.split(",[+]*");
String+expectedResult+=+result[result.length+-+1]);|code-block|syntax|javascript|1735504|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

What about the following:

<pre><code>String a = "abcd,fg;ijkl, cas";
String[] result = a.split(",[ ]*");
String expectedResult = result[result.length - 1]);
</code></pre>

blocks|key|1949044|text|还有一个:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1949045|String+s+=+"abcd,fg;ijkl,+cas";
String+result+=+s.replaceAll(".*,+",+"");|code-block|syntax|javascript|1949046|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

and one more :)

<pre><code>String s = "abcd,fg;ijkl, cas";
String result = s.replaceAll(".*, ", "");
</code></pre>

blocks|key|1735634|text|我用答案来解决我的问题，它只需要从路径中提取文件名，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1735635|String+s+=+"C:\\\\Users\\\\Blue+Tag\\\\Files\\\\Upload\\\\samplejpg.jpg";+String+result+=+s.substring(s.lastIndexOf('\\')+%2B+1).trim();|offset|length|style|CODE|1735636|entityMap^0|0|0|3Q|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

I used the answers to solve my problem, it just need to extract the file name from path,
<code>String s = &quot;C:\\\\Users\\\\Blue Tag\\\\Files\\\\Upload\\\\samplejpg.jpg&quot;; String result = s.substring(s.lastIndexOf('\\') + 1).trim();</code>

How do I get the content after the last comma in a string using a regular expression?

Example: 

<pre><code>abcd,fg;ijkl, cas
</code></pre>

The output should be <code>cas</code>

<hr>

Note: There is a space between last comma and <code>'c'</code> character which also needs to be removed. 
Also the pattern contains only one space after last comma.

How to get the string after last comma in java?

如何使用正则表达式获取字符串中最后一个逗号之后的内容？示例：abcd,fg;ijkl, cas输出应为cas注意:最后一个逗号和'c'字符之间有一个空格，也需要删除。此外，该模式在最后一个逗号后仅包含一个空格。

问如何在java中获取最后一个逗号后的字符串？
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问如何在java中获取最后一个逗号后的字符串？
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