blocks|key|324885|text|将字符串拆分成组件，并通过空格将它们连接起来：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|324886|NSString+*newString+=+[[myString+componentsSeparatedByCharactersInSet:[NSCharacterSet+newlineCharacterSet]]+componentsJoinedByString:@"+"];|code-block|syntax|javascript|324887|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Split the string into components and join them by space:

<pre><code>NSString *newString = [[myString componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]] componentsJoinedByString:@" "];
</code></pre>

blocks|key|3077064|text|我正在使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3077065|[...]
myString+=+[myString+stringByReplacingOccurrencesOfString:@"\n\n"+withString:@"\n"];
[...]|code-block|syntax|javascript|3077066|/Paul|3077067|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I'm using 

<pre><code>[...]
myString = [myString stringByReplacingOccurrencesOfString:@"\n\n" withString:@"\n"];
[...]
</code></pre>

/Paul

blocks|key|324894|text|将字符串拆分成组件并重新连接它们是一种非常冗长的方法。我也使用保罗提到的相同方法。您可以替换出现的任何字符串。根据Paul所说，您可以将换行符替换为如下所示的空格：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|324895|myString+=+[myString+stringByReplacingOccurrencesOfString:@"\n"+withString:@"+"];|code-block|syntax|javascript|324896|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Splitting the string into components and rejoining them is a very long-winded way to do this. I too use the same method Paul mentioned. You can replace any string occurrences. Further to what Paul said you can replace new line characters with spaces like this:

<pre><code>myString = [myString stringByReplacingOccurrencesOfString:@"\n" withString:@" "];
</code></pre>

blocks|key|324256|text|我的案例还包含\r，包括\n，[NSCharacterSet+newlineCharacterSet]不起作用，而是使用|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|324257|htmlContent+=+[htmlContent+stringByReplacingOccurrencesOfString:@"[\r\n]"
+++++++++++++++++++++++++++++++++++++++++++++++++++++withString:@""
++++++++++++++++++++++++++++++++++++++++++++++++++++++++options:NSRegularExpressionSearch
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++range:NSMakeRange(0,+htmlContent.length)];|code-block|syntax|javascript|324258|解决了我的问题。|324259|顺便说一句，\\s将删除所有空格，这不是预期的。|324260|entityMap^0|7|2|C|2|F|10|0|0|0|6|3|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|P|$]]

My case also contains <code>\r</code>, including <code>\n</code>, <code>[NSCharacterSet newlineCharacterSet]</code> does not work, instead, by using

<pre><code>htmlContent = [htmlContent stringByReplacingOccurrencesOfString:@"[\r\n]"
 withString:@""
 options:NSRegularExpressionSearch
 range:NSMakeRange(0, htmlContent.length)];
</code></pre>

solved my problem.

Btw, <code>\\s</code> will remove all white spaces, which is not expected.

blocks|key|324902|text|在这里提供@hallski答案的Swift+3.0版本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|324903|self.content+=+self.content.components(separatedBy:+CharacterSet.newlines).joined(separator:+"+")|code-block|syntax|javascript|324904|在这里提供@Kjuly答案的Swift+3.0版本(注意，它只用一行\n替换了任何数量的新行。如果有人可以给我指出一个更好的方法，我倾向于不使用正则表达式)：|324905|self.content+=+self.content.replacingOccurrences(of:+"[\r\\n]%2B",+with:+"\n",+options:+.regularExpression,+range:+Range(uncheckedBounds:+(lower:+self.content.startIndex,+upper:+self.content.endIndex)));|324906|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Providing a Swift 3.0 version of @hallski 's answer here: 

<pre><code>self.content = self.content.components(separatedBy: CharacterSet.newlines).joined(separator: " ")
</code></pre>

Providing a Swift 3.0 version of @Kjuly 's answer here (Note it replaces any number of new lines with just one \n. I would prefer to not use regular express if someone can point me a better way): 

<pre><code>self.content = self.content.replacingOccurrences(of: "[\r\\n]+", with: "\n", options: .regularExpression, range: Range(uncheckedBounds: (lower: self.content.startIndex, upper: self.content.endIndex)));
</code></pre>

I have a <code>NSString</code> like this:

<pre><code>Hello 
World
of
Twitter
Lets See this
&gt;
</code></pre>

I want to transform it to: 

<blockquote>
 Hello World of Twitter Lets See this >
</blockquote>

How can I do this? I'm using Objective-C on an iPhone.

Removing new line characters from NSString

Objective-C

Swift

我有一个这样的NSString：Hello WorldofTwitterLets See this>我想将其转换为：推特的 Hello World让我们看看>我该怎么做呢？我在iPhone上使用Objective-C。

问从NSString中删除换行符
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