blocks|key|441279|text|我刚刚运行了您的程序，在换行符(\n)之前添加回车符(\r)可以帮我解决这个问题。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|441280|如果您想获得系统独立的行分隔符，可以在系统属性line.separator中找到|441281|String+separator+=+System.getProperty("line.separator");
String+string+=+"This+is+lengthy+string+that+contains+many+words.+So"+%2B+separator
++++++++++++%2B+"I+am+wrapping+it.";|code-block|syntax|javascript|441282|entityMap^0|G|2|R|2|0|N|E|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|N|$]]

I just ran your program, and adding a carriage return (<code>\r</code>) before your newline (<code>\n</code>) did the trick for me.

If you want to get a system independent line separator, one can be found in the system propery <code>line.separator</code>

<pre><code>String separator = System.getProperty("line.separator");
String string = "This is lengthy string that contains many words. So" + separator
 + "I am wrapping it.";
</code></pre>

blocks|key|441313|text|有关如何正确处理换行符的问题，请参阅以下问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|441314|How+do+I+get+a+platform-dependent+new+line+character?|offset|length|441315|基本上，您想要使用|441316|String+newLineChar+=+System.getProperty("line.separator");|code-block|syntax|javascript|441317|然后使用newLineChar代替"\n“|441318|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/207947/java-how-do-i-get-a-platform-independent-new-line-character^0|0|0|1H|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

Please see the following question on how to appropriately handle newlines.

<a href="https://stackoverflow.com/questions/207947/java-how-do-i-get-a-platform-independent-new-line-character">How do I get a platform-dependent new line character?</a>

Basically you want to use

<pre><code>String newLineChar = System.getProperty("line.separator");
</code></pre>

and then use the newLineChar instead of "\n"

blocks|key|655814|text|来自JTextArea的文本将使用\n字符作为换行符，而不管它运行在哪种平台上。在将其写入文件时，您可能希望将这些字符替换为特定于平台的换行符(对于Windows，这是\r\n，正如其他人所提到的)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|655815|我认为最好的方法是将文本包装到BufferedReader中，该PrintWriter可用于迭代各行，然后使用特定于平台的换行符将每行写出到文件中。有一个涉及string.replace(...)的更短的解决方案(参见Unbeli的评论)，但它更慢，需要更多的内存。|655816|以下是我的解决方案-由于Java+8中的新功能，现在变得更加简单：|655817|public+static+void+main(String[]+args)+throws+IOException+{
++++String+string+=+"This+is+lengthy+string+that+contains+many+words.+So\nI+am+wrapping+it.";
++++System.out.println(string);
++++File+file+=+new+File("C:/Users/User/Desktop/text.txt");

++++writeToFile(string,+file);
}

private+static+void+writeToFile(String+string,+File+file)+throws+IOException+{
++++try+(
++++++++BufferedReader+reader+=+new+BufferedReader(new+StringReader(string));
++++++++PrintWriter+writer+=+new+PrintWriter(new+FileWriter(file));
++++)+{
++++++++reader.lines().forEach(line+->+writer.println(line));
++++}
}|code-block|syntax|javascript|655818|entityMap^0|2|9|H|2|2C|4|0|F|E|W|B|27|J|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|14|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|15|8|@]|D|@]|E|$M|N]]|$1|O|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|P|$]]

Text from a <code>JTextArea</code> will have <code>\n</code> characters for newlines, regardless of the platform it is running on. You will want to replace those characters with the platform-specific newline as you write it to the file (for Windows, this is <code>\r\n</code>, as others have mentioned).

I think the best way to do that is to wrap the text into a <code>BufferedReader</code>, which can be used to iterate over the lines, and then use a <code>PrintWriter</code> to write each line out to a file using the platform-specific newline. There is a shorter solution involving <code>string.replace(...)</code> (see comment by Unbeli), but it is slower and requires more memory.

Here is my solution - now made even simpler thanks to new features in Java 8:

<pre><code>public static void main(String[] args) throws IOException {
 String string = "This is lengthy string that contains many words. So\nI am wrapping it.";
 System.out.println(string);
 File file = new File("C:/Users/User/Desktop/text.txt");

 writeToFile(string, file);
}

private static void writeToFile(String string, File file) throws IOException {
 try (
 BufferedReader reader = new BufferedReader(new StringReader(string));
 PrintWriter writer = new PrintWriter(new FileWriter(file));
 ) {
 reader.lines().forEach(line -&gt; writer.println(line));
 }
}
</code></pre>

blocks|key|655872|text|如果您使用的是BufferedWriter，还可以使用.newline()方法根据您的平台重新添加换行符。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|655873|请参阅此相关问题：Strings+written+to+file+do+not+preserve+line+breaks|655874|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/8/docs/api/java/io/BufferedWriter.html#newLine--|1|https://stackoverflow.com/questions/9199216/strings-written-to-file-do-not-preserve-line-breaks^0|R|A|0|0|9|1F|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

If you are using a BufferedWriter, you could also use the <a href="https://docs.oracle.com/javase/8/docs/api/java/io/BufferedWriter.html#newLine--" rel="nofollow noreferrer">.newline()</a> method to re-add the newline based on your platform.

See this related question: <a href="https://stackoverflow.com/questions/9199216/strings-written-to-file-do-not-preserve-line-breaks">Strings written to file do not preserve line breaks</a>

blocks|key|441515|text|如果您希望将Java字符串中的回车字符保留到文件中。只需按照以下语句替换每个换行符(在java中可识别为：\n)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|441516|TempHtml+=+TempHtml.replaceAll("\n"，"\r\n")；|441517|下面是一个代码示例，|441518|++++++++//+When+Execute+button+is+pressed
++++++++String+TempHtml+=+textArea.getText();
++++++++TempHtml+=+TempHtml.replaceAll("\n",+"\r\n");
++++++++try+(PrintStream+out+=+new+PrintStream(new+FileOutputStream("C:/Temp/temp.html")))+{
++++++++++++out.print(TempHtml);
++++++++}+catch+(FileNotFoundException+e)+{
++++++++++++//+TODO+Auto-generated+catch+block
++++++++++++e.printStackTrace();
++++++++}
++++++++System.out.println(TempHtml);|code-block|syntax|javascript|441519|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|O|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|P|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you wish to keep the carriage return characters from a Java string into a file. Just replace each break line character (which is recognized in java as: \n) as per the following statement: 

TempHtml = TempHtml.replaceAll("\n", "\r\n");

Here is an code example,

<pre><code> // When Execute button is pressed
 String TempHtml = textArea.getText();
 TempHtml = TempHtml.replaceAll("\n", "\r\n");
 try (PrintStream out = new PrintStream(new FileOutputStream("C:/Temp/temp.html"))) {
 out.print(TempHtml);
 } catch (FileNotFoundException e) {
 // TODO Auto-generated catch block
 e.printStackTrace();
 }
 System.out.println(TempHtml);
</code></pre>

I am trying to write a <code>String</code>(lengthy but wrapped), which is from <code>JTextArea</code>. When the string printed to console, formatting is same as it was in <code>Text Area</code>, but when I write them to file using BufferedWriter, it is writing that <code>String</code> in single line.

Following snippet can reproduce it:

<pre><code>public class BufferedWriterTest {
 public static void main(String[] args) throws IOException {
 String string = "This is lengthy string that contains many words. So\nI am wrapping it.";
 System.out.println(string);
 File file = new File("C:/Users/User/Desktop/text.txt");
 FileWriter fileWriter = new FileWriter(file);
 BufferedWriter bufferedWriter = new BufferedWriter(fileWriter);
 bufferedWriter.write(string);
 bufferedWriter.close();
 }
}
</code></pre>

What went wrong? How to resolve this? Thanks for any help!

Strings written to file do not preserve line breaks

Windows

Java

我正在试着写一个来自JTextArea的String(冗长但包装好)。当字符串打印到控制台时，格式与在Text Area中相同，但当我使用BufferedWriter将其写入文件时，它将在单行中写入String。下面的代码片段可以重现它：public class BufferedWriterTest {    publ...

问写入文件的字符串不保留换行符
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