blocks|key|1699683|text|DateTime.ParseExact(monthName,+"MMMM",+CultureInfo.CurrentCulture+).Month|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1699684|不过，出于您的目的，最好只创建一个Dictionary<string,+int>，将月份的名称映射到它的值。|1699685|entityMap^0|0|21|0|H|N|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|P|8|@]|D|@]|E|$]]]|I|$]]

<code>DateTime.ParseExact(monthName, "MMMM", CultureInfo.CurrentCulture ).Month</code>

Although, for your purposes, you'll probably be better off just creating a <code>Dictionary&lt;string, int&gt;</code> mapping the month's name to its value.

blocks|key|1699699|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1699700|Convert.ToDate(month+%2B+"+01,+1900").Month|code-block|syntax|javascript|1699701|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could do something like this:

<pre><code>Convert.ToDate(month + " 01, 1900").Month
</code></pre>

blocks|key|1699833|text|如果您使用一些人建议的DateTime.ParseExact()-method，那么您应该仔细考虑当应用程序在非英语环境中运行时会发生什么！|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1699834|在丹麦，哪种ParseExact("Januar",+...)和ParseExact("January",+...)应该工作，哪种应该失败？|1699835|这将是CultureInfo.CurrentCulture和CultureInfo.InvariantCulture之间的区别。|1699836|entityMap^0|B|L|0|6|P|W|Q|0|3|Q|U|S|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|K|$]]

If you use the <code>DateTime.ParseExact()</code>-method that several people have suggested, you should carefully consider what you want to happen when the application runs in a non-English environment! 

In Denmark, which of <code>ParseExact("Januar", ...)</code> and <code>ParseExact("January", ...)</code> should work and which should fail? 

That will be the difference between <code>CultureInfo.CurrentCulture</code> and <code>CultureInfo.InvariantCulture</code>.

blocks|key|1700126|text|一个简单的解决方案是创建一个包含名称和值的字典。然后，您可以使用Contains()找到正确的值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1700127|Dictionary<string,+string>+months+=+new+Dictionary<string,+string>()
{
++++++++++++++++{+"january",+"01"},
++++++++++++++++{+"february",+"02"},
++++++++++++++++{+"march",+"03"},
++++++++++++++++{+"april",+"04"},
++++++++++++++++{+"may",+"05"},
++++++++++++++++{+"june",+"06"},
++++++++++++++++{+"july",+"07"},
++++++++++++++++{+"august",+"08"},
++++++++++++++++{+"september",+"09"},
++++++++++++++++{+"october",+"10"},
++++++++++++++++{+"november",+"11"},
++++++++++++++++{+"december",+"12"},
};
foreach+(var+month+in+months)
{
++++if+(StringThatContainsMonth.ToLower().Contains(month.Key))
++++{
++++++++string+thisMonth+=+month.Value;
++++}
}|code-block|syntax|javascript|1700128|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

One simply solution would be create a Dictionary with names and values. Then using Contains() you can find the right value.

<pre><code>Dictionary&lt;string, string&gt; months = new Dictionary&lt;string, string&gt;()
{
 { "january", "01"},
 { "february", "02"},
 { "march", "03"},
 { "april", "04"},
 { "may", "05"},
 { "june", "06"},
 { "july", "07"},
 { "august", "08"},
 { "september", "09"},
 { "october", "10"},
 { "november", "11"},
 { "december", "12"},
};
foreach (var month in months)
{
 if (StringThatContainsMonth.ToLower().Contains(month.Key))
 {
 string thisMonth = month.Value;
 }
}
</code></pre>

blocks|key|1699748|text|可以使用DateTime.Parse方法获取DateTime对象，然后检查其Month属性。这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1699749|int+month+=+DateTime.Parse("1."+%2B+monthName+%2B+"+2008").Month;|code-block|syntax|javascript|1699750|诀窍是构建一个有效的日期来创建DateTime对象。|1699751|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can use the DateTime.Parse method to get a DateTime object and then check its Month property. Do something like this:

<pre><code>int month = DateTime.Parse("1." + monthName + " 2008").Month;
</code></pre>

The trick is to build a valid date to create a DateTime object.

blocks|key|1699781|text|您可以使用月份的枚举：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1699782|public+enum+Month
{
++++January,
++++February,
++++//+(...)
++++December,
}++++

public+Month+ToInt(Month+Input)
{
++++return+(int)Enum.Parse(typeof(Month),+Input,+true));
}|code-block|syntax|javascript|1699783|不过，我对enum.Parse()的语法并不是百分之百确定。|1699784|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can use an enum of months:

<pre><code>public enum Month
{
 January,
 February,
 // (...)
 December,
} 

public Month ToInt(Month Input)
{
 return (int)Enum.Parse(typeof(Month), Input, true));
}
</code></pre>

I am not 100% certain on the syntax for enum.Parse(), though.

blocks|key|1484887|text|您不必创建一个DateTime实例来执行此操作。它就像这样简单：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1484888|public+static+class+Month
{
++++public+static+int+ToInt(this+string+month)
++++{
++++++++return+Array.IndexOf(
++++++++++++CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
++++++++++++month.ToLower(CultureInfo.CurrentCulture))
++++++++++++%2B+1;
++++}
}|code-block|syntax|javascript|1484889|我在da-DK区域性上运行，所以这个单元测试通过了：|offset|length|style|CODE|1484890|[Theory]
[InlineData("Januar",+1)]
[InlineData("Februar",+2)]
[InlineData("Marts",+3)]
[InlineData("April",+4)]
[InlineData("Maj",+5)]
[InlineData("Juni",+6)]
[InlineData("Juli",+7)]
[InlineData("August",+8)]
[InlineData("September",+9)]
[InlineData("Oktober",+10)]
[InlineData("November",+11)]
[InlineData("December",+12)]
public+void+Test(string+monthName,+int+expected)
{
++++var+actual+=+monthName.ToInt();
++++Assert.Equal(expected,+actual);
}|1484891|我将把创建重载的练习留给读者，您可以在其中传递显式的CultureInfo。|1484892|entityMap^0|0|0|2|5|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

You don't have to create a DateTime instance to do this. It's as simple as this:

<pre><code>public static class Month
{
 public static int ToInt(this string month)
 {
 return Array.IndexOf(
 CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
 month.ToLower(CultureInfo.CurrentCulture))
 + 1;
 }
}
</code></pre>

I'm running on the <code>da-DK</code> culture, so this unit test passes:

<pre><code>[Theory]
[InlineData("Januar", 1)]
[InlineData("Februar", 2)]
[InlineData("Marts", 3)]
[InlineData("April", 4)]
[InlineData("Maj", 5)]
[InlineData("Juni", 6)]
[InlineData("Juli", 7)]
[InlineData("August", 8)]
[InlineData("September", 9)]
[InlineData("Oktober", 10)]
[InlineData("November", 11)]
[InlineData("December", 12)]
public void Test(string monthName, int expected)
{
 var actual = monthName.ToInt();
 Assert.Equal(expected, actual);
}
</code></pre>

I'll leave it as an exercise to the reader to create an overload where you can pass in an explicit CultureInfo.

blocks|key|1700182|text|在问题提出七年后回答这个问题，可以使用内置方法进行这种比较：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1700183|Month.toInt("January")+>+Month.toInt("May")|code-block|syntax|javascript|1700184|变成了|1700185|Array.FindIndex(+CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
+++++++++++++++++t+=>+t.Equals("January",+StringComparison.CurrentCultureIgnoreCase))+>
Array.FindIndex(+CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
+++++++++++++++++t+=>+t.Equals("May",+StringComparison.CurrentCultureIgnoreCase))|1700186|为了简单起见，可以将其重构为扩展方法。下面是一个LINQPad示例(因此需要调用Dump()方法)：|offset|length|style|CODE|1700187|void+Main()
{
++++("January".GetMonthIndex()+>+"May".GetMonthIndex()).Dump();
++++("January".GetMonthIndex()+==+"january".GetMonthIndex()).Dump();
++++("January".GetMonthIndex()+<+"May".GetMonthIndex()).Dump();
}

public+static+class+Extension+{
++++public+static+int+GetMonthIndex(this+string+month)+{
++++++++return+Array.FindIndex(+CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
+++++++++++++++++++++++++t+=>+t.Equals(month,+StringComparison.CurrentCultureIgnoreCase));
++++}
}|1700188|带输出：|1700189|False
True
True|1700190|entityMap^0|0|0|0|0|14|6|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@$M|13|N|14|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|16|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

And answering this seven years after the question was asked, it is possible to do this comparison using built-in methods:

<pre><code>Month.toInt("January") &gt; Month.toInt("May")
</code></pre>

becomes

<pre><code>Array.FindIndex( CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
 t =&gt; t.Equals("January", StringComparison.CurrentCultureIgnoreCase)) &gt;
Array.FindIndex( CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
 t =&gt; t.Equals("May", StringComparison.CurrentCultureIgnoreCase))
</code></pre>

Which can be refactored into an extension method for simplicity. The following is a LINQPad example (hence the <code>Dump()</code> method calls):

<pre><code>void Main()
{
 ("January".GetMonthIndex() &gt; "May".GetMonthIndex()).Dump();
 ("January".GetMonthIndex() == "january".GetMonthIndex()).Dump();
 ("January".GetMonthIndex() &lt; "May".GetMonthIndex()).Dump();
}

public static class Extension {
 public static int GetMonthIndex(this string month) {
 return Array.FindIndex( CultureInfo.CurrentCulture.DateTimeFormat.MonthNames,
 t =&gt; t.Equals(month, StringComparison.CurrentCultureIgnoreCase));
 }
}
</code></pre>

With output:

<pre><code>False
True
True
</code></pre>

blocks|key|1699592|text|如果您使用的是c#+3.0+(或更高版本)，则可以使用扩展器|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1699593|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

If you are using c# 3.0 (or above) you can use extenders

blocks|key|1699875|text|Public+Function+returnMonthNumber(ByVal+monthName+As+String)+As+Integer
++++Select+Case+monthName.ToLower
++++++++Case+Is+=+"january"
++++++++++++Return+1
++++++++Case+Is+=+"february"
++++++++++++Return+2
++++++++Case+Is+=+"march"
++++++++++++Return+3
++++++++Case+Is+=+"april"
++++++++++++Return+4
++++++++Case+Is+=+"may"
++++++++++++Return+5
++++++++Case+Is+=+"june"
++++++++++++Return+6
++++++++Case+Is+=+"july"
++++++++++++Return+7
++++++++Case+Is+=+"august"
++++++++++++Return+8
++++++++Case+Is+=+"september"
++++++++++++Return+9
++++++++Case+Is+=+"october"
++++++++++++Return+10
++++++++Case+Is+=+"november"
++++++++++++Return+11
++++++++Case+Is+=+"december"
++++++++++++Return+12
++++++++Case+Else
++++++++++++Return+0
++++End+Select
End+Function|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1699876|注意代码是Beta版本。|unstyled|1699877|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>Public Function returnMonthNumber(ByVal monthName As String) As Integer
 Select Case monthName.ToLower
 Case Is = "january"
 Return 1
 Case Is = "february"
 Return 2
 Case Is = "march"
 Return 3
 Case Is = "april"
 Return 4
 Case Is = "may"
 Return 5
 Case Is = "june"
 Return 6
 Case Is = "july"
 Return 7
 Case Is = "august"
 Return 8
 Case Is = "september"
 Return 9
 Case Is = "october"
 Return 10
 Case Is = "november"
 Return 11
 Case Is = "december"
 Return 12
 Case Else
 Return 0
 End Select
End Function
</code></pre>

caution code is in Beta version.

blocks|key|1700060|text|我将其翻译成西班牙语版本的C#代码，谨此致敬：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1700061|public+string+ObtenerNumeroMes(string+NombreMes){

+++++++string+NumeroMes;+++

+++++++switch(NombreMes)+{

++++++++case+("ENERO")+:
++++++++++++NumeroMes+=+"01";
++++++++++++return+NumeroMes;

++++++++case+("FEBRERO")+:
++++++++++++NumeroMes+=+"02";
++++++++++++return+NumeroMes;

++++++++case+("MARZO")+:
++++++++++++NumeroMes+=+"03";
++++++++++++return+NumeroMes;

++++++++case+("ABRIL")+:
++++++++++++NumeroMes+=+"04";
++++++++++++return+NumeroMes;

++++++++case+("MAYO")+:
++++++++++++NumeroMes+=+"05";
++++++++++++return+NumeroMes;

++++++++case+("JUNIO")+:
++++++++++++NumeroMes+=+"06";
++++++++++++return+NumeroMes;

++++++++case+("JULIO")+:
++++++++++++NumeroMes+=+"07";
++++++++++++return+NumeroMes;

++++++++case+("AGOSTO")+:
++++++++++++NumeroMes+=+"08";
++++++++++++return+NumeroMes;

++++++++case+("SEPTIEMBRE")+:
++++++++++++NumeroMes+=+"09";
++++++++++++return+NumeroMes;

++++++++case+("OCTUBRE")+:
++++++++++++NumeroMes+=+"10";
++++++++++++return+NumeroMes;

++++++++case+("NOVIEMBRE")+:
++++++++++++NumeroMes+=+"11";
++++++++++++return+NumeroMes;

++++++++case+("DICIEMBRE")+:
++++++++++++NumeroMes+=+"12";
++++++++++++return+NumeroMes;

++++++++++++default:
++++++++++++Console.WriteLine("Error");
++++++++++++return+"ERROR";

++++++++}

+++}|code-block|syntax|javascript|1700062|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I translate it into C# code in Spanish version, regards:

<pre><code>public string ObtenerNumeroMes(string NombreMes){

 string NumeroMes; 

 switch(NombreMes) {

 case ("ENERO") :
 NumeroMes = "01";
 return NumeroMes;

 case ("FEBRERO") :
 NumeroMes = "02";
 return NumeroMes;

 case ("MARZO") :
 NumeroMes = "03";
 return NumeroMes;

 case ("ABRIL") :
 NumeroMes = "04";
 return NumeroMes;

 case ("MAYO") :
 NumeroMes = "05";
 return NumeroMes;

 case ("JUNIO") :
 NumeroMes = "06";
 return NumeroMes;

 case ("JULIO") :
 NumeroMes = "07";
 return NumeroMes;

 case ("AGOSTO") :
 NumeroMes = "08";
 return NumeroMes;

 case ("SEPTIEMBRE") :
 NumeroMes = "09";
 return NumeroMes;

 case ("OCTUBRE") :
 NumeroMes = "10";
 return NumeroMes;

 case ("NOVIEMBRE") :
 NumeroMes = "11";
 return NumeroMes;

 case ("DICIEMBRE") :
 NumeroMes = "12";
 return NumeroMes;

 default:
 Console.WriteLine("Error");
 return "ERROR";

 }

 }
</code></pre>

blocks|key|1699940|text|我所做的是使用SimpleDateFormat创建格式字符串，并将文本解析为日期，然后从中检索月份。代码如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1699941|int+year+=+2012+\\or+any+other+year
String+monthName+=+"January"+\\or+any+other+month
SimpleDateFormat+format+=+new+SimpleDateFormat("dd-MMM-yyyy");
int+monthNumber+=+format.parse("01-"+%2B+monthName+%2B+"-"+%2B+year).getMonth();|code-block|syntax|javascript|1699942|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

What I did was to use SimpleDateFormat to create a format string, and parse the text to a date, and then retrieve the month from that. The code is below:

<pre><code>int year = 2012 \\or any other year
String monthName = "January" \\or any other month
SimpleDateFormat format = new SimpleDateFormat("dd-MMM-yyyy");
int monthNumber = format.parse("01-" + monthName + "-" + year).getMonth();
</code></pre>

blocks|key|1700259|text|此代码可帮助您...|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1700260|using+System.Globalization;

....

string+FullMonthName+=+CultureInfo.CurrentCulture.DateTimeFormat.GetMonthName(DateTime.UtcNow.Month);|code-block|syntax|javascript|1700261|GetMonthName方法-它返回字符串...|1700262|如果您想将月份作为一个整数，那么只需使用-|1700263|DateTime+dt=+DateTime.UtcNow;
int+month=+dt.Month;|1700264|我希望，这对你有帮助！|1700265|谢谢！|1700266|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

This code helps you...

<pre><code>using System.Globalization;

....

string FullMonthName = CultureInfo.CurrentCulture.DateTimeFormat.GetMonthName(DateTime.UtcNow.Month);
</code></pre>

GetMonthName Method - it returns string...

If you want to get a month as an integer, then simply use - 

<pre><code>DateTime dt= DateTime.UtcNow;
int month= dt.Month;
</code></pre>

I hope, it helps you!!!

Thanks!!!

blocks|key|1485165|text|int+selectedValue+=+0;
++++++++++++switch+(curentMonth)
++++++++++++{
++++++++++++++++case+"January":
++++++++++++++++++++selectedValue+=+1;
++++++++++++++++++++break;
++++++++++++++++case+"February":
++++++++++++++++++++selectedValue+=+2;
++++++++++++++++++++break;
++++++++++++}
++++++++++++if+(selectedValue+!=+0)
++++++++++++{
+++++++++++++++/*+var+list=+db.model_name.Where(x+=>+x.column==+selectedValue);
++++++++++++++++return+list;+*/
++++++++++++}
++++++++++++return+Ok(selectedValue);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1485166|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>int selectedValue = 0;
 switch (curentMonth)
 {
 case &quot;January&quot;:
 selectedValue = 1;
 break;
 case &quot;February&quot;:
 selectedValue = 2;
 break;
 }
 if (selectedValue != 0)
 {
 /* var list= db.model_name.Where(x =&gt; x.column== selectedValue);
 return list; */
 }
 return Ok(selectedValue);
</code></pre>

I need to be able to compare some month names I have in an array.

It would be nice if there were some direct way like:

<pre><code>Month.toInt("January") &gt; Month.toInt("May")
</code></pre>

My Google searching seems to suggest the only way is to write your own method, but this seems like a common enough problem that I would think it would have been already implemented in .Net, anyone done this before?

How to parse a month name (string) to an integer for comparison in C#?

单元测试

我需要能够比较数组中的一些月份名称。如果有一些直接的方法就好了，比如：Month.toInt("January") > Month.toInt("May")我的谷歌搜索似乎表明唯一的方法是编写你自己的方法，但这似乎是一个足够常见的问题，我认为它已经在.Net中实现了，以前有人这样做过吗？

问如何在C#中将月份名称(字符串)解析为整数进行比较？
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问如何在C#中将月份名称(字符串)解析为整数进行比较？
EN