blocks|key|230258|text|您需要使用regular+expressions来识别不需要的字符。对于最易读的代码，您需要来自stringr包的str_replace_all，尽管来自基R的gsub也同样有效。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|230259|确切的正则表达式取决于您尝试执行的操作。您可以只删除问题中给出的那些特定字符，但删除所有标点符号要容易得多。|230260|x+<-+"a1~!@#$%25%5E&*(){}_%2B:\"<>?,./;'[]-="+#or+whatever
str_replace_all(x,+"[[:punct:]]",+"+")|code-block|syntax|javascript|230261|(基本的R等效项是gsub("[[:punct:]]",+"+",+x)。)|230262|另一种方法是换出所有非字母数字字符。|230263|str_replace_all(x,+"[%5E[:alnum:]]",+"+")|230264|请注意，字母、数字或标点符号的定义因您的语言环境而略有不同，因此您可能需要尝试一下才能准确地获得您想要的内容。|230265|entityMap|0|LINK|mutability|MUTABLE|url|http://www.regular-expressions.info/quickstart.html|1|https://cran.r-project.org/web/packages/stringr/index.html|2|https://www.rdocumentation.org/packages/stringr/topics/str_replace_all|3|https://www.rdocumentation.org/packages/base/topics/grep^0|1C|7|1L|F|28|4|5|J|0|1C|7|1|1L|F|2|28|4|3|0|0|0|9|R|0|0|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]]|D|@$9|1F|A|1G|1|1H]|$9|1I|A|1J|1|1K]|$9|1L|A|1M|1|1N]|$9|1O|A|1P|1|1Q]]|E|$]]|$1|F|3|G|5|6|7|1R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1S|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1T|8|@$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|1W|8|@]|D|@]|E|$]]|$1|Q|3|R|5|J|7|1X|8|@]|D|@]|E|$K|L]]|$1|S|3|T|5|6|7|1Y|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|1Z|8|@]|D|@]|E|$]]]|V|$W|$5|X|Y|Z|E|$10|11]]|12|$5|X|Y|Z|E|$10|13]]|14|$5|X|Y|Z|E|$10|15]]|16|$5|X|Y|Z|E|$10|17]]]]

You need to use <a href="http://www.regular-expressions.info/quickstart.html">regular expressions</a> to identify the unwanted characters. For the most easily readable code, you want the <a href="https://www.rdocumentation.org/packages/stringr/topics/str_replace_all"><code>str_replace_all</code></a> from the <a href="https://cran.r-project.org/web/packages/stringr/index.html"><code>stringr</code></a> package, though <a href="https://www.rdocumentation.org/packages/base/topics/grep"><code>gsub</code></a> from base R works just as well.

The exact regular expression depends upon what you are trying to do. You could just remove those specific characters that you gave in the question, but it's much easier to remove all punctuation characters.

<pre><code>x &lt;- "a1~!@#$%^&amp;*(){}_+:\"&lt;&gt;?,./;'[]-=" #or whatever
str_replace_all(x, "[[:punct:]]", " ")
</code></pre>

(The base R equivalent is <code>gsub("[[:punct:]]", " ", x)</code>.)

An alternative is to swap out all non-alphanumeric characters.

<pre><code>str_replace_all(x, "[^[:alnum:]]", " ")
</code></pre>

Note that the definition of what constitutes a letter or a number or a punctuatution mark varies slightly depending upon your locale, so you may need to experiment a little to get exactly what you want.

blocks|key|231219|text|不使用正则表达式来删除这些“疯狂”的字符，只需将它们转换为ASCII，这将删除重音，但将保留字母。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|231220|astr+<-+"Ábcdêãçoàúü"
iconv(astr,+from+=+'UTF-8',+to+=+'ASCII//TRANSLIT')|code-block|syntax|javascript|231221|这导致了|231222|[1]+"Abcdeacoauu"|231223|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Instead of using regex to remove those "crazy" characters, just convert them to ASCII, which will remove accents, but will keep the letters.

<pre><code>astr &lt;- "Ábcdêãçoàúü"
iconv(astr, from = 'UTF-8', to = 'ASCII//TRANSLIT')
</code></pre>

which results in 

<pre><code>[1] "Abcdeacoauu"
</code></pre>

blocks|key|2888542|text|将特殊字符转换为撇号，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2888543|Data++<-+gsub("[%5E0-9A-Za-z///'+]","'"+,+Data+,ignore.case+=+TRUE)|code-block|syntax|javascript|2888544|下面对其进行编码以删除多余的‘撇号|2888545|Data+<-+gsub("''",""+,+Data+,ignore.case+=+TRUE)|2888546|使用gsub(..)函数将特殊字符替换为撇号|offset|length|style|CODE|2888547|entityMap^0|0|0|0|0|2|8|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Convert the Special characters to apostrophe,

<pre><code>Data &lt;- gsub("[^0-9A-Za-z///' ]","'" , Data ,ignore.case = TRUE)
</code></pre>

Below code it to remove extra ''' apostrophe

<pre><code>Data &lt;- gsub("''","" , Data ,ignore.case = TRUE)
</code></pre>

Use <code>gsub(..)</code> function for replacing the special character with apostrophe

How to remove all special characters from string in R and replace them with spaces ?
Some special characters to remove are : <code>~!@#$%^&amp;*(){}_+:&quot;&lt;&gt;?,./;'[]-=</code>
I've tried <code>regex</code> with <code>[:punct:]</code> pattern but it removes only punctuation marks.
Question 2 : And how to remove characters from foreign languages like : <code>â í ü Â á ą ę ś ć</code> ?
Answer : Use <code>[^[:alnum:]]</code> to remove<code>~!@#$%^&amp;*(){}_+:&quot;&lt;&gt;?,./;'[]-=</code> and use <code>[^a-zA-Z0-9]</code> to remove also <code>â í ü Â á ą ę ś ć</code> in <code>regex</code> or <code>regexpr</code> functions.
Solution in base R :
<pre><code>x &lt;- &quot;a1~!@#$%^&amp;*(){}_+:\&quot;&lt;&gt;?,./;'[]-=&quot; 
gsub(&quot;[[:punct:]]&quot;, &quot;&quot;, x) # no libraries needed
</code></pre>

Remove all special characters from a string in R?

如何删除R中字符串中的所有特殊字符并将其替换为空格？要删除的一些特殊字符是：~!@#$%^&*(){}_+:"<>?,./;'[]-=我尝试过带有[:punct:]模式的regex，但它只删除标点符号。问题2:如何从外语中删除字符，如：â í ü Â á ą ę ś ć？答:使用[^[:alnum:]]删除~!@#$%...

问是否删除R中字符串中的所有特殊字符？
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问是否删除R中字符串中的所有特殊字符？
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