blocks|key|2751934|text|&a提供a的地址-+&p提供p的地址。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2751935|int+*+*+p_to_p+=+&p;|code-block|syntax|javascript|2751936|entityMap^0|0|2|4|1|A|2|E|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|L|$]]

<code>&amp;a</code> gives address of <code>a</code> - <code>&amp;p</code> gives address of <code>p</code>.

<pre><code>int * * p_to_p = &amp;p;
</code></pre>

blocks|key|161426|text|要获取p的地址，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|161427|int+**pp+=+&p;|code-block|syntax|javascript|161428|你还可以继续：|161429|int+***ppp+=+&pp;
int+****pppp+=+&ppp;
...|161430|或者，仅在C%2B%2B11中，您可以执行以下操作：|161431|auto+pp+=+std::addressof(p);|161432|要打印C语言的地址，大多数编译器都支持%25p，因此您可以简单地执行以下操作：|offset|length|style|CODE|161433|printf("addr:+%25p",+pp);|161434|否则，您需要强制转换它(假设是32位平台)|161435|printf("addr:+0x%25u",+(unsigned)pp);|161436|在C%2B%2B中，您可以执行以下操作：|161437|cout+<<+"addr:+"+<<+pp;|161438|entityMap^0|0|0|0|0|0|0|J|2|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|18|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1A|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1C|8|@$Q|1D|R|1E|S|T]]|9|@]|A|$]]|$1|U|3|V|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|D|7|1H|8|@]|9|@]|A|$E|F]]|$1|10|3|11|5|6|7|1I|8|@]|9|@]|A|$]]|$1|12|3|13|5|D|7|1J|8|@]|9|@]|A|$E|F]]|$1|14|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|15|$]]

To get the address of p do:

<pre><code>int **pp = &amp;p;
</code></pre>

and you can go on:

<pre><code>int ***ppp = &amp;pp;
int ****pppp = &amp;ppp;
...
</code></pre>

or, only in C++11, you can do:

<pre><code>auto pp = std::addressof(p);
</code></pre>

To print the address in C, most compilers support <code>%p</code>, so you can simply do:

<pre><code>printf("addr: %p", pp);
</code></pre>

otherwise you need to cast it (assuming a 32 bit platform)

<pre><code>printf("addr: 0x%u", (unsigned)pp);
</code></pre>

In C++ you can do:

<pre><code>cout &lt;&lt; "addr: " &lt;&lt; pp;
</code></pre>

blocks|key|159036|text|int+a+=+10;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|159037|要获得a的地址，您需要这样做：&a+(a的地址)，它返回一个int*+(指向int的指针)|unstyled|offset|length|style|CODE|159038|int+*p+=+&a;|159039|然后将a的地址存储在int*类型的p中。|159040|最后，如果你做&p，你会得到p的地址，它的类型是int**，也就是指向&p的指针：|159041|int**+p_ptr+=+&p;|159042|刚刚看到你的编辑：|159043|要打印出指针的地址，您需要将其转换为：|159044|printf("address+of+pointer+is:+0x%250X\n",+(unsigned)&p);
printf("address+of+pointer+to+pointer+is:+0x%250X\n",+(unsigned)&p_ptr);|159045|或者，如果您的printf支持它，请使用%25p|159046|printf("address+of+pointer+is:+%25p\n",+p);
printf("address+of+pointer+to+pointer+is:+%25p\n",+p_ptr);|159047|entityMap^0|0|F|2|J|1|U|4|0|0|A|4|H|1|0|7|2|E|1|O|5|Z|2|0|0|0|0|0|K|2|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|15|8|@$G|16|H|17|I|J]|$G|18|H|19|I|J]|$G|1A|H|1B|I|J]]|9|@]|A|$]]|$1|K|3|L|5|6|7|1C|8|@]|9|@]|A|$B|C]]|$1|M|3|N|5|F|7|1D|8|@$G|1E|H|1F|I|J]|$G|1G|H|1H|I|J]]|9|@]|A|$]]|$1|O|3|P|5|F|7|1I|8|@$G|1J|H|1K|I|J]|$G|1L|H|1M|I|J]|$G|1N|H|1O|I|J]|$G|1P|H|1Q|I|J]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1R|8|@]|9|@]|A|$B|C]]|$1|S|3|T|5|F|7|1S|8|@]|9|@]|A|$]]|$1|U|3|V|5|F|7|1T|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1U|8|@]|9|@]|A|$B|C]]|$1|Y|3|Z|5|F|7|1V|8|@$G|1W|H|1X|I|J]]|9|@]|A|$]]|$1|10|3|11|5|6|7|1Y|8|@]|9|@]|A|$B|C]]|$1|12|3|-4|5|F|7|1Z|8|@]|9|@]|A|$]]]|13|$]]

<pre><code>int a = 10;
</code></pre>

To get the address of a, you do: <code>&amp;a</code> (address of <code>a</code>) which returns an <code>int*</code> (pointer to int)

<pre><code>int *p = &amp;a;
</code></pre>

Then you store the address of a in <code>p</code> which is of type <code>int*</code>.

Finally, if you do <code>&amp;p</code> you get the address of <code>p</code> which is of type <code>int**</code>, i.e. pointer to pointer to int:

<pre><code>int** p_ptr = &amp;p;
</code></pre>

just seen your edit:

to print out the pointer's address, you either need to convert it:

<pre><code>printf("address of pointer is: 0x%0X\n", (unsigned)&amp;p);
printf("address of pointer to pointer is: 0x%0X\n", (unsigned)&amp;p_ptr);
</code></pre>

or if your printf supports it, use the <code>%p</code>:

<pre><code>printf("address of pointer is: %p\n", p);
printf("address of pointer to pointer is: %p\n", p_ptr);
</code></pre>

blocks|key|159053|text|您可以在C中使用%25p|type|unstyled|depth|inlineStyleRanges|entityRanges|data|159054|在C中：|159055|printf("%25p",p)|code-block|syntax|javascript|159056|在C%2B%2B中：|159057|cout<<"Address+of+pointer+p+is:+"<<p|159058|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can use %p in C

In C:

<pre><code>printf("%p",p)
</code></pre>

In C++:

<pre><code>cout&lt;&lt;"Address of pointer p is: "&lt;&lt;p
</code></pre>

blocks|key|2964708|text|你可以使用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2964709|在C中|2964710|int+a+=10;
int+*p+=+&a;+++++
int+**pp+=+&p;
printf("%25u",&p);|code-block|syntax|javascript|2964711|在C%2B%2B中|2964712|cout<<p;|2964713|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

you can use this

in C

<pre><code>int a =10;
int *p = &amp;a; 
int **pp = &amp;p;
printf("%u",&amp;p);
</code></pre>

in C++

<pre><code>cout&lt;&lt;p;
</code></pre>

blocks|key|2964731|text|拥有这个C源代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2964732|int+a+=+10;
int+*+ptr+=+&a;|code-block|syntax|javascript|2964733|使用这个|2964734|printf("The+address+of+ptr+is+%25p\n",+(void+*)+&ptr);|2964735|打印ptr的地址。|offset|length|style|CODE|2964736|请注意，转换说明符p是唯一打印指针的值和的转换说明符，它被定义为仅用于void*类型的指针。|BOLD|2964737|来自man+printf:|2964738|2964739|+p|blockquote|2964740|2964741|空*+pointer参数以十六进制打印(就像%25#x或%25#lx).一样|2964742|entityMap|0|LINK|mutability|MUTABLE|url|http://man7.org/linux/man-pages/man3/printf.3.html^0|0|0|0|0|2|3|0|9|1|Z|5|J|1|0|2|A|2|B|0|0|0|1|1|0|0|N|2|R|3|0^^$0|@$1|2|3|4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1C|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1E|8|@$M|1F|N|1G|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1H|8|@$M|1I|N|1J|O|P]|$M|1K|N|1L|O|P]|$M|1M|N|1N|O|S]]|9|@]|A|$]]|$1|T|3|U|5|6|7|1O|8|@$M|1P|N|1Q|O|P]]|9|@$M|1R|N|1S|1|1T]]|A|$]]|$1|V|3|-4|5|6|7|1U|8|@]|9|@]|A|$]]|$1|W|3|X|5|Y|7|1V|8|@$M|1W|N|1X|O|S]]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|10|3|11|5|6|7|1Z|8|@$M|20|N|21|O|S]|$M|22|N|23|O|S]]|9|@]|A|$]]|$1|12|3|-4|5|6|7|24|8|@]|9|@]|A|$]]]|13|$14|$5|15|16|17|A|$18|19]]]]

Having this C source:

<pre><code>int a = 10;
int * ptr = &amp;a;
</code></pre>

Use this

<pre><code>printf("The address of ptr is %p\n", (void *) &amp;ptr);
</code></pre>

to print the address of <code>ptr</code>.

Please note that the conversion specifier <code>p</code> is the only conversion specifier to print a pointer's value and it is defined to be used with <code>void*</code> typed pointers only.

From <a href="http://man7.org/linux/man-pages/man3/printf.3.html" rel="nofollow"><code>man printf</code>:</a>

<blockquote>
 p 
 
 The void * pointer argument is printed in hexadecimal (as if
 by %#x or %#lx).
</blockquote>

blocks|key|161481|text|您可以使用%25p格式化程序。在打印之前将指针转换为void*总是最好的做法。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|161482|C标准说：|161483|161484|参数应该是指向空的指针。指针的值以实现定义的方式转换为打印字符序列。|blockquote|161485|161486|161487|下面是你如何做到这一点：|161488|printf("%25p",+(void*)p);|code-block|syntax|javascript|161489|entityMap^0|5|2|O|5|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|12|8|@]|D|@]|E|$]]|$1|I|3|J|5|K|7|13|8|@]|D|@]|E|$]]|$1|L|3|-4|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|15|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|16|8|@]|D|@]|E|$]]|$1|P|3|Q|5|R|7|17|8|@]|D|@]|E|$S|T]]|$1|U|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|V|$]]

You can use the <code>%p</code> formatter. It's always best practice cast your pointer <code>void*</code> before printing. 

The C standard says:

<blockquote>
 The argument shall be a pointer to void. The value of the pointer is converted to a sequence of printing characters, in an implementation-defined manner.
</blockquote>

Here's how you do it:

<pre><code>printf("%p", (void*)p);
</code></pre>

blocks|key|2964768|text|在C%2B%2B中，您可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2964769|//+Declaration+and+assign+variable+a
int+a+=+7;
//+Declaration+pointer+b
int*+b;
//+Assign+address+of+variable+a+to+pointer+b
b+=+&a;

//+Declaration+pointer+c
int**+c;
//+Assign+address+of+pointer+b+to+pointer+c
c+=+&b;

std::cout+<<+"a:+"+<<+a+<<+"\n";+++++++//+Print+value+of+variable+a
std::cout+<<+"&a:+"+<<+&a+<<+"\n";+++++//+Print+address+of+variable+a

std::cout+<<+""+<<+""+<<+"\n";

std::cout+<<+"b:+"+<<+b+<<+"\n";+++++++//+Print+address+of+variable+a
std::cout+<<+"*b:+"+<<+*b+<<+"\n";+++++//+Print+value+of+variable+a
std::cout+<<+"&b:+"+<<+&b+<<+"\n";+++++//+Print+address+of+pointer+b

std::cout+<<+""+<<+""+<<+"\n";

std::cout+<<+"c:+"+<<+c+<<+"\n";+++++++//+Print+address+of+pointer+b
std::cout+<<+"**c:+"+<<+**c+<<+"\n";+++//+Print+value+of+variable+a
std::cout+<<+"*c:+"+<<+*c+<<+"\n";+++++//+Print+address+of+variable+a
std::cout+<<+"&c:+"+<<+&c+<<+"\n";+++++//+Print+address+of+pointer+c|code-block|syntax|javascript|2964770|entityMap^0|1|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

In C++ you can do:

<pre><code>// Declaration and assign variable a
int a = 7;
// Declaration pointer b
int* b;
// Assign address of variable a to pointer b
b = &amp;a;

// Declaration pointer c
int** c;
// Assign address of pointer b to pointer c
c = &amp;b;

std::cout &lt;&lt; "a: " &lt;&lt; a &lt;&lt; "\n"; // Print value of variable a
std::cout &lt;&lt; "&amp;a: " &lt;&lt; &amp;a &lt;&lt; "\n"; // Print address of variable a

std::cout &lt;&lt; "" &lt;&lt; "" &lt;&lt; "\n";

std::cout &lt;&lt; "b: " &lt;&lt; b &lt;&lt; "\n"; // Print address of variable a
std::cout &lt;&lt; "*b: " &lt;&lt; *b &lt;&lt; "\n"; // Print value of variable a
std::cout &lt;&lt; "&amp;b: " &lt;&lt; &amp;b &lt;&lt; "\n"; // Print address of pointer b

std::cout &lt;&lt; "" &lt;&lt; "" &lt;&lt; "\n";

std::cout &lt;&lt; "c: " &lt;&lt; c &lt;&lt; "\n"; // Print address of pointer b
std::cout &lt;&lt; "**c: " &lt;&lt; **c &lt;&lt; "\n"; // Print value of variable a
std::cout &lt;&lt; "*c: " &lt;&lt; *c &lt;&lt; "\n"; // Print address of variable a
std::cout &lt;&lt; "&amp;c: " &lt;&lt; &amp;c &lt;&lt; "\n"; // Print address of pointer c
</code></pre>

blocks|key|2752279|text|首先，你应该明白指针并不复杂。指针显示变量的地址。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2752280|示例：|2752281|int+a+=+10;
int+*p+=+&a;++//+This+means+giving+a+pointer+of+variable+"a"+to+int+pointer+variable+"p"|code-block|syntax|javascript|2752282|而且，你应该理解“指针是一个地址”和“地址是数值”。所以，你可以得到变量的地址为Integer。|2752283|int+a+=+10;
unsigned+long+address+=+(unsigned+long)&a;

//+comparison
printf("%25p\n",+&a);
printf("%25ld\n",+address);|2752284|输出如下|2752285|0x7fff1216619c
7fff1216619c|2752286|注意：|2752287|如果你使用64位计算机，你不能通过下面的方式获取指针。|2752288|int+a+=+10;
unsigned+int+address+=+(unsigned+int)&a;|2752289|因为在64位机器上，指针是8字节(64位)，而int是4字节。所以，你不能给4字节的变量分配一个8字节的内存地址。|2752290|您必须使用long+long或long来获取变量的地址。|offset|length|style|CODE|2752291|当为32位计算机编译代码时，|2752292|long+long始终为8+bytes.|unordered-list-item|2752293|long为4字节当为64位计算机编译代码时，machine.|2752294|long为8字节。|2752295|2752296|因此，您应该使用long来接收指针。|2752297|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|5|9|F|4|0|0|0|9|0|0|4|0|0|4|0|0|8|4|0^^$0|@$1|2|3|4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1J|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|1K|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|1L|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|1M|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|1N|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|1O|8|@]|9|@]|A|$G|H]]|$1|Q|3|R|5|6|7|1P|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|U|3|V|5|F|7|1R|8|@]|9|@]|A|$G|H]]|$1|W|3|X|5|6|7|1S|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1T|8|@$10|1U|11|1V|12|13]|$10|1W|11|1X|12|13]]|9|@]|A|$]]|$1|14|3|15|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|16|3|17|5|18|7|1Z|8|@$10|20|11|21|12|13]]|9|@]|A|$]]|$1|19|3|1A|5|18|7|22|8|@$10|23|11|24|12|13]]|9|@]|A|$]]|$1|1B|3|1C|5|18|7|25|8|@$10|26|11|27|12|13]]|9|@]|A|$]]|$1|1D|3|-4|5|6|7|28|8|@]|9|@]|A|$]]|$1|1E|3|1F|5|6|7|29|8|@$10|2A|11|2B|12|13]]|9|@]|A|$]]|$1|1G|3|-4|5|6|7|2C|8|@]|9|@]|A|$]]]|1H|$]]

First, you should understand the pointer is not complex. A pointer is showing the address of the variable.
Example:
<pre class="lang-c prettyprint-override"><code>int a = 10;
int *p = &amp;a; // This means giving a pointer of variable &quot;a&quot; to int pointer variable &quot;p&quot;
</code></pre>
And, you should understand &quot;Pointer is an address&quot; and &quot;address is numerical value&quot;. So, you can get the address of variable as Integer.
<pre class="lang-c prettyprint-override"><code>int a = 10;
unsigned long address = (unsigned long)&amp;a;

// comparison
printf(&quot;%p\n&quot;, &amp;a);
printf(&quot;%ld\n&quot;, address);
</code></pre>
output is below
<pre><code>0x7fff1216619c
7fff1216619c
</code></pre>
Note:
If you use a 64-bit computer, you can't get pointer by the way below.
<pre class="lang-c prettyprint-override"><code>int a = 10;
unsigned int address = (unsigned int)&amp;a;
</code></pre>
Because pointer is 8 bytes (64 bit) on a 64-bit machine, but int is 4 bytes. So, you can't give an 8-byte memory address to 4 bytes variable.
You have to use <code>long long</code> or <code>long</code> to get an address of the variable.
<ul>
<li><code>long long</code> is always 8 bytes.</li>
<li><code>long</code> is 4 bytes when code was compiled for a 32-bit machine.</li>
<li><code>long</code> is 8 bytes when code was compiled for a 64-bit machine.</li>
</ul>
Therefore, you should use <code>long</code> to receive a pointer.

blocks|key|160178|text|如果您试图从Linux终端编译这些代码，您可能会收到以下错误消息|type|unstyled|depth|inlineStyleRanges|entityRanges|data|160179|160180|要求参数类型为整型|blockquote|160181|160182|160183|这是因为，当您尝试通过printf获取内存地址时，您不能将其指定为视频中所示的%25d。而不是试着把%25p。|offset|length|style|CODE|160184|示例：|160185|//+this+might+works+fine+since+the+out+put+is+an+integer+as+its+expected.
printf("%25d\n",+*p);+

//+but+to+get+the+address:
printf("%25p\n",+p);+|code-block|syntax|javascript|160186|entityMap^0|0|0|0|0|0|B|6|13|2|1C|2|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|X|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|Y|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|10|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|11|8|@$J|12|K|13|L|M]|$J|14|K|15|L|M]|$J|16|K|17|L|M]]|9|@]|A|$]]|$1|N|3|O|5|6|7|18|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|19|8|@]|9|@]|A|$S|T]]|$1|U|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|V|$]]

If you are trying to compile these codes from a Linux terminal, you might get an error saying
<blockquote>
expects argument type int
</blockquote>
Its because, when you try to get the memory address by <code>printf</code>, you cannot specify it as <code>%d</code> as its shown in the video.
Instead of that try to put <code>%p</code>.
Example:
<pre><code>// this might works fine since the out put is an integer as its expected.
printf(&quot;%d\n&quot;, *p); 

// but to get the address:
printf(&quot;%p\n&quot;, p); 
</code></pre>

blocks|key|161512|text|根据上面的答案构建getter，如果您将指针作为私有变量，则可以创建一个函数，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|161513|private+int*+p;

public+int**+GetP()+{+return+&p;+}|code-block|syntax|javascript|161514|然后，当您使用它时，需要创建一个指向包含它的类的指针：|161515|DummyClass*+p_dummyClass+=+new+DummyClass;|161516|，然后在您的用例场景中：|161517|p_dummyClass+->+GetP();|161518|(别忘了解除分配)|161519|entityMap^0|10|8|0|0|0|0|0|C|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|16|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|V|$]]

Building off the above answers, if you had the pointer as a private variable, then you can make a getter function like so:
<pre><code>private int* p;

public int** GetP() { return &amp;p; }
</code></pre>
Then when you use it you create a pointer to your class that contains it:
<pre><code>DummyClass* p_dummyClass = new DummyClass;
</code></pre>
And then in your use case scenario:
<pre><code>p_dummyClass -&gt; GetP();
</code></pre>
(don't forget to deallocate)

How to get address of a pointer in c/c++?

Eg: I have below code.

<pre><code>int a =10;
int *p = &amp;a;
</code></pre>

So how do I get address of pointer <code>p</code>?
Now I want to print address of p, what should I do?

print("%s",???) what I pass to ???.

How to get address of a pointer in c/c++?

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如何在c/c++中获取指针地址我有下面的代码。int a =10;int *p = &a;那么如何获取指针p的地址呢？现在我想打印p的地址，我该怎么做？打印(“%s”，？)我传递给什么？

问如何在c/c++中获取指针的地址？
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