blocks|key|1499243|text|看起来ToString和reparse方法是最好的方法。代码如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1499244|XElement+copy+=+XElement.Parse(original.ToString());|code-block|syntax|javascript|1499245|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

It looks like the ToString and reparse method is the best way. Here is the code:

<pre><code>XElement copy = XElement.Parse(original.ToString());
</code></pre>

blocks|key|1499294|text|直接从C#+3.0+in+a+Nutshell升级|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1499295|当节点或属性被添加到元素中时(无论是通过函数构造还是Add方法)，节点或属性的Parent属性都被设置为该元素。一个节点只能有一个父元素:如果您将一个已成为父元素的节点添加到第二个父元素中，则该节点将自动被深度克隆。在以下示例中，每个客户都有一个单独的地址副本：|1499296|var+address+=+new+XElement+("address",
++++++++++++++++++new+XElement+("street",+"Lawley+St"),
++++++++++++++++++new+XElement+("town",+"North+Beach")
++++++++++++++);
var+customer1+=+new+XElement+("customer1",+address);
var+customer2+=+new+XElement+("customer2",+address);

customer1.Element+("address").Element+("street").Value+=+"Another+St";
Console.WriteLine+(
++customer2.Element+("address").Element+("street").Value);+++//+Lawley+St|code-block|syntax|javascript|1499297|这种自动复制使X-DOM对象实例化没有副作用--这是函数式编程的另一个特点。|1499298|entityMap|0|LINK|mutability|MUTABLE|url|https://rads.stackoverflow.com/amzn/click/com/0596527578^0|3|K|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|6|7|Y|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|Z|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|C|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

Lifted directly from <a href="https://rads.stackoverflow.com/amzn/click/com/0596527578" rel="nofollow noreferrer" rel="nofollow noreferrer">C# 3.0 in a Nutshell</a>:

When a node or attribute is added to an element (whether via functional construction or an Add method) the node or attribute's Parent property is set to that element. A node can have only one parent element: if you add an already parented node to a second parent, the node is automatically deep-cloned. In the following example, each customer has a separate copy of address:

<pre><code>var address = new XElement ("address",
 new XElement ("street", "Lawley St"),
 new XElement ("town", "North Beach")
 );
var customer1 = new XElement ("customer1", address);
var customer2 = new XElement ("customer2", address);

customer1.Element ("address").Element ("street").Value = "Another St";
Console.WriteLine (
 customer2.Element ("address").Element ("street").Value); // Lawley St
</code></pre>

This automatic duplication keeps X-DOM object instantiation free of side effects—another hallmark of functional programming.

blocks|key|1714370|text|不需要重新解析。XElement的一个构造器获取另一个XElement并对其进行深度复制：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1714371|XElement+original+=+new+XElement("original");
XElement+deepCopy+=+new+XElement(original);|code-block|syntax|javascript|1714372|这里有几个单元测试来演示：|1714373|[TestMethod]
public+void+XElementShallowCopyShouldOnlyCopyReference()
{
++++XElement+original+=+new+XElement("original");
++++XElement+shallowCopy+=+original;
++++shallowCopy.Name+=+"copy";
++++Assert.AreEqual("copy",+original.Name);
}

[TestMethod]
public+void+ShouldGetXElementDeepCopyUsingConstructorArgument()
{
++++XElement+original+=+new+XElement("original");
++++XElement+deepCopy+=+new+XElement(original);
++++deepCopy.Name+=+"copy";
++++Assert.AreEqual("original",+original.Name);
++++Assert.AreEqual("copy",+deepCopy.Name);
}|1714374|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

There is no need to reparse. One of the constructors of XElement takes another XElement and makes a deep copy of it:

<pre><code>XElement original = new XElement("original");
XElement deepCopy = new XElement(original);
</code></pre>

Here are a couple of unit tests to demonstrate:

<pre><code>[TestMethod]
public void XElementShallowCopyShouldOnlyCopyReference()
{
 XElement original = new XElement("original");
 XElement shallowCopy = original;
 shallowCopy.Name = "copy";
 Assert.AreEqual("copy", original.Name);
}

[TestMethod]
public void ShouldGetXElementDeepCopyUsingConstructorArgument()
{
 XElement original = new XElement("original");
 XElement deepCopy = new XElement(original);
 deepCopy.Name = "copy";
 Assert.AreEqual("original", original.Name);
 Assert.AreEqual("copy", deepCopy.Name);
}
</code></pre>

blocks|key|1499348|text|这应该是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1499349|var+copy+=+new+XElement(original.Name,+original.Attributes(),
++++++++++++++++++++++++original.Elements()+);|code-block|syntax|javascript|1499350|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This should work:

<pre><code>var copy = new XElement(original.Name, original.Attributes(),
 original.Elements() );
</code></pre>

I want to make a deep copy of a LINQ to XML XElement. The reason I want to do this is there are some nodes in the document that I want to create modified copies of (in the same document). I don't see a method to do this.

I could convert the element to an XML string and then reparse it, but I'm wondering if there's a better way.

How do I do a deep copy of an element in LINQ to XML?

单元测试

我想做一个LINQ to XML XElement的深度副本。我之所以要这样做，是因为我想(在同一文档中)创建文档中某些节点的修改副本。我看不出有什么方法可以做到这一点。我可以将元素转换为XML字符串，然后重新解析它，但我想知道是否有更好的方法。

问如何对LINQ to XML中的元素进行深度复制？
EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何对LINQ to XML中的元素进行深度复制？EN

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何对LINQ to XML中的元素进行深度复制？
EN